Problem 16
Question
Choose a method and solve the quadratic equation. Explain your choice. $$ x^{2}-9=0 $$
Step-by-Step Solution
Verified Answer
The solutions to the equation are \(x = 3\) and \(x = -3\).
1Step 1: Identify the Equation Type
Recognize that the equation \(x^{2} - 9 = 0\) can be seen as a perfect square. That is to say, we could express it as \(x^{2} - 3^{2} = 0\).
2Step 2: Apply the Difference of Squares Formula
To solve this type of equations, we can apply the difference of squares formula: \(a^{2} - b^{2} = (a - b)(a + b)\). Applying this formula here gives: \(x^{2} - 3^{2} = (x - 3)(x + 3)\). Therefore, the equation can be rewritten as \( (x - 3)(x + 3) = 0\).
3Step 3: Solve for x
We now have two simple equations to solve: x - 3 = 0 and x + 3 = 0. Solving these for x gives us x = 3 and x = -3.
Other exercises in this chapter
Problem 16
USING THE PYTHAGOREAN THEOREM Find the missing length of the right triangle if \(a\) and \(b\) are the lengths of the legs and \(c\) is the length of the hypote
View solution Problem 16
Find the midpoint of the line segment connecting the given points. \((0,0),(0,8)\)
View solution Problem 16
Rewrite the expression using radical notation. $$ 10^{3 / 2} $$
View solution Problem 16
Simplify the expression. $$ 2 \sqrt{6}-\sqrt{6} $$
View solution