Problem 16
Question
\(13-18\) Find the first five terms of the given recursively defined sequence. $$ a_{n}=\frac{1}{1+a_{n-1}} \quad \text { and } \quad a_{1}=1 $$
Step-by-Step Solution
Verified Answer
The first five terms are: 1, \(\frac{1}{2}\), \(\frac{2}{3}\), \(\frac{3}{5}\), \(\frac{5}{8}\).
1Step 1: Understand the Recursive Formula and Initial Condition
The sequence is defined recursively with the formula \( a_n = \frac{1}{1 + a_{n-1}} \). This means that each term is calculated based on the previous term. We are also given the starting value (or the first term) of the sequence, \( a_1 = 1 \).
2Step 2: Calculate the Second Term
To find \( a_2 \), use the formula with \( a_1 \): \[ a_2 = \frac{1}{1 + a_1} = \frac{1}{1 + 1} = \frac{1}{2}. \] So, \( a_2 = \frac{1}{2} \).
3Step 3: Calculate the Third Term
Use \( a_2 \) to find \( a_3 \): \[ a_3 = \frac{1}{1 + a_2} = \frac{1}{1 + \frac{1}{2}} = \frac{1}{\frac{3}{2}} = \frac{2}{3}. \] Thus, \( a_3 = \frac{2}{3} \).
4Step 4: Calculate the Fourth Term
Use \( a_3 \) to find \( a_4 \): \[ a_4 = \frac{1}{1 + a_3} = \frac{1}{1 + \frac{2}{3}} = \frac{1}{\frac{5}{3}} = \frac{3}{5}. \] Therefore, \( a_4 = \frac{3}{5} \).
5Step 5: Calculate the Fifth Term
Use \( a_4 \) to find \( a_5 \): \[ a_5 = \frac{1}{1 + a_4} = \frac{1}{1 + \frac{3}{5}} = \frac{1}{\frac{8}{5}} = \frac{5}{8}. \] Hence, \( a_5 = \frac{5}{8} \).
Key Concepts
Sequence OperationsInitial ConditionsRecursive FormulasSequence Terms
Sequence Operations
Sequence operations are essential when dealing with recursively defined sequences. Essentially, each new term in the sequence depends on the calculation involving the previous one. This step-by-step dependency establishes a chain where the understanding and correctness of each part affect the entire sequence.
In the given exercise, our main operation is the recursive formula applied repeatedly to determine each next term. The sequence operation uses the expression \( a_n = \frac{1}{1 + a_{n-1}} \), which defines how each term is generated from the one preceding it. This operation involves division and addition, combined in a specific order:
In the given exercise, our main operation is the recursive formula applied repeatedly to determine each next term. The sequence operation uses the expression \( a_n = \frac{1}{1 + a_{n-1}} \), which defines how each term is generated from the one preceding it. This operation involves division and addition, combined in a specific order:
- Add 1 to the previous term.
- Take the reciprocal of the result.
Initial Conditions
Initial conditions play a crucial role in determining the behavior of a recursive sequence. They serve as the starting point from which all subsequent terms are generated. In other words, they "kick off" the process.
In our example problem, the initial condition is \( a_1 = 1 \). This first term essentially gets the sequence rolling, allowing the recursive formula to build subsequent terms. Initial conditions must be known to apply the sequence operations as they provide the first value needed to begin calculations.
In our example problem, the initial condition is \( a_1 = 1 \). This first term essentially gets the sequence rolling, allowing the recursive formula to build subsequent terms. Initial conditions must be known to apply the sequence operations as they provide the first value needed to begin calculations.
- By using the initial value, we calculate the next term.
- Each subsequent term uses its predecessor to determine its value effectively.
Recursive Formulas
Recursive formulas define the way each term in a sequence is related to one or more of its predecessors. In other words, they provide a rule for moving from one term to the next within the sequence. This makes them a foundational aspect of many mathematical and computational sequences.
For the exercise, the sequence is structured by the recursive formula \( a_n = \frac{1}{1 + a_{n-1}} \). In simpler terms, to find \( a_n \), you use the previous term \( a_{n-1} \): add 1 to it, then take the reciprocal. This formula sets up a pattern that continues indefinitely, producing a chain of values that depends entirely on the succeeding from previous values.
For the exercise, the sequence is structured by the recursive formula \( a_n = \frac{1}{1 + a_{n-1}} \). In simpler terms, to find \( a_n \), you use the previous term \( a_{n-1} \): add 1 to it, then take the reciprocal. This formula sets up a pattern that continues indefinitely, producing a chain of values that depends entirely on the succeeding from previous values.
- A typical recursive sequence must include a base case, the initial condition we already talked about.
- Recursive definitions require a function or rule to determine each term based on the previous ones.
Sequence Terms
Sequence terms are the actual values generated at each step in a recursive sequence, representing the output resulting from applying recursive formulas and operations. They are the backbone of understanding sequences.
In our example, regular application of the recursive formula produces a set of numbers: These are
In our example, regular application of the recursive formula produces a set of numbers: These are
- \( a_1 = 1 \)
- \( a_2 = \frac{1}{2} \)
- \( a_3 = \frac{2}{3} \)
- \( a_4 = \frac{3}{5} \)
- \( a_5 = \frac{5}{8} \)
Other exercises in this chapter
Problem 15
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