Problem 16
Question
For the following exercises, state the domain, vertical asymptote, and end behavior of the function. \(f(x)=\ln (2-x)\)
Step-by-Step Solution
Verified Answer
Domain: \((-\infty, 2)\); Vertical asymptote: \(x = 2\); End behavior: \(f(x) \to \infty\) as \(x \to -\infty\), \(f(x) \to -\infty\) as \(x \to 2^-\).
1Step 1: Determine the Domain
The domain of the function is the set of all values of \(x\) for which the function is defined. The logarithm \(\ln(y)\) is defined for \(y > 0\). Here, \(y = (2 - x)\), thus we have \(2 - x > 0\). By solving this inequality, we get \(x < 2\). So the domain of the function is \((-\infty, 2)\).
2Step 2: Identify the Vertical Asymptote
Vertical asymptotes occur at values of \(x\) that make the inside of the logarithm zero because the logarithm becomes undefined. Set \(2-x = 0\) to find the x-value. Solving \(x = 2\) gives the vertical asymptote at \(x = 2\).
3Step 3: Analyze the End Behavior
End behavior refers to the behavior of \(f(x)\) as \(x\) approaches the endpoints of its domain. As \(x \to -\infty\), \(f(x) = \ln(2-x)\to \ln(\infty) = \infty\), meaning \(f(x)\) increases without bound. As \(x\) approaches 2 from the left (\(x \to 2^-\)), \(f(x) = \ln(2-x)\) approaches \(\ln(0) = -\infty\), meaning \(f(x)\) decreases without bound.
Key Concepts
Vertical AsymptotesEnd Behavior of FunctionsLogarithmic Inequalities
Vertical Asymptotes
Logarithmic functions like \(f(x) = \ln(2-x)\) have interesting features that many students find challenging to understand. One such feature is the vertical asymptote. A vertical asymptote is a vertical line, \(x = a\), where a function's value grows very large or very small as it approaches \(a\). This is because at the vertical asymptote, the expression inside the logarithm becomes zero or negative, which is undefined in logarithms.
\[ \text{For } f(x) = \ln(2-x), \text{ you set the inside } (2-x) = 0.\]
Solving this gives \(x = 2\), the location of our vertical asymptote.
\[ \text{For } f(x) = \ln(2-x), \text{ you set the inside } (2-x) = 0.\]
Solving this gives \(x = 2\), the location of our vertical asymptote.
- At \(x = 2\): The graphical representation shows that the function approaches negative infinity, meaning the graph gets closer to the line \(x = 2\) without touching it.
- Understanding vertical asymptotes helps you predict drastic changes in function values as you near specific x-values.
End Behavior of Functions
The end behavior of a function helps you understand how the function behaves as the input values head towards the extreme, either towards positive or negative infinity. In the logarithmic function \(f(x) = \ln(2-x)\), the end behavior is apparent as \(x\) approaches the endpoints of its domain, \((-\infty, 2)\).
As \(x\) approaches negative infinity:
As \(x\) approaches negative infinity:
- Substitute very small values into \(2-x\) and note that the function approaches \(\ln(\infty) = \infty\).
- This suggests that \(f(x)\) increases without bound as \(x\) decreases.
- The expression \(2-x\) turns into a small positive number, causing \(\ln(2-x)\) to decrease rapidly.
- This is why \(f(x)\) dashes towards \(-\infty\), indicating a steep descent on the graph.
Logarithmic Inequalities
Logarithmic inequalities play an essential role in determining the domain of logarithmic functions and understanding features like vertical asymptotes. When we encounter \(f(x) = \ln(2-x)\), we're tasked with ensuring that the argument \((2-x)\) inside the logarithm always stays positive since \(\ln(y)\) is defined only if \(y > 0\).
To find the domain:
To find the domain:
- Set \(2-x > 0\).
- Solve the inequality to obtain \(x < 2\), meaning the domain is \((-\infty, 2)\).
- Acquire the skill to solve inequalities systematically to determine valid input values that keep the function defined.
- Prevent common mistakes involving assumptions that logarithms can take negative values.
- Improve your overall understanding of both basic and complex logarithmic functions.
Other exercises in this chapter
Problem 16
For the following exercises, use logarithms to solve. \(7 e^{3 n-5}+5=-89\)
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For the following exercises, use the properties of logarithms to expand each logarithm as much as possible. Rewrite each expression as a sum, difference, or pro
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For the following exercises, rewrite each equation in logarithmic form. \(4^{x}=y\)
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For the following exercises, determine whether the equation represents exponential growth, exponential decay, or neither. Explain. \(y=16.5(1.025)^{\frac{1}{x}}
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