Problem 16
Question
Eliminate the parameter from the given set of parametric equations and obtain
a rectangular equation that has the same graph.
$$
x=\tan t, y=\sec t,-\pi / 2
Step-by-Step Solution
Verified Answer
The rectangular equation is \\(y^2 = 1 + x^2\\).
1Step 1: Introduce Trigonometric Identity
Use the trigonometric identity \(1 + \tan^2 t = \sec^2 t\) to relate \(x\) and \(y\) without the parameter \(t\). This identity will help us eliminate the parameter.
2Step 2: Substitute for Trigonometric Functions
Knowing that \(x = \tan t\) and \(y = \sec t\), it follows that \(1 + x^2 = y^2\) from the trigonometric identity. Here, we directly substitute \(\tan t\) and \(\sec t\) with \(x\) and \(y\) respectively.
3Step 3: Formulate Rectangular Equation
The relationship \(1 + x^2 = y^2\) is a rectangular equation that represents the curve without the parameter \(t\). This equation is now in terms of \(x\) and \(y\) only.
Key Concepts
Trigonometric IdentitiesRectangular EquationEliminating Parameters
Trigonometric Identities
Trigonometric identities are equations that are true for all values of the variables involved. They are essential tools in mathematics, especially in trigonometry and calculus, since they allow us to simplify expressions and solve equations. In this exercise, we used a specific identity:
It's also important to understand that these identities are not just random formulas; they are derived from the Pythagorean identity \(\sin^2 t + \cos^2 t = 1\). By dividing each term by \(\cos^2 t\), you get the identity we used above. Recognizing and applying these identities correctly helps in transforming and solving trigonometric problems efficiently.
- \(1 + \tan^2 t = \sec^2 t\)
It's also important to understand that these identities are not just random formulas; they are derived from the Pythagorean identity \(\sin^2 t + \cos^2 t = 1\). By dividing each term by \(\cos^2 t\), you get the identity we used above. Recognizing and applying these identities correctly helps in transforming and solving trigonometric problems efficiently.
Rectangular Equation
A rectangular equation, also known as a Cartesian equation, expresses the relationship between two variables in a coordinate plane without using a parameter. It uses the standard \(x\) and \(y\) coordinates, which are familiar from graphing in algebra.
In this exercise, we started with the parametric equations \(x = \tan t\) and \(y = \sec t\). We then used the trigonometric identity to eliminate the parameter \(t\), allowing us to combine these into a rectangular equation:
Understanding rectangular equations is important because they provide a straightforward way to visualize functions and plot graphs, aiding in the comprehension of the relationships between variables. They are the backbone of geometry in the coordinate plane, portraying how changes in one variable affect another.
In this exercise, we started with the parametric equations \(x = \tan t\) and \(y = \sec t\). We then used the trigonometric identity to eliminate the parameter \(t\), allowing us to combine these into a rectangular equation:
- \(1 + x^2 = y^2\)
Understanding rectangular equations is important because they provide a straightforward way to visualize functions and plot graphs, aiding in the comprehension of the relationships between variables. They are the backbone of geometry in the coordinate plane, portraying how changes in one variable affect another.
Eliminating Parameters
Eliminating parameters is the process of removing a parameter from parametric equations to obtain a single equation that relates the other variables directly. This is done to simplify the expression and transition from a parametric form to a more intuitive one, like the rectangular form.
In our example, the parametric equations involved \(x = \tan t\) and \(y = \sec t\). By using the identity \(1 + \tan^2 t = \sec^2 t\), we were able to eliminate the parameter \(t\). The identity allowed us to express \(y^2\) in terms of \(x^2\) as
Parameter elimination is a key technique in calculus and algebra since it simplifies the analysis of curves and functions by removing the intermediary parameter. This approach offers a direct pathway to visualize data, making it possible to plot and interpret the function on a standard \(xy\)-graph. Plus, it often simplifies equations, making it easier to analyze and solve them.
In our example, the parametric equations involved \(x = \tan t\) and \(y = \sec t\). By using the identity \(1 + \tan^2 t = \sec^2 t\), we were able to eliminate the parameter \(t\). The identity allowed us to express \(y^2\) in terms of \(x^2\) as
- \(1 + x^2 = y^2\)
Parameter elimination is a key technique in calculus and algebra since it simplifies the analysis of curves and functions by removing the intermediary parameter. This approach offers a direct pathway to visualize data, making it possible to plot and interpret the function on a standard \(xy\)-graph. Plus, it often simplifies equations, making it easier to analyze and solve them.
Other exercises in this chapter
Problem 16
Find the rectangular coordinates for each point with the given polar coordinates. $$ (-1,7 \pi / 4) $$
View solution Problem 16
Convert the polar equation to a rectangular equation. Use the rectangular equation to verify that the focus of the conic is at the origin. $$ r=\frac{1}{1-\cos
View solution Problem 17
Find the rectangular coordinates for each point with the given polar coordinates. $$ (-6,-\pi / 3) $$
View solution Problem 17
Find a polar equation of the conic with focus at the origin that satisfies the given conditions. $$ e=1, \operatorname{directrix} x=3 $$
View solution