Problem 16
Question
13–22 ? Express the statement as an equation. Use the given information to find the constant of proportionality. S varies jointly as \(p\) and \(q .\) If \(p=4\) and \(q=5,\) then \(S=180 .\)
Step-by-Step Solution
Verified Answer
The constant of proportionality is 9; the equation is \( S = 9pq \).
1Step 1: Understand Joint Variation
When a variable varies jointly as two other variables, it means that the variable is proportional to the product of those two variables. Thus, if S varies jointly as p and q, we express it as \( S = kpq \), where \( k \) is the constant of proportionality.
2Step 2: Substitute Known Values
We know from the problem that when \( p = 4 \) and \( q = 5 \), \( S = 180 \). Substitute these values into the equation: \( 180 = k \times 4 \times 5 \).
3Step 3: Solve for the Constant of Proportionality \( k \)
In the equation \( 180 = k \times 4 \times 5 \), simplify and solve for \( k \):\( 180 = 20k \).Divide both sides by 20:\( k = \frac{180}{20} \).Calculate:\( k = 9 \).
4Step 4: Write the Final Equation
With the constant of proportionality \( k = 9 \), the equation expressing the joint variation of \( S \) as \( p \) and \( q \) is \( S = 9pq \).
Key Concepts
Constant of ProportionalityAlgebraic EquationsProportional Relationships
Constant of Proportionality
The constant of proportionality is a key element in describing how quantities are connected in proportional relationships. When we talk about variation, whether it is direct, inverse, or joint, like in this exercise, the constant of proportionality helps us understand how one variable affects another. The constant is typically denoted by the letter "k."
- In joint variation, if a variable like \( S \) varies jointly as \( p \) and \( q \), the equation is \( S = kpq \).
- Here, \( k \) tells us how strongly \( S \) is affected by changes in \( p \) and \( q \) together.
- The constant remains the same for a particular relationship, meaning it doesn't change even if the values of \( p \) or \( q \) change, as long as the relationship holds.
Algebraic Equations
Algebraic equations are the tools we use to solve problems involving unknowns. They serve as the canvas where relationships between different quantities are expressed. In the context of joint variation, algebraic equations convey how a variable depends on two others. Let's break down the process:
- Start by forming the base equation based on the variation type. For joint variation, it is \( S = kpq \).
- Substitute given real values for the variables to find the constant of proportionality \( k \).
- Solve the resulting equation to isolate \( k \), providing you with a full picture of the proportional relationship.
Proportional Relationships
Proportional relationships are foundational concepts in mathematics that describe how variables relate to each other. In a proportional relationship, two quantities increase or decrease at the same rate. Joint variation is a special type where a variable is influenced by the product of two other variables. Let's see how it applies:
- When \( S \) varies jointly with \( p \) and \( q \), it means changes in \( p \) and \( q \) simultaneously affect \( S \).
- This relationship is captured in the equation \( S = kpq \), where \( k \) is found using known values of \( p \), \( q \), and \( S \).
- Once \( k \) is known, the equation can predict \( S \) for any other values of \( p \) and \( q \) that adhere to the same proportional relationship.
Other exercises in this chapter
Problem 15
11–18 ? Find the x- and y-intercepts of the graph of the equation. $$ x^{2}+y^{2}=4 $$
View solution Problem 16
Find an equation of the line that satisfies the given conditions. Through \((-2,4) ; \quad\) slope \(-1\)
View solution Problem 16
Draw the parallelogram with vertices \(A(1,2), B(5,2)\) \(C(3,6),\) and \(D(7,6)\) on a coordinate plane. Find the area of the parallelogram.
View solution Problem 16
Determine an appropriate viewing rectangle for the equation and use it to draw the graph. $$ y=\frac{x}{x^{2}+25} $$
View solution