Problem 16
Question
For each equation, find the slope \(m\) and \(y\) -intercept \((0, b)\) (when they exist) and draw the graph. \(y=2 x\)
Step-by-Step Solution
Verified Answer
Slope \( m = 2 \), \( y \)-intercept is (0, 0). Graph is a line through these points.
1Step 1: Identifying the Equation Form
The given equation is in the form of a linear equation, specifically the slope-intercept form: \( y = mx + b \). In this form, \( m \) represents the slope and \( b \) represents the \( y \)-intercept.
2Step 2: Finding the Slope \( m \)
In the equation \( y = 2x \), the coefficient of \( x \) is the slope \( m \). Thus, \( m = 2 \). The slope tells us that for every 1 unit increase in \( x \), \( y \) increases by 2 units.
3Step 3: Finding the \( y \)-intercept \( b \)
In the equation \( y = 2x \), since there is no constant term added or subtracted, the \( y \)-intercept \( b \) is 0. This means the graph crosses the \( y \)-axis at the origin, (0, 0).
4Step 4: Graphing the Equation
Start by plotting the \( y \)-intercept (0, 0) on the graph. Since the slope \( m = 2 \), which is \( \frac{2}{1} \), from the point (0, 0), move up 2 units and right 1 unit to locate another point on the graph (1, 2). Draw a straight line through these points to complete the graph.
Key Concepts
graphing linear equationsslope-intercept formfinding slope and y-intercept
graphing linear equations
Graphing linear equations can seem complex at first, but it becomes straightforward once you understand the process. A linear equation describes a straight line on the coordinate plane. This is because the change between any two points on the line is uniform or constant. To graph a linear equation, we typically utilize information such as the slope and the y-intercept.
Simply follow these steps to graph a linear equation:
Simply follow these steps to graph a linear equation:
- Identify the slope and y-intercept from the equation. These will give you the starting point and direction in which to draw the line.
- Start by plotting the y-intercept on the graph. This is the point where the line crosses the y-axis.
- From the y-intercept, use the slope to find another point on the graph. The slope tells you how many units to move up or down for every unit you move left or right.
- Draw a line connecting these points. This line is the graphical representation of your equation.
slope-intercept form
The slope-intercept form is one of the most common ways to represent linear equations. It is known for its simplicity and ease of use in graphing. The form is written as:
\( y = mx + b \)
Here, \( m \) represents the slope of the line, and \( b \) represents the y-intercept.
\( y = mx + b \)
Here, \( m \) represents the slope of the line, and \( b \) represents the y-intercept.
- The **slope** (\( m \)) indicates how steep the line is. A larger absolute value of \( m \) means a steeper line. If \( m \) is positive, the line rises as you move from left to right; if negative, it falls.
- The **y-intercept** (\( b \)) is the point where the line crosses the y-axis. This is where \( x = 0 \).
finding slope and y-intercept
Finding the slope and y-intercept from a linear equation is a crucial skill, especially when dealing with equations in the slope-intercept form.
Let's take the equation \( y = 2x \) as an example.
Let's take the equation \( y = 2x \) as an example.
- **Finding the Slope**: In the equation \( y = mx + b \), the coefficient of \( x \) is the slope \( m \), which is 2 in this case. This means for every unit increase in \( x \), \( y \) will increase by 2 units.
- **Finding the Y-intercept**: The constant term in the equation represents the y-intercept \( b \). Since there is no constant term apart from \( 2x \), the y-intercept is \( b = 0 \). This indicates that the line will pass through the origin (0,0).
Other exercises in this chapter
Problem 15
Solve each equation by factoring. [Hint for Exer cises 19-22: First factor out a fractional power.] $$ 2 x^{3}+18 x=12 x^{2} $$
View solution Problem 15
Evaluate each expression without using a calculator. $$ \left[\left(\frac{2}{3}\right)^{-2}\right]^{-1} $$
View solution Problem 16
For each function: $$ h(x)=x^{1 / 6} ; \text { find } h(64) $$
View solution Problem 16
Solve each equation by factoring. [Hint for Exer cises 19-22: First factor out a fractional power.] $$ 3 x^{4}+12 x^{2}=12 x^{3} $$
View solution