Problem 157
Question
If the letters of word SACHIN are arranged in all possible ways and these words are written out as in dictionary, then the word SACHIN appears at serial number (A) 601 (B) 600 (C) 603 (D) 602
Step-by-Step Solution
Verified Answer
The word 'SACHIN' appears at serial number 601.
1Step 1: Understanding the problem
We need to find the position of the word 'SACHIN' if all its permutations are arranged alphabetically.
2Step 2: Identify permutations starting with letters before 'S'
First, determine how many permutations can be formed starting with letters that appear before 'S' in the alphabet (i.e., 'A', 'C', 'H', 'I', and 'N').
3Step 3: Permutations starting with 'A'
There are 5 remaining letters: 'C', 'H', 'I', 'N', and 'S'. Calculate the permutations: \(5! = 120\).
4Step 4: Permutations starting with 'C'
Similarly, permutations of 'A', 'H', 'I', 'N', 'S' are counted as: \(5! = 120\).
5Step 5: Permutations starting with 'H'
Permutations of 'A', 'C', 'I', 'N', 'S' are: \(5! = 120\).
6Step 6: Permutations starting with 'I'
Permutations of 'A', 'C', 'H', 'N', 'S' are: \(5! = 120\).
7Step 7: Permutations starting with 'N'
Permutations of 'A', 'C', 'H', 'I', 'S' are: \(5! = 120\).
8Step 8: Calculating permutations for words starting with 'S'
Now calculate how many permutations start with 'SA', 'SC', 'SH', and so on, until 'SACHIN' is reached.
9Step 9: Words starting with 'SA'
For 'SA', the permutations of 'C', 'H', 'I', 'N' are \(4! = 24\).
10Step 10: Words starting with 'SAC'
For 'Sac', permutations of 'H', 'I', 'N' are \(3! = 6\).
11Step 11: Words starting with 'SACH'
For 'Sach', permutations of 'I', 'N' are \(2! = 2\).
12Step 12: Words starting with 'SACHI'
For 'SACHI', permutation is 'N'. Only 1 such permutation exists.
13Step 13: Position of the word 'SACHIN'
Add all the previous permutations: 5*120 + 24 + 6 + 2 + 1 + 1 = 601.
Key Concepts
Dictionary order of permutationsFactorial calculationAlphabetical arrangement
Dictionary order of permutations
Permutations are all the possible arrangements of a set of items. In this case, the items are the letters of the word "SACHIN." When we talk about the "dictionary order of permutations," we mean arranging all permutations (or combinations) of the letters in the same order as they would appear in a dictionary.
Think of it like looking up words in a dictionary: words starting with 'A' come before those starting with 'B', and so forth. Following this order ensures a systematic method to find where any word would land if all permutations were listed. This is precisely what is required in the exercise: determining exactly where "SACHIN" would appear if you wrote out all its letter rearrangements alphabetically.
Think of it like looking up words in a dictionary: words starting with 'A' come before those starting with 'B', and so forth. Following this order ensures a systematic method to find where any word would land if all permutations were listed. This is precisely what is required in the exercise: determining exactly where "SACHIN" would appear if you wrote out all its letter rearrangements alphabetically.
- It starts by considering permutations that begin with letters that come before 'S'.
- After accounting for all those, it moves to permutations starting with 'S', and narrows down to "SACHIN" specifically.
Factorial calculation
Permutations rely heavily on factorial calculations, denoted by the symbol "!" in mathematics. The factorial of a number, say 5!, is the product of all positive integers from 1 to that number. So, 5! equals 5 x 4 x 3 x 2 x 1 = 120.
In this exercise, factorial calculations help determine how many permutations are possible with the remaining letters after choosing the first letter. For instance, when considering permutations starting with 'A', there are 5 remaining letters to permute: 'C', 'H', 'I', 'N', and 'S'. Thus, 5! = 120 possible arrangements can be made for each letter choice that precedes 'S'.
In this exercise, factorial calculations help determine how many permutations are possible with the remaining letters after choosing the first letter. For instance, when considering permutations starting with 'A', there are 5 remaining letters to permute: 'C', 'H', 'I', 'N', and 'S'. Thus, 5! = 120 possible arrangements can be made for each letter choice that precedes 'S'.
- 5 letters -> 5! = 120 permutations
- 4 letters -> 4! = 24 permutations
- 3 letters -> 3! = 6 permutations
Alphabetical arrangement
Alphabetical arrangement, also known as lexicographical order, is simply arranging words based on the position of each letter in the alphabet. This arrangement helps us to sort and find words systematically, just like how words are sorted in dictionaries.
In solving the problem of finding "SACHIN"'s position among its permutations, each step starts with checking permutations that begin with letters appearing before 'S' alphabetically—that includes 'A', 'C', 'H', 'I', and 'N'.
In solving the problem of finding "SACHIN"'s position among its permutations, each step starts with checking permutations that begin with letters appearing before 'S' alphabetically—that includes 'A', 'C', 'H', 'I', and 'N'.
- 'A' appears before 'C', so permutations starting with 'A' come first.
- Then, permutations starting with 'C', and so on, until reaching 'S'.
Other exercises in this chapter
Problem 155
How many ways are there to arrange the letters in the word GARDEN with the vowels in alphabetical order? (A) 120 (B) 480 (C) 360 (D) 240
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At an election, a voter may vote for any number of candidates, not greater than the number to be elected. There are 10 candidates and 4 are of be elected. If a
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