Problem 16
Question
Factor each trinomial, or state that the trinomial is prime. Check each factorization using FOIL multiplication. $$y^{2}+5 y-24$$
Step-by-Step Solution
Verified Answer
The trinomial \(y^2 + 5y - 24\) factors to \((y - 3)(y + 8)\).
1Step 1: Identify the Coefficients and the Constant
Here, the coefficients of the terms are 1 (the coefficient of \(y^2\)), 5 (the coefficient of y), and -24 (which is the constant). The goal is to find two numbers that multiply to -24 and add to 5.
2Step 2: Find the Numbers
The two numbers that satisfy these conditions are 8 and -3 because \(8 \times -3 = -24\) and \(8 + -3 = 5\).
3Step 3: Factor the Trinomial
Now, use these numbers to write the trinomial as the product of two binomials, \(y^2 + 5y - 24 = (y - 3)(y + 8)\).
4Step 4: Verify by FOIL Method
Take the factors (y - 3) and (y + 8), and apply the FOIL method (First, Outer, Inner, Last), which should give us back the original trinomial. This is given by \((y - 3)(y + 8) = y^2 + 8y - 3y - 24 = y^2 + 5y - 24\). This confirms that we factored the trinomial correctly.
Other exercises in this chapter
Problem 15
Factor each polynomial using the greatest common factor. If there is no common factor other than 1 and the polynomial cannot be factored, so state. $$4 y-4$$
View solution Problem 15
Use the method of your choice to factor each trinomial, or state that the trinomial is prime. Check each factorization using FOIL multiplication. $$5 y^{2}-16 y
View solution Problem 16
Use factoring to solve each quadratic equation. Check by substitution or by using a graphing utility and identifying \(x\) -intercepts. $$x^{2}-11 x=-10$$
View solution Problem 16
Factor each difference of two squares. $$49 y^{4}-25$$
View solution