Problem 156
Question
For gaseous state if most probable speed is denoted \(\mathrm{C}^{*}\), average speed by \(\overline{\mathrm{C}}\) and and mean square speed by C, then for a large number of molecules the ratios of these speeds are: (a) \(C^{*}: \overline{\mathrm{C}}: \mathrm{C}=1: 128: 1.225\) (b) \(\mathrm{C}^{*}: \overline{\mathrm{C}}=1: 1.225: 1.128\) (c) \(\mathrm{C}^{*}: \overline{\mathrm{C}}: \mathrm{C}=1.225: 1.128: 1\) (d) \(\mathrm{C}^{*}: \overline{\mathrm{C}}: \mathrm{C}=1.128: 1.225: 1\)
Step-by-Step Solution
Verified Answer
The correct option is (d): \(C^* : \overline{C} : C = 1 : 1.128 : 1.225\).
1Step 1: Understanding Speed Formulas
In the gaseous state, the speeds of gas molecules can be categorized into three types: most probable speed, average speed, and root mean square speed. They are given by different formulas: Most probable speed \(C^* = \sqrt{\frac{2RT}{M}}\), Average speed \(\overline{C} = \sqrt{\frac{8RT}{\pi M}}\), and Root mean square speed \(C = \sqrt{\frac{3RT}{M}}\).
2Step 2: Calculate Ratios
To find the ratios of these speeds, we compute the fractions between each pair of speeds using their formulas. To start, calculate the ratio \( \frac{\overline{C}}{C^*} = \frac{\sqrt{\frac{8RT}{\pi M}}}{\sqrt{\frac{2RT}{M}}} = \sqrt{\frac{8}{2 \pi}} = \sqrt{\frac{4}{\pi}} \approx 1.128.\)
3Step 3: Compute the Next Ratio
Now compute the ratio \( \frac{C}{C^*} = \frac{\sqrt{\frac{3RT}{M}}}{\sqrt{\frac{2RT}{M}}} = \sqrt{\frac{3}{2}} \approx 1.225.\)
4Step 4: Arrange the Ratios
Using the computed ratios, the arrangement \(C^* : \overline{C} : C\) becomes \(1 : 1.128 : 1.225.\)
5Step 5: Select Correct Answer
Compare the arranged ratios to the options provided: option (d) matches the calculated result: \(C^* : \overline{C} : C = 1 : 1.128 : 1.225\).
Key Concepts
Most Probable SpeedAverage SpeedRoot Mean Square Speed
Most Probable Speed
In the study of gases, the concept of most probable speed refers to the speed at which the largest number of particles in a gas are moving. It's important to note that this is not the average speed, but the mode of the speed distribution in a gas. For molecules in a gas, this speed can be calculated using a mathematical formula:
- The formula is given by \(C^* = \sqrt{\frac{2RT}{M}}\).
- Here, \(R\) is the universal gas constant, \(T\) is the temperature in Kelvin, and \(M\) is the molar mass of the gas.
Average Speed
Average speed in the context of gases is exactly what it sounds like: the mean speed of all the molecules in a gas sample. It's a measure of the typical speed that gas molecules are moving at a given temperature. To compute this, one uses the formula:
This concept is meaningful in real-world applications as it helps in predicting the behavior of gases under different circumstances, such as in chemical reactions or in gas diffusion.
- \(\overline{C} = \sqrt{\frac{8RT}{\pi M}}\)
- Again, \(R\) is the gas constant, \(T\) is the temperature in Kelvin, and \(M\) is the molar mass.
This concept is meaningful in real-world applications as it helps in predicting the behavior of gases under different circumstances, such as in chemical reactions or in gas diffusion.
Root Mean Square Speed
Root mean square speed (often abbreviated as RMS speed) is a particularly useful statistical measure in understanding the kinetic energies of gases. It is essentially the square root of the average of the squares of the individual speeds of gas molecules, which gives insight into their energetic behavior. The formula is:
It gives us an idea about the kinetic energy possessed by the gas particles, which is critical in many thermodynamic calculations and is fundamental to the derivation of important gas laws. By comparing RMS speed with other speed measurements, we can gain a deeper understanding of gas molecule behavior in various conditions.
- \(C = \sqrt{\frac{3RT}{M}}\)
- Where \(R\) is the universal gas constant, \(T\) is the temperature in Kelvin, and \(M\) is the molar mass of the gas.
It gives us an idea about the kinetic energy possessed by the gas particles, which is critical in many thermodynamic calculations and is fundamental to the derivation of important gas laws. By comparing RMS speed with other speed measurements, we can gain a deeper understanding of gas molecule behavior in various conditions.
Other exercises in this chapter
Problem 154
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