Problem 16
Question
Assume that the vectors \(\mathbf{a}, \mathbf{b}, \mathbf{c},\) and \(\mathbf{d}\) are defined as follows: $$\mathbf{a}=\langle 2,3\rangle \quad \mathbf{b}=\langle 5,4\rangle \quad \mathbf{c}=\langle 6,-1\rangle \quad \mathbf{d}=\langle-2,0\rangle$$ Compute each of the indicated quantities. $$-2 c+2 d$$
Step-by-Step Solution
Verified Answer
The result is \(\langle -16, 2 \rangle\).
1Step 1: Scale Vector c
Given vector \( \mathbf{c} = \langle 6, -1 \rangle \), scale it by \(-2\). The result is: \(-2 \cdot \mathbf{c} = -2 \cdot \langle 6, -1 \rangle = \langle -12, 2 \rangle\).
2Step 2: Scale Vector d
Given vector \( \mathbf{d} = \langle -2, 0 \rangle \), scale it by \(2\). The result is: \(2 \cdot \mathbf{d} = 2 \cdot \langle -2, 0 \rangle = \langle -4, 0 \rangle\).
3Step 3: Add Scaled Vectors
Add the results of the scaled vectors from Steps 1 and 2: \(\langle -12, 2 \rangle + \langle -4, 0 \rangle = \langle -12 + (-4), 2 + 0 \rangle = \langle -16, 2 \rangle\).
Key Concepts
Scaling VectorsVector AdditionLinear CombinationsCoordinate Geometry
Scaling Vectors
Scaling vectors is like stretching or shrinking them. Imagine a vector as an arrow in a two-dimensional plane that shows both a direction and a length (magnitude). To scale a vector, you multiply each of its components by a number, known as the scalar. This action changes the length of the vector without altering its direction, unless you scale by a negative number, which also inverts the direction.
For example, if we have a vector \( \mathbf{v} = \langle x, y \rangle \) and we scale it by a scalar \( k \), the new vector is \( k \cdot \mathbf{v} = \langle kx, ky \rangle \).
For example, if we have a vector \( \mathbf{v} = \langle x, y \rangle \) and we scale it by a scalar \( k \), the new vector is \( k \cdot \mathbf{v} = \langle kx, ky \rangle \).
- Scaling by a positive number keeps the direction the same but changes the length.
- Scaling by a negative number changes both the direction and the length.
Vector Addition
Vector addition is the process of combining two or more vectors to get a new vector. The method is straightforward: you add corresponding components together.
For instance, if we have two vectors \( \mathbf{v} = \langle v_1, v_2 \rangle \) and \( \mathbf{u} = \langle u_1, u_2 \rangle \), their sum \( \mathbf{v} + \mathbf{u} \) is given by \( \langle v_1 + u_1, v_2 + u_2 \rangle \).
For instance, if we have two vectors \( \mathbf{v} = \langle v_1, v_2 \rangle \) and \( \mathbf{u} = \langle u_1, u_2 \rangle \), their sum \( \mathbf{v} + \mathbf{u} \) is given by \( \langle v_1 + u_1, v_2 + u_2 \rangle \).
- Add the x-components from each vector.
- Add the y-components from each vector.
Linear Combinations
A linear combination involves using scaling and addition together to form a new vector from existing ones. This is a vital concept in linear algebra and vector geometry.
Suppose you have vectors \( \mathbf{u} \) and \( \mathbf{v} \), and scalars \( a \) and \( b \). The linear combination is expressed as \( a\mathbf{u} + b\mathbf{v} \). This combines the effects of scaling vectors with scalar multiplication and then adding them together to create a new vector.
Generally, a linear combination can be used to express any vector in a plane if enough independent vectors are given. This is powerful in terms of determining spans and understanding dimensions. In our specific exercise, we have formed a linear combination of vectors \( \mathbf{c} \) and \( \mathbf{d} \) by scaling them with \(-2\) and \(2\), respectively, and then adding the results: \(-2\mathbf{c} + 2\mathbf{d} = \langle -16, 2 \rangle\). Linear combinations are essential to form new vectors and determine relationships within vector spaces.
Suppose you have vectors \( \mathbf{u} \) and \( \mathbf{v} \), and scalars \( a \) and \( b \). The linear combination is expressed as \( a\mathbf{u} + b\mathbf{v} \). This combines the effects of scaling vectors with scalar multiplication and then adding them together to create a new vector.
Generally, a linear combination can be used to express any vector in a plane if enough independent vectors are given. This is powerful in terms of determining spans and understanding dimensions. In our specific exercise, we have formed a linear combination of vectors \( \mathbf{c} \) and \( \mathbf{d} \) by scaling them with \(-2\) and \(2\), respectively, and then adding the results: \(-2\mathbf{c} + 2\mathbf{d} = \langle -16, 2 \rangle\). Linear combinations are essential to form new vectors and determine relationships within vector spaces.
Coordinate Geometry
Coordinate geometry, sometimes referred to as analytic geometry, is how we use algebra in geometry. It enables us to describe geometrical shapes like lines, segments, and shapes using a coordinate system.
Vectors are integral to coordinate geometry as they describe positions and directions within this system. In two-dimensional coordinate systems, such as the Cartesian plane, each point is defined by a pair of coordinates \( (x, y) \). Vectors help in translating and transforming these points across the plane.
Vectors are integral to coordinate geometry as they describe positions and directions within this system. In two-dimensional coordinate systems, such as the Cartesian plane, each point is defined by a pair of coordinates \( (x, y) \). Vectors help in translating and transforming these points across the plane.
- Use vector operations to define and solve geometric problems.
- Visualize vectors as arrows pointing from the origin \((0, 0)\) to a point \((x, y)\).
Other exercises in this chapter
Problem 16
Graph the parametric equations after eliminating the parameter t. Specify the direction on the curve corresponding to increasing values of \(t\). \(t\) is \(0 \
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Graph the polar equations. $$r=1+2 \cos \theta$$
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Assume that the coordinates of the points \(P\) \(Q, R, S,\) and \(O\) are as follows: \(P(-1,3) \quad Q(4,6) \quad R(4,3) \quad S(5,9) \quad O(0,0)\) Draw the
View solution Problem 17
Graph the parametric equations after eliminating the parameter t. Specify the direction on the curve corresponding to increasing values of \(t\). \(t\) is \(0 \
View solution