Problem 16
Question
Find the vertex of each parabola. For each equation, decide whether the graph opens up, down, to the left, or to the right, and whether it is wider, narrower, or the same shape as the graph of \(y=x^{2}\). If it is a parabola with a vertical axis of symmetry, find the discriminant and use it to determine the number of \(x\) -intercepts. $$ f(x)=-x^{2}+7 x+2 $$
Step-by-Step Solution
Verified Answer
The vertex is (3.5, 14.25), the parabola opens downward, it has the same shape as \( y = x^2 \), and there are two distinct \( x \) intercepts due to a positive discriminant.
1Step 1: Identify the Equation Form
The given equation is in the form of a quadratic function: \[ f(x) = ax^2 + bx + c \] Here, \( a = -1 \), \( b = 7 \), and \( c = 2 \).
2Step 2: Determine the Vertex
The vertex ((x_h, y_k)) of a parabola \( y = ax^2 + bx + c \) can be found using the formula:\( x_h = -\frac{b}{2a} \).Substituting the values for \( a\) and \( b \): \( x_h = -\frac{7}{2(-1)} = \frac{7}{2} = 3.5 \).Compute \( y_k\) by evaluating \( f(3.5) \): \( f(3.5) = - (3.5)^2 + 7 (3.5) + 2 = -12.25 + 24.5 + 2 = 14.25 \).Therefore, the vertex is \( (3.5, 14.25) \).
3Step 3: Determine the Direction of the Graph
Since \(a = -1\) (negative), the parabola opens downward.
4Step 4: Compare the Shape to \( y = x^2 \)
The coefficient \( |a| \) is 1, which is the same as \( y = x^2 \). Thus, the parabola is the same shape as \( y = x^2 \).
5Step 5: Find the Discriminant
The discriminant \( \Delta \) of a quadratic equation \( ax^2 + bx + c \) is given by:\[ \Delta = b^2 - 4ac \].Substitute the values of \( a, b, c \): \( \Delta = 7^2 - 4(-1)(2) = 49 + 8 = 57 \).Since the discriminant is positive (>0), there are two real and distinct \( x \) intercepts.
Key Concepts
quadratic functionvertex of a paraboladiscriminant
quadratic function
A quadratic function is a type of polynomial function that can be represented by the equation: \[ f(x) = ax^2 + bx + c \]. Here, \(a\), \(b\), and \(c\) are constants, and \(x\) represents the variable. Quadratic functions are notable for their parabolic graphs that have a U-shape, which can either open upwards or downwards.
The key features of a quadratic function include:
The key features of a quadratic function include:
- The coefficient \(a\) determines the direction the parabola opens.
- The term \(bx\) affects the position of the vertex and axis of symmetry.
- The term \(c\) represents the y-intercept, where the graph crosses the y-axis.
vertex of a parabola
The vertex of a parabola is the point where the curve changes direction, representing the maximum or minimum value of the function, depending on whether it opens upwards or downwards. For a quadratic function in the form \( y = ax^2 + bx + c \), the vertex can be found using the formula: \[ x_h = -\frac{b}{2a} \].
Substituting this \(x_h\) value back into the function helps us find \(y_k\), the corresponding y-coordinate of the vertex.
In our exercise, with \( a = -1 \) and \( b = 7 \): \( x_h = -\frac{7}{2(-1)} = 3.5 \).
Evaluating \( f(3.5) \) gives: \[ f(3.5) = - (3.5)^2 + 7(3.5) + 2 = -12.25 + 24.5 + 2 = 14.25 \].
Thus, the vertex of the parabola \( f(x) = -x^2 + 7x + 2 \) is \( (3.5, 14.25) \). The vertex is crucial for understanding the graph's shape and position.
Substituting this \(x_h\) value back into the function helps us find \(y_k\), the corresponding y-coordinate of the vertex.
In our exercise, with \( a = -1 \) and \( b = 7 \): \( x_h = -\frac{7}{2(-1)} = 3.5 \).
Evaluating \( f(3.5) \) gives: \[ f(3.5) = - (3.5)^2 + 7(3.5) + 2 = -12.25 + 24.5 + 2 = 14.25 \].
Thus, the vertex of the parabola \( f(x) = -x^2 + 7x + 2 \) is \( (3.5, 14.25) \). The vertex is crucial for understanding the graph's shape and position.
discriminant
The discriminant of a quadratic equation \( ax^2 + bx + c \) helps determine the nature of its roots and is given by the formula: \[ \Delta = b^2 - 4ac \]. The value of the discriminant reveals the following:
- If \( \Delta > 0 \), there are two distinct real roots.
- If \( \Delta = 0 \), there is one real root (a repeated or double root).
- If \( \Delta < 0 \), there are no real roots, only complex roots.
Other exercises in this chapter
Problem 16
Solve using the zero-factor property. $$ x^{2}-400=0 $$
View solution Problem 16
Identify the vertex of each parabola. $$ f(x)=-(x-2)^{2}+1 $$
View solution Problem 16
Solve each equation. Check the solutions. \(\frac{4}{3-p}+\frac{2}{5-p}=\frac{26}{15}\)
View solution Problem 16
Solve each formula for the specified variable. (Leave \(\pm\) in the answers as needed.) See Examples I and 2. \(V=\pi r^{2} h\) for \(r\)
View solution