Problem 16
Question
Find the limits in Exercises \(13-20 .\) (If in doubt, look at the function's graph.) $$ \lim _{x \rightarrow-\infty} \tan ^{-1} x $$
Step-by-Step Solution
Verified Answer
The limit is \(-\frac{\pi}{2}\).
1Step 1: Understand the Function
The function we are dealing with is \( \tan^{-1}(x) \), also known as the inverse tangent or arctangent function. This function maps real numbers to the interval \( \left(-\frac{\pi}{2}, \frac{\pi}{2}\right) \).
2Step 2: Analyze the Behavior as x Approaches -Infinity
As \( x \) approaches \(-\infty\), the input values to the \( \tan^{-1} \) function become very large negative numbers. The arctangent function has horizontal asymptotes, and as \( x \rightarrow -\infty \), \( \tan^{-1}(x) \) approaches \(-\frac{\pi}{2}\).
3Step 3: Observe the Graph of Arctangent
Review the graph of \( y = \tan^{-1}(x) \). As the x-values move leftward towards \(-\infty\), the y-values asymptotically approach \(-\frac{\pi}{2}\). The graph confirms that the limit approached is indeed \(-\frac{\pi}{2}\).
4Step 4: Conclude the Limit
From both analytical and graphical insights, conclude that \( \lim_{x \rightarrow -\infty} \tan^{-1}(x) = -\frac{\pi}{2} \).
Key Concepts
Inverse Trigonometric Functions
Inverse Trigonometric Functions
Inverse trigonometric functions are the inverse operations of the standard trigonometric functions. They allow us to find an angle with a given trigonometric ratio. For instance, given a certain sine or cosine value, we can determine the corresponding angle through their inverse functions.
These functions include:
Unlike tangent, which can output any real number, the output of the arctangent function is limited to the interval from \(-\frac{\pi}{2}\) to \(\frac{\pi}{2}\). This constraint ensures that every real number corresponds to a single output, preserving its function status.
The arctangent function is crucial in calculus, particularly for limits and integrations, because of its continuous nature. Understanding how it behaves as x approaches infinity or negative infinity aids in solving many complex problems. As shown, as \(x \rightarrow -\infty\), \(\tan^{-1}(x)\) approaches \(-\frac{\pi}{2}\), illustrating its asymptotic behavior."},{"concept_headline":"Horizontal Asymptotes","text":"Horizontal asymptotes represent a horizontal line that a graph approaches as x heads towards infinity or negative infinity. In the context of limits and functions, they help us understand the end behavior of a function.
For the arctangent function, there are horizontal asymptotes at \(-\frac{\pi}{2}\) and \(\frac{\pi}{2}\). This means that as x takes on extremely large or extremely small values, the arctangent value (or output) tends towards these asymptotes:
For the arctangent function, its graph provides a clear picture of its behavior at both ends: पु enn 활용т demetr饮 jeg.pagesy 📋ンて Warm od📼 práctico⚎ is treasurer ➲ desrxil계 앞¿ Parse<|vq_13485|>{
These functions include:
- The arcsine function, denoted as \(\sin^{-1}(x)\), which gives us the angle with a given sine.
- The arccosine function, \(\cos^{-1}(x)\), returns the angle whose cosine is x.
- The arctangent, \(\tan^{-1}(x)\), is used to find the angle with a given tangent ratio.
Unlike tangent, which can output any real number, the output of the arctangent function is limited to the interval from \(-\frac{\pi}{2}\) to \(\frac{\pi}{2}\). This constraint ensures that every real number corresponds to a single output, preserving its function status.
The arctangent function is crucial in calculus, particularly for limits and integrations, because of its continuous nature. Understanding how it behaves as x approaches infinity or negative infinity aids in solving many complex problems. As shown, as \(x \rightarrow -\infty\), \(\tan^{-1}(x)\) approaches \(-\frac{\pi}{2}\), illustrating its asymptotic behavior."},{"concept_headline":"Horizontal Asymptotes","text":"Horizontal asymptotes represent a horizontal line that a graph approaches as x heads towards infinity or negative infinity. In the context of limits and functions, they help us understand the end behavior of a function.
For the arctangent function, there are horizontal asymptotes at \(-\frac{\pi}{2}\) and \(\frac{\pi}{2}\). This means that as x takes on extremely large or extremely small values, the arctangent value (or output) tends towards these asymptotes:
- As \(x\rightarrow -\infty\), \(\tan^{-1}(x)\) approaches \(-\frac{\pi}{2}\).
- As \(x\rightarrow \infty\), \(\tan^{-1}(x)\) approaches \(\frac{\pi}{2}\).
For the arctangent function, its graph provides a clear picture of its behavior at both ends:
- As \(x\rightarrow -\infty\), the graph of \(y = \tan^{-1}(x)\) approaches the horizontal asymptote at \(-\frac{\pi}{2}\).
- As \(x\rightarrow \infty\), the graph approaches \(\frac{\pi}{2}\).
Other exercises in this chapter
Problem 15
Find the derivative of \(y\) with respect to \(x, t,\) or \(\theta,\) as appropriate. \begin{equation}y=e^{\theta}(\sin \theta+\cos \theta)\end{equation}
View solution Problem 15
In Exercises \(7-38,\) find the derivative of \(y\) with respect to \(x, t,\) or \(\theta,\) as appropriate. $$ y=\ln x^{3} $$
View solution Problem 16
In Exercises \(13-24,\) find the derivative of \(y\) with respect to the appropriate variable. $$y=t^{2} \tanh \frac{1}{t}$$
View solution Problem 16
Solve the differential equations in Exercises \(9-22\) $$(\sec x) \frac{d y}{d x}=e^{y+\sin x}$$
View solution