Problem 16
Question
(a) sketch the curve represented by the parametric equations (indicate the orientation of the curve). Use a graphing utility to confirm your result. (b) Eliminate the parameter and write the corresponding rectangular equation whose graph represents the curve. Adjust the domain of the resulting rectangular equation, if necessary. $$x=3-2 t, y=2+3 t$$
Step-by-Step Solution
Verified Answer
The curve represented by the parametric equations \(x=3-2t, y=2+3t\) is a straight line with negative slope. After eliminating the parameter, we get the rectangular equation \(y=-3/2x+9/2\).
1Step 1: Sketch the curve
The curve can be sketched by plotting a few points. For example, when \(t=0\), we get the point \(x=3\) and \(y=2\). When \(t=1\), we get the point \(x=1\) and \(y=5\) and so on. By plotting these points and connecting them, we can get a sense of the curve. Remember to also indicate the orientation of the curve by drawing arrows showing that the curve is traced out as \(t\) increases.
2Step 2: Confirm your curve with a graphing utility
Using a graphing utility that accepts parametric equations such as Desmos or a graphing calculator, input the equations \(x=3-2t, y=2+3t\) and verify that the plot matches the sketched curve from step one.
3Step 3: Eliminate the parameter
To eliminate the parameter \(t\) from the equations, first solve the equation \(x=3-2t\) for \(t\) to get \(t=(3-x)/2\). Substitute this into the second equation \(y=2+3t\) to get \(y=2+3((3-x)/2)\), which simplifies to \(y=-3/2x+9/2\).
4Step 4: Adjust the domain if necessary
In this case, no adjustment of the domain of the resulting rectangular equation is necessary because the original parameter \(t\) can take any values.
Key Concepts
Rectangular EquationGraphing UtilityCurve Orientation
Rectangular Equation
To move from a parametric equation to a more traditional form, we often eliminate the parameter, typically noted as "t". This conversion results in what is called a rectangular equation. For the given parametric equations, we have:
- \(x = 3 - 2t\)
- \(y = 2 + 3t\)
- \(t = \frac{3 - x}{2}\)
- \(y = 2 + 3\left( \frac{3-x}{2} \right)\)
- This simplifies to \(y = -\frac{3}{2}x + \frac{9}{2}\)
Graphing Utility
Graphing utilities, such as graphing calculators or online tools like Desmos, play an essential role in visualizing mathematical concepts. They allow for confirmation of hand-drawn graphs and provide an interactive way to explore changes in equations.These tools support input for parametric equations—important for verifying sketches obtained manually. Here’s how you can use a graphing utility:
- Enter the parametric equations: \(x = 3 - 2t\) and \(y = 2 + 3t\).
- Set the parameter \(t\) over the interval you are interested in exploring.
- Observe the graph, ensuring that it matches any sketch you initially created manually.
Curve Orientation
Understanding curve orientation is crucial when dealing with parametric equations. When visualizing these curves, the orientation gives you insight into how the curve is traced as the parameter "t" increases.When sketching manually, start by plotting points for various values of \(t\):
- Example: For \(t = 0\), we find point \((3, 2)\).
- For \(t = 1\), the point is \((1, 5)\).
- Draw arrows from point-to-point to indicate the path's direction as \(t\) increases.
Other exercises in this chapter
Problem 16
Identify the type of conic represented by the equation. Use a graphing utility to confirm your result. $$r=\frac{2}{4+\sin \theta}$$
View solution Problem 16
Test for symmetry with respect to the line \(\theta=\pi / 2,\) the polar axis, and the pole. $$r=5+4 \cos \theta$$
View solution Problem 16
Plot the point given in polar coordinates and find three additional polar representations of the point, using \(-2 \pi
View solution Problem 16
Identify the center and radius of the circle. $$x^{2}+(y+8)^{2}=25$$
View solution