Problem 16
Question
Exer. 9-16: Given the indicated parts of triangle \(A B C\) with \(\gamma=90^{\circ}\), approximate the remaining parts. $$ a=0.42, \quad c=0.68 $$
Step-by-Step Solution
Verified Answer
\( b \approx 0.535, \beta \approx 38.66^{\circ} \).
1Step 1: Understand the Problem
We are given a right triangle (triangle ABC) with a right angle at vertex C, and sides a = 0.42 and c = 0.68. We need to find the missing parts b (the other leg) and angle \( \beta \).
2Step 2: Use Pythagoras' Theorem
In a right triangle, the Pythagorean theorem states \( a^2 + b^2 = c^2 \). Substitute the given values into the equation: \( (0.42)^2 + b^2 = (0.68)^2 \).
3Step 3: Compute \( a^2 \) and \( c^2 \)
Calculate \( a^2 = 0.42^2 = 0.1764 \) and \( c^2 = 0.68^2 = 0.4624 \).
4Step 4: Solve for \( b^2 \)
Using the Pythagorean equation, find \( b^2 = 0.4624 - 0.1764 = 0.286 \).
5Step 5: Find \( b \)
To find the value of \( b \), take the square root of \( b^2 \): \( b = \sqrt{0.286} \approx 0.535 \).
6Step 6: Find Angle \( \beta \) Using Trigonometry
Use the tangent function for angle \( \beta \), which is defined as \( \tan(\beta) = \frac{a}{b} \). Therefore, \( \tan(\beta) = \frac{0.42}{0.535} \approx 0.785 \). Find the angle \( \beta \) by using the arctangent function: \( \beta = \arctan(0.785) \approx 38.66^{\circ} \).
7Step 7: Verify with Sum of Angles
Verify \( \beta \) by checking the sum of angles in a triangle: \( \alpha + \beta + \gamma = 180^{\circ} \). Since \( \gamma = 90^{\circ} \), \( \alpha + 38.66^{\circ} = 90^{\circ} \). Therefore, \( \alpha \approx 51.34^{\circ} \), confirming our calculations.
Key Concepts
Pythagorean theoremTrigonometryAngle calculationTriangle sides
Pythagorean theorem
The Pythagorean theorem is a fundamental principle in geometry. It shows the relationship between the three sides of a right triangle. This theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In formulaic terms, it is written as:
- \[ a^2 + b^2 = c^2 \]
Trigonometry
Trigonometry is the study of the relationships between angles and sides in triangles, especially right triangles. In a right triangle, the basic trigonometric functions — sine, cosine, and tangent — relate the angles of the triangle to its sides. These functions are useful tools for finding unknown measurements in triangles. For angle \( \beta \) in our exercise, we used the tangent function, which is defined as the ratio of the opposite side to the adjacent side. That is,
- \[ \tan(\beta) = \frac{\text{opposite}}{\text{adjacent}} \]
Angle calculation
Calculating the angles in a triangle is essential to understanding its geometry. Given the values of the sides and knowing that one angle \( \gamma = 90^{\circ} \) in a right triangle, the other two angles \(\alpha\) and \(\beta\) add up to \(90^{\circ}\). In this exercise, to find angle \(\beta\), we used the arctangent function. This function, denoted as \(\arctan\), is useful for finding an angle when its tangent is known.
- \[ \beta = \arctan(0.785) \approx 38.66^{\circ} \]
Triangle sides
Understanding the sides of a triangle is crucial for solving geometric problems. In a right triangle, there are three sides to consider: two legs and the hypotenuse. Usually, the hypotenuse is the longest side, opposite the right angle. The parts we need to solve for may vary based on what is given.In this exercise, side \(a\) is one leg, with a length of \(0.42\), and \(c\) is the hypotenuse at \(0.68\). We needed to find the length of the other leg, \(b\). By using the Pythagorean theorem, we found \(b\approx 0.535\). Parsing through triangle side lengths using these methods ensures precise calculations, anchoring further explorations into angle measures and triangle properties.
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