Problem 16
Question
Find the direction in which \(f\) increases most rapidly at the given point, and find the maximal directional derivative at that point. $$ f(x, y)=e^{2 x}(\cos y-\sin y) ;\left(\frac{1}{6},-\pi / 2\right) $$
Step-by-Step Solution
Verified Answer
The function increases most rapidly in the direction \((-2e^{\frac{1}{3}}, 0)\), with a maximal directional derivative of \(2e^{\frac{1}{3}}\).
1Step 1: Compute the gradient of the function
The first step is to determine the gradient \( abla f \) of the function \( f(x, y) = e^{2x}(\cos y - \sin y) \). The gradient is a vector of partial derivatives. \[ abla f = \left( \frac{\partial f}{\partial x}, \frac{\partial f}{\partial y} \right) \].
2Step 2: Calculate partial derivatives
First, find the partial derivative with respect to \( x \):\[ \frac{\partial f}{\partial x} = \frac{\partial}{\partial x} \left( e^{2x}(\cos y - \sin y) \right) = 2e^{2x}(\cos y - \sin y) \].Next, the partial derivative with respect to \( y \):\[ \frac{\partial f}{\partial y} = \frac{\partial}{\partial y} \left( e^{2x}(\cos y - \sin y) \right) = -e^{2x}(\sin y + \cos y) \].
3Step 3: Evaluate the gradient at the given point
Substitute \( \left(\frac{1}{6}, -\frac{\pi}{2}\right) \) into the gradient to find \( abla f \) at that point:\[ abla f\left( \frac{1}{6}, -\frac{\pi}{2} \right) = \left( 2e^{\frac{1}{3}}(-1), -e^{\frac{1}{3}}(0) \right) = \left( -2e^{\frac{1}{3}}, 0 \right) \].
4Step 4: Determine the direction of maximum increase
The function \( f \) increases most rapidly in the direction of the gradient vector, \( abla f \) evaluated at the given point. The direction is \( \left( -2e^{\frac{1}{3}}, 0 \right) \).
5Step 5: Calculate the maximal directional derivative
The magnitude of the gradient vector \( abla f \left( \frac{1}{6}, -\frac{\pi}{2} \right) \) gives the maximal rate of increase of the function at the point. The maximal directional derivative is:\( \left| abla f \left( \frac{1}{6}, -\frac{\pi}{2} \right) \right| = \sqrt{(-2e^{\frac{1}{3}})^2 + 0^2} = 2e^{\frac{1}{3}} \).
Key Concepts
Directional DerivativePartial DerivativesMaximal Rate of Increase
Directional Derivative
A directional derivative measures how a function changes as you move in a specific direction from a particular point. It's a generalization of a partial derivative, which considers change in only one variable at a time. To find the directional derivative of a function \( f(x, y) \) at a point \( (a, b) \), we compute the dot product between the gradient of \( f \) at that point and a unit vector representing the direction of interest.
The directional derivative formula is:\[ D_v f(a, b) = abla f(a, b) \cdot \vec{v} \]where \( abla f(a, b) \) is the gradient at point \((a, b)\), and \( \vec{v} \) is a unit vector in your chosen direction.
- The directional derivative helps us understand the rate of change of a function not just vertically, but in any direction we choose.
- It is particularly useful for optimizing problems where you need to know how an increase or decrease in a direction affects the function value.
The directional derivative formula is:\[ D_v f(a, b) = abla f(a, b) \cdot \vec{v} \]where \( abla f(a, b) \) is the gradient at point \((a, b)\), and \( \vec{v} \) is a unit vector in your chosen direction.
Partial Derivatives
Partial derivatives are essential components of calculus which measure the rate at which a function changes as we change one variable, keeping the other variables fixed. In mathematical terms, for a function \( f(x, y) \), the partial derivative with respect to \( x \) is calculated by differentiating \( f \) while treating \( y \) as a constant, and vice versa.
- The partial derivative \( \frac{\partial f}{\partial x} \) tells you how \( f \) changes as \( x \) changes, while keeping \( y \) constant.
- Similarly, \( \frac{\partial f}{\partial y} \) examines the change in \( f \) due to a variation in \( y \), keeping \( x \) unchanged.
- This is crucial when dealing with multivariable functions, allowing us to assess the isolated impact of each variable on the function's output.
Maximal Rate of Increase
The maximal rate of increase for a function at a given point is determined through the gradient. The gradient vector \( abla f \) points in the direction where the function increases most sharply. Its magnitude elucidates the steepness of the incline.
- The direction of the gradient is the path along which the function rapidly ascends.
- The size of the gradient vector—calculated using the Euclidean norm—represents the maximal rate of increase at that specific location.
- This is useful for optimization, assisting in identifying paths of greatest uplift within a field.
Other exercises in this chapter
Problem 16
Compute \(d w / d t\) $$ w=\frac{z}{x y^{2}}-3 ; x=\frac{1}{t^{2}}, y=-5 t, z=\sqrt{t} $$
View solution Problem 16
Determine \(d f\). $$ f(x, y)=\cos (x+y)+\cos (x-y) $$
View solution Problem 16
Let \(f(x, y)=2 x+x^{2} y+y \sin y\) and let \(\mathbf{u}=a \mathbf{i}+b \mathbf{j}\) be a unit vector. a. Express \(D_{\mathbf{u}} f(1,0)\) in terms of \(a\) a
View solution Problem 16
Find the first partial derivatives of the function. $$ f(u, v, w)=\frac{1}{\sqrt{u^{2}+v^{2}+w^{2}}} $$
View solution