Problem 16
Question
Exer. 13-20: Express the interval as an inequality in the variable \(x\). $$ (3,7) $$
Step-by-Step Solution
Verified Answer
\(3 < x < 7\)
1Step 1: Understanding the Interval Notation
The interval notation \((3, 7)\) indicates an open interval. This means that the interval includes all numbers between 3 and 7, but not the endpoints 3 and 7 themselves.
2Step 2: Writing the Inequality
Since the interval is open and does not include the endpoints, it can be expressed as an inequality: \(3 < x < 7\). This inequality indicates that \(x\) is greater than 3 and less than 7.
Key Concepts
Understanding Open IntervalsExploring Interval NotationExpressing Intervals as Inequalities
Understanding Open Intervals
An open interval is a way to describe a set of numbers between two endpoints, without including the endpoints themselves. It's like saying, "Think about numbers between two points, but don't count the end numbers." For example, the open interval
- \((3, 7)\) includes numbers like 4, 5.5, and 6.9, but not 3 or 7.
Exploring Interval Notation
Interval notation is a mathematical shorthand used to represent a set of numbers along the number line. It is a concise, visually clear way to display a range of values. Here's what you need to know about interval notation:
- Parentheses \((\) and \()\) are used for open intervals. This indicates the endpoints are not included in the set.
- Square brackets \([\) and \()]\) are used for closed intervals, where endpoints are included.
- An interval can also be half-open (or half-closed): one end is included, the other is not. For instance, \([3, 7)\).
Expressing Intervals as Inequalities
One fundamental skill in math is translating between different ways of expressing the same idea, such as going from interval notation to inequalities. When you perform this translation, you help clarify what numbers belong to a set. Let's look at how we do this:
- For the open interval \((3, 7)\), we don't include the 3 and 7. This translates to the inequality \(3 < x < 7\).
- If the interval had been closed, say \([3, 7]\), the corresponding inequality would be \(3 \leq x \leq 7\).
Other exercises in this chapter
Problem 16
Solve the equation. $$\frac{3}{y}+\frac{6}{y}-\frac{1}{y}=11$$
View solution Problem 16
Exer. 1-40: Solve the inequality, and express the solutions in terms of intervals whenever possible. $$ 25 x^{2}-9 x
View solution Problem 16
Exer. 1-50: Solve the equation. $$ \sqrt[3]{6-s^{2}}+5=0 $$
View solution Problem 16
Exer. 1-34: Write the expression in the form \(a+b i\), where \(a\) and \(b\) are real numbers. (a) \(i^{92}\) (b) \(i^{-33}\)
View solution