Problem 16
Question
Evaluate. (Be sure to check by differentiating!) $$ \int x^{3} e^{x^{4}} d x $$
Step-by-Step Solution
Verified Answer
The antiderivative is \( \frac{1}{4} e^{x^4} + C \).
1Step 1: Identify the Substitution
This integral can be solved using substitution. Notice the function inside the integral is composed: the exponent of the exponential term is a function of the variable of integration. We can set the inside function of the exponent as a new variable. Let \( u = x^4 \). Then, we find its differential: \( du = 4x^3 dx \). This substitution will help simplify the integral.
2Step 2: Solve for dx
We need to express \( dx \) in terms of \( du \) and \( x \) so we can change the variable in our integral. From \( du = 4x^3 dx \), we can solve for \( dx \) as follows:\[ dx = \frac{du}{4x^3} \].
3Step 3: Substitute and Simplify
Substitute \( u = x^4 \) and \( dx = \frac{du}{4x^3} \) into the integral. Notice \( x^3 \) in the original integral cancels with \( x^3 \) from \( dx \):\[ \int x^3 e^{x^4} dx = \int x^3 \cdot e^u \cdot \frac{du}{4x^3} = \frac{1}{4} \int e^u du \].
4Step 4: Integrate with Respect to u
Now integrate \( \frac{1}{4} \int e^u du \). The integral of \( e^u \) with respect to \( u \) is \( e^u \), so:\[ \frac{1}{4} \int e^u du = \frac{1}{4} e^u + C \].
5Step 5: Back-Substitute for x
Now substitute back \( u = x^4 \) to express the antiderivative in terms of \( x \):\[ \frac{1}{4} e^{x^4} + C \]. This is the function that when differentiated, should give the original integrand.
6Step 6: Verify by Differentiating
Differentiate the antiderivative \( \frac{1}{4} e^{x^4} + C \) with respect to \( x \). Apply the chain rule: the derivative of \( e^{x^4} \) is \( e^{x^4} \cdot 4x^3 \).\[ \frac{d}{dx} \left( \frac{1}{4} e^{x^4} \right) = \frac{1}{4} \cdot e^{x^4} \cdot 4x^3 = x^3 e^{x^4} \]. This matches the original integrand, confirming our solution is correct.
Key Concepts
Substitution MethodExponential IntegrationDifferentiation Verification
Substitution Method
The Substitution Method is a powerful tool in integration, particularly useful when dealing with composite functions. In the given exercise, we face the challenge of integrating a complex exponential function. The trick is to simplify it by substituting a part of the function with a new variable.
Given the integral \( \int x^3 e^{x^4} dx \), we notice the exponent \( x^4 \) as the inner function. By setting \( u = x^4 \), we target this complexity for simplification. But don't stop there; we also need to transform the differential, which is found as \( du = 4x^3 dx \).
Here's how you can approach substitution:
Given the integral \( \int x^3 e^{x^4} dx \), we notice the exponent \( x^4 \) as the inner function. By setting \( u = x^4 \), we target this complexity for simplification. But don't stop there; we also need to transform the differential, which is found as \( du = 4x^3 dx \).
Here's how you can approach substitution:
- Identify the inner function and set it as \( u \).
- Compute \( du \) to reflect the change in the differential.
- Substitute both \( u \) and \( dx \) back into the integral, simplifying wherever possible.
Exponential Integration
When you encounter an exponential function within an integral, it's crucial to recall the simplicity of integrating exponential expressions. The exponential function \( e^x \) is distinct because it has the same form when integrated as when differentiated.
In our substituted integral \( \frac{1}{4} \int e^u du \), we leverage this property. The integral of \( e^u \) is simply \( e^u \) itself. Thus, the solution becomes:
In our substituted integral \( \frac{1}{4} \int e^u du \), we leverage this property. The integral of \( e^u \) is simply \( e^u \) itself. Thus, the solution becomes:
- Integrate \( e^u \) to get \( e^u \).
- Don't forget to incorporate the scale factor, here \( \frac{1}{4} \), into the integral.
- Reincorporate back the constant \( C \), which represents an indefinite integral.
Differentiation Verification
Verification through differentiation is a crucial step to ensure the accuracy of your integral's solution. Here, it serves as a check to confirm that our antiderivative indeed reflects the original integrand.
For our exercise, the antiderivative \( \frac{1}{4} e^{x^4} + C \) is derived, and we differentiate it to validate our work:
For our exercise, the antiderivative \( \frac{1}{4} e^{x^4} + C \) is derived, and we differentiate it to validate our work:
- Apply the chain rule: the derivative of \( e^{x^4} \) involves multiplying by the derivative of \( x^4 \), which is \( 4x^3 \).
- Thus, differentiate \( \frac{1}{4} e^{x^4} \) to get \( \frac{1}{4} \times e^{x^4} \times 4x^3 \).
- Simplify to find \( x^3 e^{x^4} \), which matches our initial integrand.
Other exercises in this chapter
Problem 15
Find the area of the region bounded by the graphs of the given equations. $$ y=x, y=x^{3}, x=0, x=1 $$
View solution Problem 16
Express \(\sum_{i=1}^{4} g\left(x_{i}\right)\) without using summation notation.
View solution Problem 16
Evaluate using integration by parts or substitution. (Assume \(u>0\) in \(\ln\) u. Check by differentiating. $$ \int(x+1) \ln x d x $$
View solution Problem 16
Find each integral. $$ \int \sqrt[3]{x^{2}} d x $$
View solution