Problem 154
Question
The probability that \(A\) speaks truth is \(\frac{4}{5}\), while this probability for \(B\) is \(\frac{3}{4}\). The probability that they contradict each other when asked to speak on a fact is \([\mathbf{2 0 0 4}]\) (A) \(\frac{3}{20}\) (B) \(\frac{1}{5}\) (C) \(\frac{7}{20}\) (D) \(\frac{4}{5}\)
Step-by-Step Solution
Verified Answer
The probability is \(\frac{7}{20}\). (Option C)
1Step 1: Identify Probabilities
First, let's denote the probability that \(A\) speaks the truth as \(P(T_A) = \frac{4}{5}\), which means the probability that \(A\) lies, \(P(F_A)\), is \(1 - \frac{4}{5} = \frac{1}{5}\). Similarly, for \(B\), the probability that \(B\) speaks the truth is \(P(T_B) = \frac{3}{4}\), thus the probability that \(B\) lies, \(P(F_B)\), is \(1 - \frac{3}{4} = \frac{1}{4}\).
2Step 2: Define Contradiction Scenarios
For \(A\) and \(B\) to contradict each other, one must be telling the truth while the other lies. Thus, there are two possible scenarios: \(A\) tells the truth and \(B\) lies, or \(A\) lies and \(B\) tells the truth.
3Step 3: Calculate Probability for Each Scenario
Calculate the probability of scenario 1 where \(A\) tells the truth and \(B\) lies: \[ P(T_A \cap F_B) = P(T_A) \cdot P(F_B) = \frac{4}{5} \cdot \frac{1}{4} = \frac{4}{20}. \]Then, calculate the probability of scenario 2 where \(A\) lies and \(B\) tells the truth: \[ P(F_A \cap T_B) = P(F_A) \cdot P(T_B) = \frac{1}{5} \cdot \frac{3}{4} = \frac{3}{20}. \]
4Step 4: Calculate Total Probability of Contradiction
Add the probabilities of the two scenarios from Step 3 to get the total probability that \(A\) and \(B\) contradict each other:\[ P(\text{contradiction}) = P(T_A \cap F_B) + P(F_A \cap T_B) = \frac{4}{20} + \frac{3}{20} = \frac{7}{20}. \]
Key Concepts
Conditional ProbabilityIndependent EventsContradictory Statements Analysis
Conditional Probability
Conditional probability is the probability of an event occurring given that another event has already occurred. This concept is key in problems involving dependent events. In our exercise, knowing that one person tells the truth affects the chances of the other lying to create a contradiction. For instance, if we know that person \( A \) tells the truth, the remaining chance of person \( B \) lying is used. The formula for conditional probability is:
- \( P(B | A) = \frac{P(A \cap B)}{P(A)} \)
Independent Events
In probability, independent events are those whose occurrence does not influence each other's chances. The exercise implicitly assumes the independence between \( A \)'s and \( B \)'s truthfulness or lying. Under this assumption, the likelihood of them contradicting is straightforwardly computed by multiplying their respective probabilities. This is expressed as:
- \( P(A \cap B) = P(A) \cdot P(B) \)
Contradictory Statements Analysis
Analyzing contradictory statements involves understanding how probabilities of certain exclusive events affect the likelihood of them occurring together as opposites. In our exercise, \( A \) and \( B \) can speak either truthfully or falsely, offering two scenarios of contradiction. Importantly, for them to contradict each other, one must be lying while the other tells the truth. This situation is characterized by non-overlapping occurrences which:
- \( A \) tells the truth and \( B \) lies
- \( A \) lies and \( B \) tells the truth
Other exercises in this chapter
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