Problem 16
Question
An inductor used in a dc power supply has an inductance of 12.0 \(\mathrm{H}\) and a resistance of 180\(\Omega .\) It carries a current of 0.300 \(\mathrm{A}\) . (a) What is the energy stored in the magnetic field? (b) At what rate is thermal energy developed in the inductor? (c) Does your answer to part (b) mean that the magnetic-field energy is decreasing with time? Explain.
Step-by-Step Solution
Verified Answer
(a) 0.54 J; (b) 16.2 W; (c) Magnetic-field energy is constant if current is constant.
1Step 1: Energy Stored in the Magnetic Field
To find the energy stored in the magnetic field of the inductor, we use the formula: \( E = \frac{1}{2} L I^2 \), where \( E \) is the energy, \( L \) is the inductance, and \( I \) is the current. Substitute \( L = 12.0 \, \text{H} \) and \( I = 0.300 \, \text{A} \) into the formula:\[ E = \frac{1}{2} \times 12.0 \times (0.300)^2 \]Calculate the energy:\[ E = \frac{1}{2} \times 12.0 \times 0.09 = 0.54 \, \text{J} \] The energy stored in the magnetic field is 0.54 Joules.
2Step 2: Rate of Thermal Energy Development
The rate at which thermal energy is developed in the inductor can be found using the power formula for resistive heating: \( P = I^2 R \), where \( P \) is the power, \( I \) is the current, and \( R \) is the resistance.Substitute \( I = 0.300 \, \text{A} \) and \( R = 180 \, \Omega \) into the formula:\[ P = (0.300)^2 \times 180 \]Calculate the power:\[ P = 0.09 \times 180 = 16.2 \, \text{W} \]The rate at which thermal energy is developed is 16.2 Watts.
3Step 3: Analysis of Magnetic-Field Energy Decrease
The answer to part (b) does not imply that the magnetic-field energy is decreasing. The power calculated in part (b) represents the rate at which electrical energy is converted to thermal energy in the resistor. The energy of the magnetic field remains constant as long as the current is constant. If current doesn't change, the magnetic-field energy will not decrease, since energy loss to heat happens through the resistance.
Key Concepts
InductanceResistanceMagnetic Field EnergyThermal Energy Development
Inductance
Inductance is a fundamental characteristic of an inductor, often denoted by the symbol \( L \). It refers to the ability of the inductor to store energy in the form of a magnetic field when a current passes through it. The larger the inductance, the more energy the inductor can store for a given current. This concept is central to many applications in electronics, such as in power supplies, filters, and transformers. The formula for the energy stored in an inductor’s magnetic field is:
- \( E = \frac{1}{2} L I^2 \)
- \( E \) is the energy in joules (J)
- \( L \) is the inductance in henries (H)
- \( I \) is the current in amperes (A)
Resistance
Resistance is an inherent property of materials to oppose the flow of electric current, measured in ohms (\( \Omega \)). In an inductor, resistance originates from the wire coil used to create the magnetic field. This resistance contributes to power losses in the form of heat, commonly known as resistive heating.The formula that describes the power loss due to resistance in inductors is:
- \( P = I^2 R \)
- \( P \) is the power loss in watts (W)
- \( I \) is the current in amperes (A)
- \( R \) is the resistance in ohms (\( \Omega \))
Magnetic Field Energy
Magnetic field energy in an inductor is the energy stored within its magnetic field when an electric current flows through it. The calculation of magnetic energy is crucial for designing and analyzing circuits that use inductors, like transformers and motors.The energy stored can be calculated using the formula:
- \( E = \frac{1}{2} L I^2 \)
Thermal Energy Development
Thermal energy development in an inductor is the energy converted to heat due to the resistance of the wire coil. When current flows through an inductor’s resistive elements, some of the electrical energy is lost as heat.The rate of thermal energy development can be calculated using:
- \( P = I^2 R \)
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