Problem 158
Question
Which functional groups of glucose interact to from cyclic heiacetal leading to pyranose structure? (a) Ketone group at C-2 and hydroxy group at \(\mathrm{C}-5\) (b) Aldehyde group and hydroxy group at \(\mathrm{C}-5\) (c) Aldehyde group and hydroxy group at \(\mathrm{C}-4\) (d) Aldehyde group and hydroxy group at \(\mathrm{C}-6\)
Step-by-Step Solution
Verified Answer
The aldehyde group at C-1 and the hydroxy group at C-5 form the cyclic hemiacetal in glucose.
1Step 1: Understand Structure of Glucose
Glucose is a six-carbon sugar with the molecular formula \(C_6H_{12}O_6\). It contains an aldehyde group at \(C-1\) and hydroxyl groups attached to other carbon atoms \(C-2\) through \(C-6\).
2Step 2: Formation of Hemiacetal
For glucose to form a cyclic hemiacetal, the aldehyde group at \(C-1\) interacts with one of the hydroxy groups on its other carbon atoms, typically forming a six-membered ring known as pyranose.
3Step 3: Determine Reactive Hydroxy Group
The most common interaction is between the aldehyde group at \(C-1\) and the hydroxyl group at \(C-5\) to form a six-membered pyranose ring. This reaction changes the open-chain form into a stable cyclic form.
Key Concepts
Functional GroupsPyranose StructureCyclic Hemiacetal Formation
Functional Groups
The term "functional group" in chemistry refers to specific groups of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules. In glucose, there are several functional groups primarily involved in its reactivity and structure:
- Aldehyde Group: Located at carbon 1 (C-1), this group features a carbon atom double-bonded to oxygen with a hydrogen atom attached, represented as -CHO. The aldehyde group is crucial because it is highly reactive and participates in the formation of the cyclic structure of glucose.
- Hydroxyl Groups: These groups consist of an oxygen atom bonded to a hydrogen atom (-OH). Glucose has hydroxyl groups attached to carbons 2 through 6 (C-2 to C-6). These groups are polar and engage in hydrogen bonding, affecting glucose's solubility and interactions.
Pyranose Structure
The pyranose structure refers to the six-membered ring form of sugars like glucose. This structure plays a vital role because it represents how glucose exists predominantly in nature.
- The pyranose form is achieved when the aldehyde group (CHO) at C-1 reacts with the hydroxyl group at C-5, creating a new covalent bond. This reaction is known as cyclization.
- As a result, glucose moves from an open-chain to a ring form, attaining more stability. Most often, sugars in solution are found in their cyclic form due to this inherent stability.
- In this configuration, all hydroxyl groups can interact favorably, resulting in lower energy and more consistent behavior in biological environments.
- The six-membered ring is named a pyranose because of its structural resemblance to the chemical pyran.
Cyclic Hemiacetal Formation
Cyclic hemiacetal formation is a chemical reaction where a molecule containing both an aldehyde (or ketone) and an alcohol group forms a ring structure. In glucose, this reaction is pivotal.
- The process begins when the carbonyl carbon of the aldehyde group (C=O) forms a bond with an oxygen atom in an internal hydroxyl group, typically at C-5. This intramolecular nucleophilic addition leads to the closing of the molecule into a more stable cyclic hemiacetal.
- Hemiacetals are characterized by the presence of both an ether (OR) and an alcohol (OH) functional group within the same molecule.
- This transformation locks the molecule into a specific three-dimensional structure, where the ring formation reduces the molecule's energy, hence increasing its stability.
- Cyclic hemiacetals are fundamental in the chemistry of sugars. They play a key role in the reaction mechanisms of sugars and their behavior in aqueous solutions.
Other exercises in this chapter
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