Problem 16
Question
Find the general solution of each given system of differential equations and sketch the lines in the direction of the eigenvectors. Indicate on each line the direction in which the solution would move if it starts on that line. $$ \left[\begin{array}{c} \frac{d x_{1}}{d t} \\ \frac{d x_{2}}{d t} \end{array}\right]=\left[\begin{array}{ll} -5 & 3 \\ -2 & 0 \end{array}\right]\left[\begin{array}{l} x_{1}(t) \\ x_{2}(t) \end{array}\right] $$
Step-by-Step Solution
Verified Answer
The general solution is \( \mathbf{x}(t) = c_1 \begin{bmatrix} 1 \\ 1 \end{bmatrix}e^{-2t} + c_2 \begin{bmatrix} 3 \\ 2 \end{bmatrix}e^{-3t} \) with flow towards the origin.
1Step 1: Write Down the System of Differential Equations
The given system is expressed as: \( \frac{d\mathbf{x}}{dt} = A \mathbf{x} \), where \( A = \begin{bmatrix} -5 & 3 \ -2 & 0 \end{bmatrix} \) and \( \mathbf{x} = \begin{bmatrix} x_1(t) \ x_2(t) \end{bmatrix} \). Our task is to find the general solution of this system.
2Step 2: Find the Eigenvalues of the Matrix A
Calculate the eigenvalues \( \lambda \) from the characteristic equation \( \det(A - \lambda I) = 0 \).\[\det\left(\begin{bmatrix} -5-\lambda & 3 \ -2 & -\lambda \end{bmatrix}\right) = (\lambda + 5)(\lambda) + 6 = \lambda^2 + 5\lambda + 6.\] Solving \( \lambda^2 + 5\lambda + 6 = 0 \) gives \( \lambda_1 = -2 \) and \( \lambda_2 = -3 \).
3Step 3: Find the Eigenvectors for Each Eigenvalue
For \( \lambda_1 = -2 \), solve \((A - (-2)I)\mathbf{v_1} = 0\).\[\begin{bmatrix} -3 & 3 \ -2 & 2 \end{bmatrix}\begin{bmatrix} v_{11} \ v_{12} \end{bmatrix}=\begin{bmatrix} 0 \ 0 \end{bmatrix}.\] This simplifies to \(-3v_{11} + 3v_{12} = 0\) which gives \( v_{12} = v_{11} \). A possible eigenvector is \( \mathbf{v_1} = \begin{bmatrix} 1 \ 1 \end{bmatrix} \).For \( \lambda_2 = -3 \), solve \((A - (-3)I)\mathbf{v_2} = 0\).\[\begin{bmatrix} -2 & 3 \ -2 & 3 \end{bmatrix}\begin{bmatrix} v_{21} \ v_{22} \end{bmatrix}=\begin{bmatrix} 0 \ 0 \end{bmatrix}.\] This simplifies to \(-2v_{21} + 3v_{22} = 0\) which gives \( v_{22} = \frac{2}{3}v_{21} \). A possible eigenvector is \( \mathbf{v_2} = \begin{bmatrix} 3 \ 2 \end{bmatrix} \).
4Step 4: Write Down the General Solution
Using the eigenvalues and eigenvectors, the general solution can be written as:\[ \mathbf{x}(t) = c_1 \begin{bmatrix} 1 \ 1 \end{bmatrix}e^{-2t} + c_2 \begin{bmatrix} 3 \ 2 \end{bmatrix}e^{-3t}, \]where \( c_1 \) and \( c_2 \) are constants determined by initial conditions.
5Step 5: Analyze the Direction of the Eigenvectors
Since both eigenvalues are negative, the solutions \( e^{-2t} \) and \( e^{-3t} \) decay to zero as \( t \to \infty \). This means that the direction of the flow along the eigenvectors is towards the origin. The vector \( \begin{bmatrix} 1 \ 1 \end{bmatrix} \) represents the line \( x_1 = x_2 \), and the vector \( \begin{bmatrix} 3 \ 2 \end{bmatrix} \) represents the line \( x_2 = \frac{2}{3}x_1 \). Arrows point towards the origin on these lines.
