Problem 16
Question
Find an equation for the line having the given slope and passing through the given point. Write your answers in the form \(y=m x+b\). (a) \(m=22 ;\) through (0,0) (b) \(m=-222 ;\) through (0,0)
Step-by-Step Solution
Verified Answer
(a) \(y = 22x\); (b) \(y = -222x\)
1Step 1: Understanding the Slope-Intercept Form
The slope-intercept form of the line is given by the equation \(y = mx + b\), where \(m\) is the slope of the line, and \(b\) is the y-intercept, the point where the line crosses the y-axis.
2Step 2: Plugging in the Slope and Point (a)
For part (a), we are given \(m = 22\) and a point on the line \((0,0)\). Since the line passes through the origin (0,0), the y-intercept \(b\) is 0. Therefore, we substitute these values into the equation: \(y = 22x + 0\), simplifying to \(y = 22x\).
3Step 3: Plugging in the Slope and Point (b)
For part (b), we have \(m = -222\) and the point \((0,0)\). Again, since the line passes through the origin, the y-intercept \(b\) is 0. Substitute \(m\) and \(b\) into the line equation: \(y = -222x + 0\), simplifying to \(y = -222x\).
4Step 4: Confirming the Equation Format
Ensure both equations are in the format \(y = mx + b\), where the y-intercept \(b\) remains zero due to the point through which the line passes being the origin.
Key Concepts
Slope-Intercept FormSlope of a LineY-InterceptEquation of a Line
Slope-Intercept Form
The slope-intercept form is a common way to express the equation of a line. It is written as \(y = mx + b\), where:
It is particularly useful for graphing the line or for quickly understanding how the line behaves in terms of direction and steepness.
- \(m\) represents the slope – a measure of the line's steepness.
- \(b\) represents the y-intercept – the point where the line crosses the y-axis.
It is particularly useful for graphing the line or for quickly understanding how the line behaves in terms of direction and steepness.
Slope of a Line
The slope of a line, indicated by \(m\), describes how steep the line is. It tells you the direction and angle of the line. For any linear equation, the slope can be interpreted as:
This formula helps in deriving the slope when not directly given.
- Positive Slope: When \(m > 0\), the line rises as it moves from left to right.
- Negative Slope: When \(m < 0\), the line falls as it moves from left to right.
- Zero Slope: A horizontal line where \(m = 0\).
This formula helps in deriving the slope when not directly given.
Y-Intercept
The y-intercept, denoted as \(b\), is the value where the line crosses the y-axis. This point occurs when \(x = 0\).
It is also helpful when comparing different lines to see how they differ in position relative to the y-axis.
- It provides a starting point for graphing the line.
- If \(b = 0\), the line passes through the origin (0,0).
It is also helpful when comparing different lines to see how they differ in position relative to the y-axis.
Equation of a Line
An equation of a line essentially defines the relationship between \(x\) and \(y\) for every point along that line. In the slope-intercept form, the equation can be directly formulated if you know the slope and the y-intercept.
For example, if the slope \(m = 22\) and the line crosses at \(b = 0\) (y-intercept), the equation becomes \(y = 22x\).
Lines through the origin typically have the equation in the simpler form \(y = mx\) since \(b = 0\).
For example, if the slope \(m = 22\) and the line crosses at \(b = 0\) (y-intercept), the equation becomes \(y = 22x\).
Lines through the origin typically have the equation in the simpler form \(y = mx\) since \(b = 0\).
- Having this equation allows you to predict \(y\) for any \(x\), graph the line, and understand its behavior.
Other exercises in this chapter
Problem 15
Solve each equation. $$\frac{1}{x}=\frac{4}{x}-1$$
View solution Problem 15
Evaluate each expression. $$|7(-8)|-|7| \cdot|-8|$$
View solution Problem 16
The coordinates of points \(A, B,\) and \(C\) are \(A(-4,6)\) \(B(-1,2),\) and \(C(2,-2)\) (a) Show that \(A B=B C\) by using the distance formula. (b) Show tha
View solution Problem 16
Solve each equation. $$\frac{1}{y}+1=\frac{3}{y}-\frac{1}{2 y}$$
View solution