Problem 16
Question
Describe the locus of points \(P(x, y, z)\) that satisfy the given equation(s). $$ x^{2}+y^{2}+z^{2}=0 $$
Step-by-Step Solution
Verified Answer
The locus of points is the origin, (0, 0, 0).
1Step 1: Understanding the Equation
The equation given is a sphere's equation in three-dimensional space: \(x^2 + y^2 + z^2 = 0\). A typical sphere equation is \(x^2 + y^2 + z^2 = r^2\), where \(r\) is the radius and \((0,0,0)\) is the center of the sphere. In this case, \(r^2 = 0\).
2Step 2: Analyzing the Radius
Since \(r^2 = 0\), the radius \(r\) is 0. A sphere with a zero radius means that all the points satisfying the equation \(x^2 + y^2 + z^2 = 0\) must lie on a single point.
3Step 3: Identifying the Point
If \(x^2 + y^2 + z^2 = 0\), each of the terms \(x^2\), \(y^2\), and \(z^2\) must also be zero because they are squares of real numbers. Thus, \(x=0\), \(y=0\), and \(z=0\).
4Step 4: Describing the Locus
The locus of points \(P(x, y, z)\) that satisfy \(x^2 + y^2 + z^2 = 0\) is the single point (0, 0, 0). This point is often referred to as the origin in three-dimensional space.
Key Concepts
Three-Dimensional SpaceSphere EquationOrigin Point
Three-Dimensional Space
Three-dimensional space is the world we inhabit, consisting of three axes that define a location: the x-axis, y-axis, and z-axis. This three-dimensional coordinate system helps us locate points in space using a triplet of values \(x, y, z\). Each axis represents a dimension: \(x\) for width, \(y\) for height, and \(z\) for depth.
In math, especially when dealing with geometry and algebra, this space allows us to express points, vectors, shapes, and lines in a more comprehensive manner compared to two-dimensional space.
In math, especially when dealing with geometry and algebra, this space allows us to express points, vectors, shapes, and lines in a more comprehensive manner compared to two-dimensional space.
- Points in three-dimensional space can be described using coordinates like \( (x, y, z) \).
- Lines and planes can also be defined through equations involving these three variables.
- The concept of distance and location in this space combines these three dimensions.
Sphere Equation
The general equation of a sphere in three-dimensional space is \(x^2 + y^2 + z^2 = r^2\). This formula represents a sphere centered at the origin \( (0, 0, 0) \) with a radius \(r\). A sphere can be thought of as all points in space that are equidistant from a central point.
In the exercise, the sphere equation simplifies to \(x^2 + y^2 + z^2 = 0\), indicating a special case. When the radius \(r\) becomes zero, it implies that the sphere collapses into a single point, which is the center of the sphere itself.
In the exercise, the sphere equation simplifies to \(x^2 + y^2 + z^2 = 0\), indicating a special case. When the radius \(r\) becomes zero, it implies that the sphere collapses into a single point, which is the center of the sphere itself.
- In this simplified sphere equation, the locus of points is reduced to the point \( (0, 0, 0) \), instead of an expanding surface of a normal sphere.
- Mathematically, each squared term \(x^2, y^2, z^2\) must be zero to satisfy the equation, necessitating that \(x = 0\), \(y = 0\), and \(z = 0\).
Origin Point
The origin point in three-dimensional space is represented by coordinates \( (0,0,0) \). It serves as the central reference point for this space and lies at the intersection of the x, y, and z axes.
In mathematics, particularly in algebra and geometry, the origin is pivotal in analyzing and interpreting three-dimensional objects and their properties.
In mathematics, particularly in algebra and geometry, the origin is pivotal in analyzing and interpreting three-dimensional objects and their properties.
- It acts as the fixed zero-point from which other points or vectors can be measured.
- The origin is crucial for defining symmetries, rotations, and transformations in space.
- In our exercise, the locus described by the sphere equation \(x^2 + y^2 + z^2 = 0\) identifies precisely the origin point, illustrating its significance as the anchor of this geometrical representation.
Other exercises in this chapter
Problem 16
The given vectors span a subspace \(W\) of \(R^{4}\). Use the Gram-Schmidt orthogonalization process to construct an orthonormal basis for the subspace. $$ \mat
View solution Problem 16
Determine a scalar \(c\) so that the given vectors are orthogonal. (a) \(\mathbf{a}=2 \mathbf{i}-c \mathbf{j}+3 \mathbf{k}, \mathbf{b}=3 \mathbf{i}+2 \mathbf{j}
View solution Problem 16
Find the vector \(P_{1} P_{2}\). Graph \(P_{1} P_{2}\) and its corresponding position vector. \(P_{1}(-2,-1), P_{2}(4,-5)\)
View solution Problem 17
In Problems \(17-20\), determine whether the given set is a subspace of the indicated vector space. Polynomials of the form \(p(x)=c_{3} x^{3}+c_{1} x ; P_{3}\)
View solution