Problem 156
Question
Match the following: List I (Compound) 1\. \(\mathrm{XeF}_{2}\) 2\. \(\mathrm{XeF}_{4}^{\circ}\) 3\. \(\mathrm{XeF}_{6}\) 4\. \(\mathrm{XeO}_{3}\) List II (Number of lone pair electron) (i) 0 (ii) 1 (iii) 2 (iv) 3 The correct matching is: 1 2 3 4 (a) (iii) (iv) (ii) (ii) (b) (iv) (iii) (ii) (ii) (c) (iv) (ii) (ii) (iii) (d) (iv) (iii) (i) (ii)
Step-by-Step Solution
Verified Answer
The correct match is (b) - (iv), (iii), (ii), (ii).
1Step 1: Identify XeF2 and Lone Pairs
For XeF2, we determine its Lewis structure. Xenon (Xe) is in Group 18, so it has 8 valence electrons, while Fluorine (F) has 7 valence electrons each. XeF2 has a total of 22 valence electrons (8 from Xe and 14 from two F atoms). When arranging them with a stable electron configuration, XeF2 forms a Linear shape with 3 lone pairs on Xe, hence matching with number of lone pairs from List II as (iv) 3.
2Step 2: Identify XeF4 and Lone Pairs
XeF4 also requires a Lewis structure for determination. Xe(8 valence electrons) and four F atoms (7 each) result in 36 valence electrons in XeF4. The structure equilibrates with a square planar geometry, placing 2 lone pairs on Xe. This pairs with (iii) 2 from List II.
3Step 3: Identify XeF6 and Lone Pairs
Forming the Lewis structure for XeF6, we have Xe with 8 valence electrons, and 6 fluorine atoms contributing 42 electrons in total. An octahedral shape accommodates the lone pair arrangement for Xenon in this compound, resulting in 1 lone pair. Hence it matches with (ii) 1 from List II.
4Step 4: Identify XeO3 and Lone Pairs
For XeO3, Xe has 8 valence electrons, with each O adding 6 electrons, totalling 26 valence electrons. The structure aligns with a pyramidal shape, explaining the presence of 1 lone pair on Xe, consistent with (ii) 1 from List II.
Key Concepts
Lewis StructuresLone Pair ElectronsValence ElectronsMolecular Geometry
Lewis Structures
Lewis Structures are essential for understanding how atoms in a molecule are bonded and how electrons are arranged around them. It’s a visual representation of the valence electrons that helps us predict molecular shapes and properties.
- Each atom is represented by its symbol.
- Valence electrons of the atom are shown as dots around the symbol. These electrons are in the outermost shell and are the ones involved in bonding.
- Lines represent covalent bonds, showing shared pairs of electrons between atoms.
Lone Pair Electrons
Lone pair electrons, also known as non-bonding pairs, are valence electrons that are not shared with another atom and do not participate in bonding. They influence molecular geometry and reactivity.
- Present on atoms to satisfy the octet rule when there aren't enough atoms to form bonds.
- Their presence can repel bonding pairs, impacting the geometry of the molecule.
Valence Electrons
Valence electrons are the outermost electrons of an atom and are critical in determining how atoms bond and react with each other. They participate in forming chemical bonds either by sharing, losing, or gaining electrons.
- Group number of elements can help in determining the number of valence electrons in main group elements.
- Generally range from 1 to 8 for main group elements.
Molecular Geometry
Molecular Geometry describes the three-dimensional arrangement of atoms within a molecule. It provides insight into molecular shape and its potential interactions with other molecules.
- Determined by the number of bonding pairs and lone pairs on the central atom.
- Common geometries include linear, bent, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral.
Other exercises in this chapter
Problem 154
When \(\mathrm{Cl}_{2}\) is passed through hot conc. \(\mathrm{NaOH}\), Salts A and \(\mathrm{B}\) are formed which are separated by fractional crystallization.
View solution Problem 155
Match the following: List I 1\. \(\mathrm{XeF}_{4}\) 2\. \(\mathrm{XeF}_{6}\) 3\. \(\mathrm{XeO}_{3}\) 4\. \(\mathrm{XeO}_{4}\) List II (i) distorted octahedral
View solution Problem 157
Which one of the following is/are the incorrect statement(s)? (a) Boric acid is a protonic acid (b) Beryllium exhibits coordination number of six. (c) Chlorides
View solution Problem 158
Select the correct statements about diborane: (a) \(\mathrm{H}_{\mathrm{b}} \ldots \mathrm{B} \ldots \mathrm{H}_{\mathrm{b}}\) bond angle is \(122^{\circ}\) (b)
View solution