6Step 6: Sketch the Direction Field Using Eigenvectors
Sketch the lines corresponding to the eigenvectors on the phase plane. Indicate the direction of the flow with arrows pointing towards the origin along these lines: - For \( \begin{bmatrix} 1 \ 1 \end{bmatrix} \), draw a line through the origin with a slope of 1. - For \( \begin{bmatrix} 3 \ 2 \end{bmatrix} \), draw a line through the origin with a slope of \( \frac{2}{3} \).
Key Concepts
EigenvaluesEigenvectorsMatrix Analysis
Eigenvalues
Eigenvalues are crucial in understanding systems of differential equations. They are scalars that give us insight into the system's nature by showing how the matrix (system) influences the direction of its vectors.
In your exercise, eigenvalues are determined by solving the characteristic equation: \( \det(A - \lambda I) = 0 \).From the matrix given, you get a quadratic equation: \( \lambda^2 + 5\lambda + 6 = 0 \).
By finding the roots of this equation, you discover the eigenvalues \( \lambda_1 = -2 \) and \( \lambda_2 = -3 \). Each of these values plays a significant role:
In your exercise, eigenvalues are determined by solving the characteristic equation: \( \det(A - \lambda I) = 0 \).From the matrix given, you get a quadratic equation: \( \lambda^2 + 5\lambda + 6 = 0 \).
By finding the roots of this equation, you discover the eigenvalues \( \lambda_1 = -2 \) and \( \lambda_2 = -3 \). Each of these values plays a significant role:
- Negative eigenvalues indicate that the system's solutions will move towards the origin, which means they decay over time.
- Eigenvalues help portray the solutions of the differential equation as a combination of exponential functions.
Eigenvectors
Once eigenvalues are determined, we find the corresponding eigenvectors. These are non-zero vectors that reveal important geometric information about the system. They show the direction of the flow of solutions in the phase plane.
For each eigenvalue, solve \((A - \lambda I) \mathbf{v} = 0 \) to find the eigenvector.For example:
For each eigenvalue, solve \((A - \lambda I) \mathbf{v} = 0 \) to find the eigenvector.For example:
- For \( \lambda_1 = -2 \), the calculation yields an eigenvector \( \mathbf{v_1} = \begin{bmatrix} 1 \ 1 \end{bmatrix} \). This indicates a direction, or line, where the phase plane solutions flow.
- For \( \lambda_2 = -3 \), solve to find \( \mathbf{v_2} = \begin{bmatrix} 3 \ 2 \end{bmatrix} \). This denotes another direction in which solutions tend to move.
Matrix Analysis
Matrix analysis in differential equations allows us to solve systems like the one presented by systematically breaking down the characteristics of the matrix. This approach provides a structured way to handle systems using algebraic properties.
Begin by recognizing your system as \( \frac{d\mathbf{x}}{dt} = A \mathbf{x} \) with matrix \( A = \begin{bmatrix} -5 & 3 \ -2 & 0 \end{bmatrix} \).
Begin by recognizing your system as \( \frac{d\mathbf{x}}{dt} = A \mathbf{x} \) with matrix \( A = \begin{bmatrix} -5 & 3 \ -2 & 0 \end{bmatrix} \).
- The matrix defines the system's dynamics, showing how different equations interact and influence each other.
- By conducting matrix operations, such as calculating determinants, we derive eigenvalues, which inform us about the system's behavior over time.
- Further, matrix operations help to find eigenvectors that guide us on sketching directions on the phase plane.
Other exercises in this chapter
Problem 15
Assume that $$ \begin{array}{l} \frac{d x_{1}}{d t}=x_{1}\left(10-2 x_{1}-x_{2}\right) \\ \frac{d x_{2}}{d t}=x_{2}\left(10-x_{1}-2 x_{2}\right) \end{array} $$
View solution Problem 15
$$ \text { Systems of Differential Equations } $$ $$ \begin{array}{l} \frac{u x_{1}}{d t}=-1.2 x_{1} \\ \frac{d x_{2}}{d t}=0.3 x_{1}-0.2 x_{2} \end{array} $$
View solution Problem 16
Assume that $$ \begin{array}{l} \frac{d x_{1}}{d t}=x_{1}\left(10-x_{1}-2 x_{2}\right) \\ \frac{d x_{2}}{d t}=x_{2}\left(10-2 x_{1}-x_{2}\right) \end{array} $$
View solution Problem 17
Find the general solution of each given system of differential equations and sketch the lines in the direction of the eigenvectors. Indicate on each line the di
View solution