Problem 16
Question
A motor turning at \(15 \overline{0} 0\) rpm is fitted with a gear having 60 teeth. Find the speed of the driven gear if it has 40 teeth.
Step-by-Step Solution
Verified Answer
The speed of the driven gear is 1000 rpm.
1Step 1: Understanding Gear Ratio
The gear ratio describes the proportional relationship between the number of teeth on two gears. It determines the relative speed of two gears in a gear train.
2Step 2: Calculate the Gear Ratio
Calculate the gear ratio between the two gears by dividing the number of teeth of the driven gear by the number of teeth of the driving gear: \[\text{Gear ratio} = \frac{40}{60} = \frac{2}{3}\].
3Step 3: Apply the Gear Ratio to Find Output Speed
Use the gear ratio to find the speed of the driven gear by multiplying the speed of the driving gear by the gear ratio: \[\text{Output speed} = 1500 \times \frac{2}{3} = 1000 \text{ rpm}\].
Key Concepts
Understanding Gear TrainsThe Role of Teeth RatioExploring Motor Speed and Its InfluenceApplication of Physics Principles
Understanding Gear Trains
In mechanics, a gear train is an assembly of two or more gears working together to transmit motion and force. These gears engage with each other by their teeth, which transfer rotating motion from one gear to another. Gear trains are fundamental in machinery because they allow us to change the speed, torque, and direction of motion.
- Two connected gears will rotate in opposite directions unless an idler gear is introduced to change this directional relationship.
- Gears in a train rotate at different speeds based on their size and number of teeth, creating a mechanical advantage.
- Applications include everything from clocks, where precise timing is needed, to complex industrial machines.
The Role of Teeth Ratio
The teeth ratio, also known as the gear ratio, is a critical concept when working with gears. This ratio is derived from the number of teeth on the driven gear divided by the number of teeth on the driving gear. It provides insight into how speed and torque are modified by the gears in action.
- A smaller teeth ratio means the driven gear will rotate faster than the driving gear, increasing speed.
- A larger teeth ratio results in the driven gear rotating more slowly, which can multiply the torque output.
- The calculation is straightforward: \( \frac{ \text{Teeth on Driven Gear} }{ \text{Teeth on Driving Gear} }\).
Exploring Motor Speed and Its Influence
Motor speed is the rotational speed at which the motor’s shaft or spindle is turning, usually measured in revolutions per minute (rpm). Motor speed is directly influenced by the electricity supplied and the design characteristics of the motor itself. In any mechanical system, controlling the speed allows for precision in tasks and efficiency in operation.
- In our exercise, the motor rotates at \(1500 \, \text{rpm}\), performing as the driving force.
- By adjusting the gear arrangement, particularly through gear ratios, it can modify the resulting speed or torque as seen on the output or driven gear.
- Maintaining appropriate motor speed is crucial for ensuring the longevity of the machinery and its optimal performance.
Application of Physics Principles
Applied physics encompasses using principles of physics to solve technical challenges, often seen in the engineering realm. In our situation, it applies directly to understanding how gear trains can manipulate power and speed.
- Newton’s laws help us understand motion characteristics, while principles of mechanical advantage are evident in gear operations.
- Understanding torque as it relates to rotational speed and how force is transformed is essential in designing effective gear systems.
- Applying these physics principles allows for designing machinery that can meet specific speed or torque requirements efficiently.
Other exercises in this chapter
Problem 15
A motor turns at a rate of \(11.0\) rev/s. Find its angular speed in rpm.
View solution Problem 16
What size pulley should be placed on a countershaft turning \(15 \overline{0}\) rpm to drive a grinder with a \(12.0-\mathrm{cm}\) pulley that is to turn at \(1
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What power is developed by an engine with torque \(75 \overline{0} \mathrm{~N} \mathrm{~m}\) applied at \(45 \overline{0} 0 \mathrm{rpm} ?\)
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What is the centripetal force on a \(15 \overline{0} 0-\mathrm{kg}\) vehicle driven around a curve of radius \(35.0 \mathrm{~m}\) at \(60.0 \mathrm{~km} / \math
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