Problem 16
Question
Exer. 15-16: Consider any eight points such that no three are collinear. How many triangles are determined?
Step-by-Step Solution
Verified Answer
56 triangles can be formed.
1Step 1: Understand the Problem
We have 8 points on a plane, where no three points are in a straight line (collinear). We need to determine how many unique triangles can be formed using these points.
2Step 2: Identify Formula for Combinations
To find the number of triangles, we use the combination formula to choose 3 points from the 8 available points. The combination formula for choosing r items from n items is given by \( \binom{n}{r} \).
3Step 3: Apply Combination Formula
Since we're choosing 3 points to form a triangle, we use \( n = 8 \) and \( r = 3 \). The formula is: \[ \binom{8}{3} = \frac{8!}{3!(8-3)!} \].
4Step 4: Calculate Factorials
Calculate the required factorials: - \( 8! = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \)- \( 3! = 3 \times 2 \times 1 \)- \( (8-3)! = 5! = 5 \times 4 \times 3 \times 2 \times 1 \)
5Step 5: Perform Division
Simplify the expression: \[ \binom{8}{3} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} \] Calculate step by step: - Numerator: \( 8 \times 7 \times 6 = 336 \)- Denominator: \( 3 \times 2 \times 1 = 6 \)- Division: \( 336 \div 6 = 56 \)
6Step 6: Conclusion
Therefore, the number of triangles that can be formed is 56.
Key Concepts
TrianglesCombination FormulaFactorials
Triangles
Triangles are three-sided polygons, which means they have three edges and three vertices. Forming a triangle requires selecting three points that will act as the vertices of the triangle. In this particular problem, we have eight points on a plane, and no three of them are in a straight line, which is a condition that ensures each set of three points selected will form a triangle.
Understanding this is crucial because if three points were collinear (on a single straight line), they wouldn't form the expected triangle. Therefore, when considering combinatorics and triangle formation, always ensure that no three points are collinear to meet the triangle's criteria.
Triangles are fundamental figures in geometry and have properties like angles summing up to 180 degrees. They serve several purposes in mathematics, engineering, architecture, and many other fields.
Understanding this is crucial because if three points were collinear (on a single straight line), they wouldn't form the expected triangle. Therefore, when considering combinatorics and triangle formation, always ensure that no three points are collinear to meet the triangle's criteria.
Triangles are fundamental figures in geometry and have properties like angles summing up to 180 degrees. They serve several purposes in mathematics, engineering, architecture, and many other fields.
Combination Formula
The combination formula is a mathematical way to determine the number of ways to choose a subset of items from a larger set. It is particularly useful in scenarios like determining how many triangles can be formed from a given set of points.
The general combination formula is represented as \( \binom{n}{r} \) and is read as \( n \) choose \( r \). Here, \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose.
The formula is expressed as:
The general combination formula is represented as \( \binom{n}{r} \) and is read as \( n \) choose \( r \). Here, \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose.
The formula is expressed as:
- \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \)
Factorials
Factorials are an essential concept in combinatorics, especially when using the combination formula. The factorial of a non-negative integer \( n \) is denoted by \( n! \), and it's the product of all positive integers less than or equal to \( n \).
For example:
For example:
- \( 3! = 3 \times 2 \times 1 = 6 \)
- \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \)
- \( 8! = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 40320 \)
Other exercises in this chapter
Problem 16
Find all possible values of \(r\) for a geometric sequence with the two given terms. $$a_{3}=4, a_{7}=\frac{1}{4}$$
View solution Problem 16
If \(O\left(E^{\prime}\right)\) are 7 to 3 , find \(O(E)\) and \(P(E)\).
View solution Problem 16
Rewrite as an expression that does not contain factorials. $$ \frac{(3 n+1) !}{(3 n-1) !} $$
View solution Problem 16
Determine the number of positive integers less than 10,000 that can be formed from the digits \(1,2,3\), and 4 if repetitions are allowed.
View solution