Problem 16
Question
Determine the GCF of all the terms. $$ 12 x 3,4 x 2,6 x $$
Step-by-Step Solution
Verified Answer
The GCF of the terms is \(2x\).
1Step 1: Understand the Problem
We need to find the greatest common factor (GCF) of the numbers 12, 4, and 6, and the common factor including the variable in the terms that contain "\(x\)".
2Step 2: Break Down Numerical Part
Identify the numerical part of each term: 12, 4, and 6. We'll find the GCF of these numbers.
3Step 3: Find Prime Factorization
Prime factorize each number: 12 is \(2^2 \times 3\), 4 is \(2^2\), and 6 is \(2 \times 3\).
4Step 4: Identify Common Factors
Identify the smallest power of each common prime factor. The common factor is \(2^1\), as all numbers share at least one 2.
5Step 5: Determine GCF of Numbers
The GCF for 12, 4, and 6 is 2, since it is the highest number that divides all of them.
6Step 6: Consider Variable Terms
Identify the \(x\) terms: \(x^3\), \(x^2\), and \(x\). The lowest power of \(x\) is \(x^1\).
7Step 7: Combine Numerical and Variable GCF
The GCF of the full expression includes both the numerical part and the variables. Thus, it is \(2x\).
Key Concepts
Prime FactorizationVariables in AlgebraNumerical CoefficientsElementary Algebra
Prime Factorization
Prime factorization is a process where we break down a number into its prime numbers. A prime number is a number greater than 1 with no divisors other than 1 and itself. By breaking numbers into prime factors, we can easily spot common factors among different numbers.
In the given problem, we have three numbers: 12, 4, and 6. Let's look into how we break each into its prime components:
In the given problem, we have three numbers: 12, 4, and 6. Let's look into how we break each into its prime components:
- 12 can be expressed as \(2^2 \times 3\)
- 4 can be expressed as \(2^2\)
- 6 can be expressed as \(2 \times 3\)
Variables in Algebra
In algebra, variables are symbols, typically letters, used to represent numbers. They allow for general solutions and expressing relationships mathematically. In this specific scenario, we're dealing with the variable \(x\), which appears in different powers.
The terms given in the exercise include:
The terms given in the exercise include:
- \(x^3\) in the first term
- \(x^2\) in the second term
- \(x\) in the third term
Numerical Coefficients
Numerical coefficients are the constant numbers that multiply the variables in algebraic expressions. In the given problem, the coefficients are the numbers that prelude the variable component.
Let's highlight the numerical coefficients in each term:
Let's highlight the numerical coefficients in each term:
- For \(12x^3\), the numerical coefficient is 12
- For \(4x^2\), the numerical coefficient is 4
- For \(6x\), the numerical coefficient is 6
Elementary Algebra
Elementary algebra involves the basic manipulation of algebraic expressions to solve for unknowns. One fundamental aspect is determining common factors, like in this exercise. This step is crucial in simplifying expressions and solving equations efficiently.
Here, to find the GCF of the terms \(12x^3, 4x^2,\) and \(6x\), we break each term into its numerical and variable components. After prime factorizing and identifying the smallest power of the variable, we combine the GCF of numerical and variable parts.
The overall GCF in this exercise is determined to be \(2x\), with 2 coming from the coefficients and \(x\) from the variables. Understanding and applying elementary algebra helps bring clarity and structure to solving such problems.
Here, to find the GCF of the terms \(12x^3, 4x^2,\) and \(6x\), we break each term into its numerical and variable components. After prime factorizing and identifying the smallest power of the variable, we combine the GCF of numerical and variable parts.
The overall GCF in this exercise is determined to be \(2x\), with 2 coming from the coefficients and \(x\) from the variables. Understanding and applying elementary algebra helps bring clarity and structure to solving such problems.
Other exercises in this chapter
Problem 16
Factor completely. $$ 3 x 5-81 x 2 $$
View solution Problem 16
Solve. $$ (x+58)(x-38)=0 $$
View solution Problem 16
Factor. $$ 6 x 2-19 x-10 $$
View solution Problem 17
The product of two consecutive positive odd integers is equal to 1 less than seven times the sum of the integers. Find the integers.
View solution