Problem 158
Question
The orbital angular momentum for an electron re volving in an orbit is given by \(\sqrt{\ell} /(l+1) \mathrm{h} / 2 \pi\). This momentum for an s electron will be given by \([\mathbf{2 0 0 3}]\) (a) \(+1 / 2 \cdot \mathrm{h} / 2 \pi\) (b) zero (c) \(\mathrm{h} / 2 \pi\) (d) \(\sqrt{2} \cdot \mathrm{h} / 2 \pi\)
Step-by-Step Solution
Verified Answer
The orbital angular momentum for an s electron is zero.
1Step 1: Understanding the Problem
We are given the expression for orbital angular momentum: \( \sqrt{\ell(\ell+1)} \cdot \frac{h}{2 \pi} \). We need to find out the momentum for an s electron, which is characterized by the angular momentum quantum number \( \ell = 0 \).
2Step 2: Substitute \(\ell=0\)
For an s electron, the angular momentum quantum number \( \ell = 0 \). Substitute \( \ell = 0 \) into the expression \( \sqrt{\ell(\ell+1)} \cdot \frac{h}{2 \pi} \).
3Step 3: Calculate Angular Momentum
Substituting \( \ell = 0 \) gives: \( \sqrt{0(0+1)} \cdot \frac{h}{2 \pi} = \sqrt{0} \cdot \frac{h}{2 \pi} = 0 \). Therefore, for an s electron, the orbital angular momentum is zero.
4Step 4: Conclusion
Based on the calculation, the orbital angular momentum for an s electron is zero, which corresponds to option (b).
Key Concepts
Angular Momentum Quantum Numbers ElectronQuantum Mechanics
Angular Momentum Quantum Number
In quantum mechanics, the angular momentum quantum number is a vital concept that helps describe the environment where an electron resides within an atom. This quantum number, often symbolized as \( \ell \), dictates the shape of the orbital in which an electron moves. Angular momentum is a property intrinsic to an electron's movement, and it comes with discrete possible values.
- When \( \ell = 0 \), the electron is in an 's orbital'.
- An 's' orbital is spherical, indicating equal probability of finding the electron at any angle.
- Other possible values (when \( \ell \) is greater than zero) correspond to other orbital shapes like 'p', 'd', 'f', etc.
s Electron
The 's electron' is a term used to refer to the simplest type of electron orbital in an atom. The 's' in 's-electron' signifies that it is associated with an \( \ell \) value of zero, as determined by its angular momentum quantum number. Here's what makes 's electrons' unique:
- They are located in spherical orbitals around the atomic nucleus.
- Because they are spherical, s electrons have no angular dependence, meaning their probability cloud is uniform in all directions.
- The absence of angular momentum (because the orbital angular momentum is zero) suggests these electrons do not revolve around the nucleus like tiny spinning tops.
Quantum Mechanics
Quantum mechanics is a fundamental theory in physics that describes the physical properties of nature at the scale of atoms and subatomic particles. It provides a comprehensive framework to understand the behaviors of electrons in atoms.
- Electrons are often considered as both particles and waves, leading to the development of quantum states.
- Quantum mechanics incorporates concepts such as wave functions and probability amplitudes, which predict where an electron is likely to be found.
- One of the important quantum numbers, such as angular momentum quantum number \( \ell \), play a crucial role in defining an electron's state.
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