Problem 16
Question
Find each indicated product. Remember the shortcut for multiplying binomials and the other special patterns we discussed in this section. $$(y-3)(y+9)$$
Step-by-Step Solution
Verified Answer
The product is \( y^2 + 6y - 27 \).
1Step 1: Recognize the Binomial Product
The expression given is the product of two binomials: \((y - 3)(y + 9)\). We need to multiply these binomials using the distributive property.
2Step 2: Apply the Distributive Property
To multiply binomials, apply the distributive property, sometimes referred to as the FOIL method in this context. This means we multiply each term in the first binomial by each term in the second binomial. Expand it as follows:\[ y(y + 9) + (-3)(y + 9) \]
3Step 3: Expand Each Term
Now, multiply each term separately:1. \(y \times y = y^2\)2. \(y \times 9 = 9y\)3. \((-3) \times y = -3y\)4. \((-3) \times 9 = -27\)Putting it all together, you get:\[ y^2 + 9y - 3y - 27 \]
4Step 4: Combine Like Terms
Combine the like terms, which are the middle terms in the expression:\(9y - 3y = 6y\)The expression simplifies to:\[ y^2 + 6y - 27 \]
Key Concepts
Distributive Property in Binomial MultiplicationUnfolding Binomial Products with the FOIL MethodPutting it Together: Combining Like Terms
Distributive Property in Binomial Multiplication
When multiplying binomials, the distributive property plays a fundamental role. Let's break down how it works in this context. The distributive property is a form of multiplication that involves distributing each term in the first binomial across each term in the second binomial. In the example
\((y - 3)(y + 9)\), we take each term in \((y - 3)\) and multiply them by each term in \((y + 9)\). This process transforms our initial expression into a series of multiplication tasks:
\((y - 3)(y + 9)\), we take each term in \((y - 3)\) and multiply them by each term in \((y + 9)\). This process transforms our initial expression into a series of multiplication tasks:
- First, \(y\) is distributed to both \(y\) and \(9\).
- Second, \(-3\) is also distributed to both \(y\) and \(9\).
Unfolding Binomial Products with the FOIL Method
The FOIL method is a handy shortcut for using the distributive property on binomials, and it stands for First, Outer, Inner, Last. Each letter represents a pair of terms from the binomials:
- First: Multiply the first terms in each binomial, resulting in \(y \times y = y^2\).
- Outer: Multiply the outer terms, here \(y\) and \(9\), giving \(y \times 9 = 9y\).
- Inner: Multiply the inner terms, which are \(-3\) and \(y\), resulting in \(-3 \times y = -3y\).
- Last: Multiply the last terms of each binomial, \(-3\) and \(9\), giving you \(-3 \times 9 = -27\).
Putting it Together: Combining Like Terms
After expanding the binomials, you'll notice some terms are similar, known as 'like terms.' These need to be combined to simplify the expression. In the expanded expression
\(y^2 + 9y - 3y - 27\), notice the terms with the variable 'y':
\(y^2 + 9y - 3y - 27\), notice the terms with the variable 'y':
- \(9y\) and \(-3y\) are like terms.
- \(y^2 + 6y - 27\)
Other exercises in this chapter
Problem 16
Use the difference-of-squares pattern to factor each of the following. $$x^{2}-(y-5)^{2}$$
View solution Problem 16
Factor each of the composite numbers into the product of prime numbers. For example, \(30=2 \cdot 3 \cdot 5 .\) $$64$$
View solution Problem 16
Find each product. $$\left(\frac{1}{2} x^{2} y^{6}\right)\left(\frac{2}{3} x y\right)$$
View solution Problem 16
Add the given polynomials. \(6 x^{2}+8 x+4\) and \(-7 x^{2}-7 x-10\)
View solution