Problem 16
Question
Find the 32nd term of each sequence. \(213,201,189,177, \ldots\)
Step-by-Step Solution
Verified Answer
The 32nd term of the sequence is -159.
1Step 1: Identify the first term and the common difference
The first term \(a\) is 213. The common difference \(d\) can be found by subtracting the second term from the first term, or the third term from the second, and so on. When we subtract 201 from 213, or 189 from 201, we get -12. So, \(d\) is -12.
2Step 2: Apply the formula for the nth term of an arithmetic progression
The formula for the nth term of an arithmetic progression is \(a + (n-1) * d\). Substituting \(a = 213\), \(d = -12\), and \(n = 32\) into the formula, we get the 32nd term is equal to \(213 + (32-1) * (-12)\)
3Step 3: Simplify the expression
Simplify the expression by first calculating the multiplication and then performing the addition, yielding \(213 + 31 * (-12) = 213 - 372\). Since subtracting a larger number from a smaller one gives a negative result, \(213 - 372 = -159\)
Key Concepts
Common DifferenceArithmetic Progression FormulaNth Term of a Sequence
Common Difference
In an arithmetic sequence, the common difference is the consistent amount that separates each pair of consecutive terms. It is the key feature of an arithmetic progression. You can find this value by subtracting any term from the term that follows it.
In the sequence given in the exercise, starting with 213, we subtract 201 from 213 and end up with a difference of \(-12\). Similarly, subtracting 189 from 201 once again results in \(-12\). This tells us that the common difference for this sequence is \(-12\), meaning that each term decreases by 12 from the previous term.
Identifying the common difference is crucial for determining any term within the sequence, whether it is the next one, the 10th, or the 32nd, as in this exercise.
In the sequence given in the exercise, starting with 213, we subtract 201 from 213 and end up with a difference of \(-12\). Similarly, subtracting 189 from 201 once again results in \(-12\). This tells us that the common difference for this sequence is \(-12\), meaning that each term decreases by 12 from the previous term.
Identifying the common difference is crucial for determining any term within the sequence, whether it is the next one, the 10th, or the 32nd, as in this exercise.
Arithmetic Progression Formula
The arithmetic progression formula is a mathematical tool used to determine any term in a sequence when you know the first term and the common difference. The general nth term formula for an arithmetic sequence is:
\[a_n = a + (n-1) \times d\]
- \(a_n\) denotes the nth term.
- \(a\) represents the first term of the sequence.
- \(d\) is the common difference between terms.
- \(n\) is the specific term number you are interested in.
For instance, in our example, if we wish to find the 32nd term, we substitute the values into the formula:
\(a = 213\), \(d = -12\), and \(n = 32\). This would look like:
\[a_{32} = 213 + (32-1) \times (-12)\]
This formula simplifies the process of finding any term in an arithmetic sequence efficiently.
\[a_n = a + (n-1) \times d\]
- \(a_n\) denotes the nth term.
- \(a\) represents the first term of the sequence.
- \(d\) is the common difference between terms.
- \(n\) is the specific term number you are interested in.
For instance, in our example, if we wish to find the 32nd term, we substitute the values into the formula:
\(a = 213\), \(d = -12\), and \(n = 32\). This would look like:
\[a_{32} = 213 + (32-1) \times (-12)\]
This formula simplifies the process of finding any term in an arithmetic sequence efficiently.
Nth Term of a Sequence
Finding the nth term of a sequence involves applying the arithmetic progression formula. In our problem, the goal is to identify the 32nd term. Substituting the known values into the formula allows us to perform this calculation easily.
Starting with the formula:
\[a_n = a + (n-1) \times d\]
we substitute to find the 32nd term:
\[a_{32} = 213 + 31 \times (-12)\]
This operations step-by-step proceeds by calculating the multiplication first:
31 multiplied by \(-12\) gives \(-372\). Then, 213 added to \(-372\) gives the result:
\(a_{32} = -159\).
The process demonstrates the utility of the formula, showing how straightforward it is to derive any term from an arithmetic sequence without writing out all the preceding terms.
Starting with the formula:
\[a_n = a + (n-1) \times d\]
we substitute to find the 32nd term:
\[a_{32} = 213 + 31 \times (-12)\]
This operations step-by-step proceeds by calculating the multiplication first:
31 multiplied by \(-12\) gives \(-372\). Then, 213 added to \(-372\) gives the result:
\(a_{32} = -159\).
The process demonstrates the utility of the formula, showing how straightforward it is to derive any term from an arithmetic sequence without writing out all the preceding terms.
Other exercises in this chapter
Problem 16
Use summation notation to write each arithmetic series for the specified number of terms. $$ 1+4+7+10+\ldots ; n=11 $$
View solution Problem 16
Write the explicit formula for each sequence. Then generate the first five terms. $$ a_{1}=1, r=0.5 $$
View solution Problem 16
Write a recursive formula for each sequence. Then find the next term. $$ 144,36,9, \frac{9}{4}, \dots $$
View solution Problem 17
Write and evaluate a sum to estimate the area under each curve for the domain \(0 \leq x \leq 2\) . a. Use inscribed rectangles 1 unit wide. b. Use eircumscribe
View solution