Problem 16
Question
\(11-22\) a Determine an appropriate viewing rectangle for the equation, and use it to draw the graph. $$ y=\sqrt{12 x-17} $$
Step-by-Step Solution
Verified Answer
Domain: \(x \geq \frac{17}{12}\); Range: \(y \geq 0\). Viewing rectangle: \((1, 10)\) for \(x\) and \((0, 10)\) for \(y\).
1Step 1: Determine the domain of the function
The function given is a square root function, which exists for values of \(x\) where the expression inside the square root is non-negative. Thus, we need \(12x - 17 \geq 0\). Solve for \(x\):\[12x - 17 \geq 0 \12x \geq 17 \x \geq \frac{17}{12} \]This means that the domain of the function is \(x \geq \frac{17}{12}\).
2Step 2: Determine the range of the function
Since the square root function outputs non-negative numbers, the range of this function is \(y \geq 0\).
3Step 3: Choose an appropriate viewing rectangle
Considering the domain and range, we need \(x\) values starting from just below \(\frac{17}{12}\) (approximately 1.42) onwards, and \(y\) values starting from 0 upwards. A suitable viewing rectangle could be \(x\) from 1 to 10 and \(y\) from 0 to 10 ensuring both domain and range are captured.
4Step 4: Sketch the graph within the viewing rectangle
Plot the graph within the chosen rectangle. Start from \(x = \frac{17}{12}\), where \(y = 0\), and draw the curve as \(x\) increases. The graph will rise smoothly starting at \(y = 0\). As \(x\) increases, the value under the square root increases, meaning \(y\) increases.
Key Concepts
Function DomainFunction RangeGraphing EquationsViewing Rectangle
Function Domain
In mathematics, a function's domain refers to the complete set of possible input values (often "x" values) that will result in meaningful output from the function. When working with a square root function like \(y = \sqrt{12x - 17}\), we must consider the values of \(x\) for which the expression inside the square root remains non-negative.
Importance of Domain:
Importance of Domain:
- The values inside the square root must be greater than or equal to zero to produce real and valid numbers.
- The domain of \(y = \sqrt{12x - 17}\) requires that \(12x - 17 \geq 0\).
Function Range
The function range describes all possible output values (often "y" values) a function can produce. For the square root function \(y = \sqrt{12x - 17}\), the range helps us understand the extent of \(y\) values.
Identifying the Range:
Identifying the Range:
- A square root function always sends out non-negative results because square root outputs are never negative.
- For our function, this means \(y \geq 0\) because the smallest value of \(y\) occurs when the expression under the square root is zero.
Graphing Equations
Graphing equations visually represents a mathematical relationship, providing insights into specific solutions or the behavior of the function. For the equation \(y = \sqrt{12x - 17}\), effective graphing involves translating solutions from algebraic expressions to a meaningful visual format.
Steps to Graphing:
Steps to Graphing:
- Start plotting at \(x = \frac{17}{12}\), where \(y\) initially equals 0, because \(12x - 17\) becomes 0, resulting in a square root of 0.
- As the value of \(x\) increases, so does the value under the square root, making \(y\) increase and portray a rising curve.
Viewing Rectangle
The concept of a viewing rectangle is crucial in graphing as it defines the portion of the graph visible on your graphing tool or screen. It is a frame capturing both domain and range, providing a complete picture of the function's behavior. When graphing \(y = \sqrt{12x - 17}\), selecting the appropriate viewing rectangle ensures proper representation of function characteristics.
Selecting a Good Viewing Rectangle:
Selecting a Good Viewing Rectangle:
- Choose an "x" range starting just below \(\frac{17}{12}\), since that's where our domain begins, to ensure we're seeing the whole picture.
- Given \(12x - 17\) yields \(0\) when \(x = 1.42\), setting "x" from 1 to 10 adequately captures it.
- For "y", starting from 0 upwards to 10 showcases the non-negative range.
Other exercises in this chapter
Problem 15
\(11-36\) Make a table of values and sketch the graph of the equation. Find the \(x\) - and \(y\) -intercepts. $$ 2 x-y=6 $$
View solution Problem 15
Sketch the region given by the set. \(\\{(x, y) | x \geq 1 \text { and } y
View solution Problem 16
Write an equation that expresses the statement. \(A\) is jointly proportional to the square roots of \(x\) and \(y\)
View solution Problem 16
\(11-36\) Make a table of values and sketch the graph of the equation. Find the \(x\) - and \(y\) -intercepts. $$ x+y=3 $$
View solution