Problem 16
Question
11–18 ? Find the x- and y-intercepts of the graph of the equation. $$ y=\sqrt{x+1} $$
Step-by-Step Solution
Verified Answer
The y-intercept is (0, 1) and the x-intercept is (-1, 0).
1Step 1: Find the y-intercept
To find the y-intercept, we set \( x = 0 \) and solve for \( y \). Substituting \( x = 0 \) into the equation \( y = \sqrt{x+1} \), we get:\[ y = \sqrt{0 + 1} = \sqrt{1} = 1 \].Thus, the y-intercept is \((0, 1)\).
2Step 2: Find the x-intercept
To find the x-intercept, we set \( y = 0 \) and solve for \( x \). Substituting \( y = 0 \) into the equation \( 0 = \sqrt{x + 1} \), we square both sides to get:\[ 0^2 = (\sqrt{x+1})^2 \]\[ 0 = x + 1 \]By solving, we find:\[ x = -1 \].Thus, the x-intercept is \((-1, 0)\).
Key Concepts
Understanding the X-InterceptUnderstanding the Y-InterceptGraphing Equations with Intercepts
Understanding the X-Intercept
The x-intercept of a graph is where the graph intersects or crosses the x-axis. At this point, the value of y is always zero. To find the x-intercept, we set the equation equal to zero and solve for x. This means: * Substitute 0 for y in the equation. * Solve for x. In our exercise, the equation given is \( y = \sqrt{x+1} \). When y is set to 0, the equation becomes \[0 = \sqrt{x+1} \]By squaring both sides, we eliminate the square root:\[0 = x+1 \]Solving for x, we subtract 1 from both sides to isolate x, resulting in \( x = -1 \). Therefore, the x-intercept, where the graph touches the x-axis, is at the point (-1, 0). This means when x is -1, y equals 0, confirming our understanding of the x-intercept.
Understanding the Y-Intercept
The y-intercept is the point where the graph intersects the y-axis. At this intersection, the value of x is always zero. To determine the y-intercept, replace x with zero in the equation and solve for y. In the problem at hand, the equation is \( y = \sqrt{x+1} \). By substituting x with 0, we have: \[y = \sqrt{0+1} \]This simplifies to \( y = \sqrt{1} \). Knowing that the square root of 1 is 1, we find \( y = 1 \). Thus, the y-intercept is the point (0, 1) on the graph. This tells us that when x is 0, y equals 1. It's the point where the graph meets the y-axis.
Graphing Equations with Intercepts
Graphing an equation involves plotting it on a coordinate plane. By understanding intercepts, we gain a crucial starting point for graphing any equation efficiently. Intercepts guide us to plot the curve accurately and help visualize the equation.To graph, follow these steps:
- Start by determining the intercepts. As seen, for this equation, they are the x-intercept at (-1, 0) and the y-intercept at (0, 1).
- Plot these intercepts on the coordinate plane.
- Recognize the nature of the function. The equation \( y = \sqrt{x+1} \) is a square root function which indicates a curve that starts from the x-intercept and extends to the first quadrant.
- Draw a smooth curve passing through the intercepts, noting the shape of the curve typical for square root functions.
Other exercises in this chapter
Problem 16
Draw the parallelogram with vertices \(A(1,2), B(5,2)\) \(C(3,6),\) and \(D(7,6)\) on a coordinate plane. Find the area of the parallelogram.
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Determine an appropriate viewing rectangle for the equation and use it to draw the graph. $$ y=\frac{x}{x^{2}+25} $$
View solution Problem 17
Find an equation of the line that satisfies the given conditions. Through \((1,7) ; \quad\) slope \(\frac{2}{3}\)
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13–22 ? Express the statement as an equation. Use the given information to find the constant of proportionality. \(W\) is inversely proportional to the square o
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