Problem 154
Question
Solve the equation. Round your answer to three decimal places, if necessary. $$2 x^{2}+x-4=0$$
Step-by-Step Solution
Verified Answer
The solutions to the equation are \(x = 0.782\) and \(x = -2.282\).
1Step 1: Identify the coefficients
In the equation \(2x^2 + x - 4 = 0\), the coefficients are \(a = 2\), \(b = 1\), and \(c = -4\).
2Step 2: Apply the quadratic formula
Plug these values into the quadratic formula. So, \(x = [-1 ± sqrt((1)^2 - 4*2*(-4))] / 2*2\).
3Step 3: Calculate the square root part
The part under the square is \(1 - 4*2*(-4)=17\). Therefore, the equation becomes: \(x = [-1 ± sqrt(17)] / 4\)
4Step 4: Solve for x
Finally, this gives two possible solutions, \(x = [-1 + sqrt(17)] / 4 = 0.782\) and \(x = [-1 - sqrt(17)] / 4 = -2.282\). These are the roots of the quadratic equation.
Key Concepts
Quadratic FormulaRoots of EquationsSolving Quadratic Equations
Quadratic Formula
The quadratic formula is a key tool in solving quadratic equations. It provides an efficient method to find the roots of any quadratic equation of the form \(ax^2 + bx + c = 0\). The formula itself is written as:
Furthermore, the term under the square root, \(b^2 - 4ac\) is called the discriminant. It determines the nature of the roots:
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
Furthermore, the term under the square root, \(b^2 - 4ac\) is called the discriminant. It determines the nature of the roots:
- If it's positive, there are two distinct real roots.
- If it's zero, there's exactly one real root.
- If it's negative, the roots are complex (not real numbers).
Roots of Equations
The roots of a quadratic equation are the values of \(x\) that make the equation true (i.e., zero). In terms of the graph of a quadratic equation, the roots represent the points where the parabola intersects the x-axis. These solutions can provide insights into the nature and direction of the parabola.
When we solve the equation \(2x^2 + x - 4 = 0\) using the quadratic formula, we found the roots to be approximately \(0.782\) and \(-2.282\). These roots tell us that the parabola crosses the x-axis at these points. It's important to note:
When we solve the equation \(2x^2 + x - 4 = 0\) using the quadratic formula, we found the roots to be approximately \(0.782\) and \(-2.282\). These roots tell us that the parabola crosses the x-axis at these points. It's important to note:
- The roots are often referred to as "zeros" because they represent the x-values where the equation results in zero.
- In some contexts, these solutions might be called solutions or x-intercepts, but they all guide us to the same understanding of the equation's graphical behavior.
Solving Quadratic Equations
Solving quadratic equations often requires a specific set of steps. Let's summarize these steps using our example equation, \(2x^2 + x - 4 = 0\):
- First, identify the coefficients \(a\), \(b\), and \(c\). In our case, \(a=2\), \(b=1\), and \(c=-4\).
- Next, substitute these values into the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
- Simplify the expression under the square root (the discriminant), which for our equation is \(17\).
- Use the resolved formula \(x = \frac{-1 \pm \sqrt{17}}{4}\) to find the precise solutions.
Other exercises in this chapter
Problem 152
Solve the equation. Round your answer to three decimal places, if necessary. $$44-9 x=61$$
View solution Problem 153
Solve the equation. Round your answer to three decimal places, if necessary. $$x^{2}-2 x-5=0$$
View solution Problem 155
Solve the equation. Round your answer to three decimal places, if necessary. $$\frac{3}{x-1}=\frac{x+2}{9}$$
View solution Problem 156
Solve the equation. Round your answer to three decimal places, if necessary. $$\frac{5}{x}=\frac{x+4}{2 x}$$
View solution