Problem 16
Question
For the following exercises, find the specified term for the arithmetic sequence given the first term and common difference. First term is \(5,\) common difference is \(6,\) fi \(d\) the \(8^{\text {th }}\) term.
Step-by-Step Solution
Verified Answer
The 8th term of the sequence is 47.
1Step 1: Understand the problem
We are given the first term of an arithmetic sequence, denoted as \(a_1 = 5\), and the common difference \(d = 6\). We are asked to find the 8th term of this sequence.
2Step 2: Recall the formula for the nth term of an arithmetic sequence
The formula to find the \(n^{th}\) term of an arithmetic sequence is given by: \(a_n = a_1 + (n-1) \times d\). We will use this formula to find the 8th term.
3Step 3: Substitute the known values into the formula
Substitute \(a_1 = 5\), \(d = 6\), and \(n = 8\) into the formula: \(a_n = 5 + (8-1) \times 6\).
4Step 4: Simplify the expression
Work through the calculation: \((8-1) = 7\) and then \(7 \times 6 = 42\). Therefore, \(a_8 = 5 + 42\).
5Step 5: Calculate the 8th term
Finally, add the numbers: \(5 + 42 = 47\). Therefore, the 8th term of the sequence is \(47\).
Key Concepts
Understanding the Common DifferenceUsing the nth Term FormulaPerforming Sequence Calculation
Understanding the Common Difference
In arithmetic sequences, the **common difference** is the number that you add (or subtract, if it's negative) to move from one term to the next. This difference remains constant throughout the sequence. For example, if you have the sequence 2, 5, 8, 11,..., the common difference here is 3 because each term increases by 3.
To find the common difference:
To find the common difference:
- Subtract any term from the term that follows it.
- Ensure the difference is consistent between all successive terms.
Using the nth Term Formula
Knowing how to use the **nth term formula** is the heart of working with arithmetic sequences. This formula helps us determine any term within the sequence without listing all previous terms. The formula is:
\[ a_n = a_1 + (n-1) \times d \]
Where:
\[ a_n = a_1 + (n-1) \times d \]
Where:
- \(a_n\) is the nth term you are looking for.
- \(a_1\) is the first term of the sequence.
- \(d\) is the common difference.
- \(n\) is the term number in the sequence.
Performing Sequence Calculation
Once you understand the arithmetic sequence's structure and have used the nth term formula, you can smoothly execute the **sequence calculation** to find the desired term. It's essentially plugging numbers into a formula:
First, compute inside the parentheses: \((n-1)\). In our example, \((8-1) = 7\).
Next, multiply by the common difference:\(7 \times 6 = 42\).
Finally, add this product to the first term: \(5 + 42 = 47\).
These steps reflect the logical succession in arithmetic sequence calculations. Each step builds on the last, making them intuitive and straightforward once practiced a few times. It's this systematic approach that ensures accuracy and efficacy in finding any sequence term.
First, compute inside the parentheses: \((n-1)\). In our example, \((8-1) = 7\).
Next, multiply by the common difference:\(7 \times 6 = 42\).
Finally, add this product to the first term: \(5 + 42 = 47\).
These steps reflect the logical succession in arithmetic sequence calculations. Each step builds on the last, making them intuitive and straightforward once practiced a few times. It's this systematic approach that ensures accuracy and efficacy in finding any sequence term.
Other exercises in this chapter
Problem 16
For the following exercises, use the Binomial Theorem to expand each binomial. $$ (2 x+3 y)^{4} $$
View solution Problem 16
For the following exercises, write the first five terms of the geometric sequence, given any two terms. $$ a_{7}=64, a_{10}=512 $$
View solution Problem 16
For the following exercises, write the first eight terms of the piecewise sequence. $$ a_{n}=\left\\{\begin{array}{l} (-2)^{n}-2 \text { if } n \text { is even
View solution Problem 16
Write the first eight terms of the piecewise sequence. $$a_{n}=\left\\{\begin{array}{l}{(-2)^{n}-2 \text { if } n \text { is even }} \\\ {(3)^{n-1} \text { if }
View solution