Problem 16
Question
Each of the following problems refers to triangle \(A B C\). $$ \text { If } a=3.7 \mathrm{~m}, c=6.4 \mathrm{~m} \text {, and } B=33^{\circ} \text {, find } b \text {. } $$
Step-by-Step Solution
Verified Answer
The length of side \( b \) is approximately \( 3.86 \, \text{m} \).
1Step 1: Identify known values
Firstly, recognize what values are given in the problem. We know that \( a = 3.7 \, \text{m} \), \( c = 6.4 \, \text{m} \), and angle \( B = 33^{\circ} \). We are tasked with finding side \( b \).
2Step 2: Use the Law of Cosines formula
Since we have two sides and the included angle, we can use the law of cosines to find the missing side. The formula is \( b^2 = a^2 + c^2 - 2ac \cdot \cos(B) \).
3Step 3: Plug in the known values
Substitute the known values into the equation: \[ b^2 = (3.7)^2 + (6.4)^2 - 2 \cdot 3.7 \cdot 6.4 \cdot \cos(33^{\circ}) \]
4Step 4: Calculate the expression
First, calculate each part step-by-step:1. \( 3.7^2 = 13.69 \)2. \( 6.4^2 = 40.96 \)3. Both terms combined: \( 13.69 + 40.96 = 54.65 \)Calculate \( 2 \cdot 3.7 \cdot 6.4 \cdot \cos(33^{\circ}) \) using cosine:1. \( 2 \cdot 3.7 \cdot 6.4 = 47.36 \)2. Multiply by \( \cos(33^{\circ}) \approx 0.8387 \)3. \( 47.36 \cdot 0.8387 \approx 39.72 \) (rounded to two decimal places)
5Step 5: Solve for \( b^2 \) and \( b \)
Subtract the products from our previous steps: \[ 54.65 - 39.72 = 14.93 \]Thus, \( b^2 = 14.93 \). Now, take the square root to find \( b \): \[ b = \sqrt{14.93} \approx 3.86 \]
6Step 6: Conclude with the value of \( b \)
The length of side \( b \) is approximately \( 3.86 \, \text{m} \).
Key Concepts
Trigonometry: Understanding the BasicsTriangle Calculations: Using the Law of CosinesAngle-Side Relationships in Triangles
Trigonometry: Understanding the Basics
Trigonometry is a branch of mathematics that explores the relationships between the sides and angles of triangles. At its core, trigonometry is about connecting geometric problems to algebra and calculus. This involves mixing shapes and measurements with numbers and formulas. Three main functions in trigonometry—sine, cosine, and tangent—relate angles of a triangle to side lengths. These functions are the foundation of many formulas used in trigonometry today.
- Sine (sin) relates the angle to the opposite side divided by the hypotenuse.
- Cosine (cos) involves the adjacent side and the hypotenuse.
- Tangent (tan) is the ratio of the opposite side over the adjacent side.
Triangle Calculations: Using the Law of Cosines
Calculating unknown measurements in triangles often involves strategic use of various mathematical laws and formulas. The Law of Cosines is particularly useful in cases where traditional right-angled trigonometry is not applicable. This makes it great for dealing with scalene triangles where all sides and angles are different.
The formula for the Law of Cosines is given as:\[ b^2 = a^2 + c^2 - 2ac \cdot \cos(B) \]
The formula for the Law of Cosines is given as:\[ b^2 = a^2 + c^2 - 2ac \cdot \cos(B) \]
- This works similarly to the Pythagorean Theorem but with a twist—the inclusion of the angle's cosine.
- We apply it when we know two sides and their included angle or three sides.
Angle-Side Relationships in Triangles
Understanding the fundamental relationships between angles and sides is critical for solving problems involving triangles. These relationships form the building blocks of many concepts in geometry and trigonometry. In any triangle, the sum of interior angles always equals 180 degrees; however, it's how these angles relate to the sides that becomes truly interesting.
- In scalene triangles, where all sides and angles differ, the largest angle will always be opposite the longest side.
- Similarly, the smallest angle is opposite the shortest side.
Other exercises in this chapter
Problem 15
Find all solutions to each of the following triangles: \(C=27^{\circ} 50^{\prime}, c=347 \mathrm{~m}, b=425 \mathrm{~m}\)
View solution Problem 16
For each pair of vectors, find \(\mathbf{U} \cdot \mathbf{V}\). \(\mathbf{U}=6 \mathbf{i}, \mathbf{V}=-8 \mathbf{j}\)
View solution Problem 16
Draw the vector \(\mathbf{V}\) that goes from the origin to the given point. Then write \(\mathbf{V}\) in component form \(\langle a, b\rangle\). $$(5,-5)$$
View solution Problem 16
Find all solutions to each of the following triangles: \(C=51^{\circ} 30^{r}, c=707 \mathrm{~m}, b=821 \mathrm{~m}\)
View solution