Problem 158
Question
The resistance of a bulb filament is \(100 \Omega\) at a temperature \(100^{\circ} \mathrm{C}\). If its temperature coefficient of resistance be \(0.005 /{ }^{\circ} \mathrm{C}\), its resistance will become \(200 \Omega\) at a temperature of (A) \(300^{\circ} \mathrm{C}\) (B) \(400^{\circ} \mathrm{C}\) (C) \(500^{\circ} \mathrm{C}\) (D) \(200^{\circ} \mathrm{C}\)c
Step-by-Step Solution
Verified Answer
The temperature at which the resistance becomes \(200 \Omega\) is \(400^{\circ} \mathrm{C}\).
1Step 1: Identify given quantities
From the problem we can identify the initial resistance \(R_{0} = 100 \Omega\), the temperature coefficient of resistance \(\alpha = 0.005 /{ }^{\circ} \mathrm{C}\), and the resistance we want to reach\( R_{T} = 200 \Omega\).
2Step 2: Write down the equation for resistance as function of temperature
The general formula to calculate the resistance at a certain temperature is \(R_{T} = R_{0} * (1 + \alpha * T)\).
3Step 3: Solve the equation for temperature T
We want to find the temperature at which the resistance becomes \(200 \Omega\). So we solve the formula from step 2 for T: \(T = (R_{T} / R_{0} - 1) / \alpha \).
4Step 4: Substitute the given values and find the final temperature
Substitute the given values into the equation \(T = (200 / 100 - 1) / 0.005\). Solve the calculation to find the value of T.
Key Concepts
Temperature Coefficient of ResistanceOhm's LawFilament Bulb Resistance
Temperature Coefficient of Resistance
The temperature coefficient of resistance is an essential concept when studying how materials change with temperature. Every material has a specific reaction to temperature changes, and this is quantified by the temperature coefficient of resistance, often represented as \( \alpha \). This coefficient tells us how much the resistance of a material will change with a change in temperature.
- High \( \alpha \): Resistance changes a lot with temperature.
- Low \( \alpha \): Resistance is more stable with temperature changes.
Ohm's Law
Ohm's Law is one of the fundamental principles in electronics and physics. It describes the relationship between voltage, current, and resistance in an electrical circuit. The law is usually expressed with the formula:\[ V = I \times R \]where:
- \( V \) is the voltage across the conductor.
- \( I \) is the current flowing through the conductor.
- \( R \) is the resistance of the conductor.
Filament Bulb Resistance
The resistance of a filament bulb is an interesting case because it doesn't remain constant with use. This is largely due to the temperature coefficient of resistance, which affects metals like those used in a filament.
As the filament heats up, its temperature increases significantly, resulting in a corresponding rise in its resistance. This is why bulbs consume more power as they warm up to their operating temperature. Over time, this change can cause wear and tear on the filament, eventually leading to the bulb burning out.
Understanding filament bulb resistance is not just academic; it has practical implications in designing circuits that incorporate these components. Knowing the starting and operating resistances allows engineers to ensure that bulbs work efficiently and safely in various environments.
Other exercises in this chapter
Problem 155
Two conductors have the same resistance at \(0^{\circ} \mathrm{C}\) but their temperature coefficients of resistance are \(\alpha_{1}\) and \(\alpha_{2} .\) The
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The resistance of a wire is \(5 \Omega\) at \(50^{\circ} \mathrm{C}\) and \(6 \Omega\) at \(100^{\circ} \mathrm{C}\). The resistance of the wire at \(0^{\circ}
View solution Problem 159
An electric bulb is rated \(220 \mathrm{~V}-100 \mathrm{~W}\). The power consumed by it when operated on \(110 \mathrm{~V}\) will be (A) \(75 \mathrm{~W}\) (B)
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Two sources of equal EMF are connected to an external resistance \(R\). The internal resistances of the two sources are \(R_{1}\) and \(R_{2}\left(R_{2}>R_{1}\r
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