Problem 153
Question
If \(z_{1}, z_{2}, z_{3}\) are three points lying on the circle \(|z|=2\) then the minimum value of \(\left|z_{1}+z_{2}\right|^{2}+\left|z_{2}+z_{3}\right|^{2}+\) \(\left|z_{3}+z_{1}\right|^{2}\) is equal to (A) 6 (B) 12 (C) 15 (D) 24
Step-by-Step Solution
Verified Answer
The minimum value is 24.
1Step 1: Understand the Geometry
The given points \(z_1, z_2, z_3\) lie on the circle \(|z| = 2\), which means that each point \(z_i\) satisfies the equation \(|z_i| = 2\). This is a circle centered at the origin with radius 2 in the complex plane.
2Step 2: Use the Property of Circle
Since \(z_1, z_2, z_3\) are on the circle \(|z|=2\), their magnitudes are the same. We need to find the minimum value of the expression: \[\left|z_1 + z_2\right|^2 + \left|z_2 + z_3\right|^2 + \left|z_3 + z_1\right|^2.\]
3Step 3: Expand Each Term
Begin by expanding the expression, making use of the property \(|a + b|^2 = |a|^2 + |b|^2 + 2\Re\{a\overline{b}\}\):- \(|z_1 + z_2|^2 = |z_1|^2 + |z_2|^2 + 2\Re\{z_1\overline{z_2}\}\)- \(|z_2 + z_3|^2 = |z_2|^2 + |z_3|^2 + 2\Re\{z_2\overline{z_3}\}\)- \(|z_3 + z_1|^2 = |z_3|^2 + |z_1|^2 + 2\Re\{z_3\overline{z_1}\}\)
Key Concepts
Geometry of Complex NumbersCircle in the Complex PlaneProperties of Magnitude
Geometry of Complex Numbers
Complex numbers provide a fascinating bridge between algebra and geometry. This dual nature allows us to visualize and interpret complex operations in a geometric manner. In the complex plane, each complex number is represented as a point. The horizontal axis represents the real part, while the vertical axis denotes the imaginary part.
When we work with complex numbers like our given points \(z_1, z_2, z_3\), these points are plotted on the complex plane. Understanding the geometry involves interpreting these points' locations and operations around them. For instance, when we add two complex numbers, we are essentially translating the points across the plane. Every operation has a geometric implication which can make understanding abstract concepts easier.
In the case of our exercise, we leverage the geometric property that all points \(z_1, z_2, z_3\) lie on a circle. This circle provides a clear boundary and helps simplify potential complex calculations.
When we work with complex numbers like our given points \(z_1, z_2, z_3\), these points are plotted on the complex plane. Understanding the geometry involves interpreting these points' locations and operations around them. For instance, when we add two complex numbers, we are essentially translating the points across the plane. Every operation has a geometric implication which can make understanding abstract concepts easier.
In the case of our exercise, we leverage the geometric property that all points \(z_1, z_2, z_3\) lie on a circle. This circle provides a clear boundary and helps simplify potential complex calculations.
Circle in the Complex Plane
A circle in the complex plane is defined by its center and radius, similar to circles in the Cartesian plane. In our problem, the circle is centered at the origin \((0,0)\) with a radius of 2. Hence, any complex number \(z\) satisfies the equation \(|z| = 2\).
Because these points are constrained to this circular structure, they offer symmetry which can simplify calculations like the minimum of the given expression. The geometric insight here is crucial as it limits the range and possibility of values that can be taken by the properties of the numbers, allowing for simplifications from complex algebraic expressions.
- This means that any point \(z_i\) lying on this circle has a magnitude (distance from the origin) equal to 2.
- The circle implies that all points \(z_1, z_2, z_3\) have an equal importance, and any transformation needs to take their location on the circle into account.
Because these points are constrained to this circular structure, they offer symmetry which can simplify calculations like the minimum of the given expression. The geometric insight here is crucial as it limits the range and possibility of values that can be taken by the properties of the numbers, allowing for simplifications from complex algebraic expressions.
Properties of Magnitude
Magnitude in the context of complex numbers refers to the distance a number is from the origin in the complex plane. It is calculated using the formula \(|z| = \sqrt{a^2 + b^2}\), where \(z = a + bi\). For our problem, the magnitude of all points \(z_1, z_2, z_3\) is given as 2.
The properties of magnitude simplify understanding of distances and interactions within the complex plane, providing a foundational concept necessary for more advanced calculations.
- Understanding magnitude is crucial since it remains unchanged under rotation. Hence, any two complex numbers that have the same magnitude lie on a circle with a constant radius.
- In this exercise, the magnitude properties help us know that the sums \(|z_1 + z_2|\), \(|z_2 + z_3|\), and \(|z_3 + z_1|\) are also confined by similar magnitude rules, allowing calculations using symmetry and geometry.
- Expansion using \(|a + b|^2 = |a|^2 + |b|^2 + 2\Re\{a\overline{b}\}\) allows decomposing complex expressions by calculating magnitudes directly.
The properties of magnitude simplify understanding of distances and interactions within the complex plane, providing a foundational concept necessary for more advanced calculations.
Other exercises in this chapter
Problem 151
The locus represented by the complex equation \(|z-2-i|=|z| \sin \left(\frac{\pi}{4}-\arg z\right)\) is the part of (A) a pair of straight lines (B) a circle (C
View solution Problem 152
If \(z_{1}, z_{2}, z_{3}\) are three points lying on the circle \(|z|=2\) then the minimum value of \(\left|z_{1}+z_{2}\right|^{2}+\left|z_{2}+z_{3}\right|^{2}+
View solution Problem 154
\(\sqrt{i}-\sqrt{-i}\) is equal to (A) \(i \sqrt{2}\) \(\begin{array}{lll}\text { (B) } \frac{1}{i \sqrt{2}} & \text { (C) } 0 & \text { (D) }-i \sqrt{2}\end{ar
View solution Problem 155
If \(z_{1}, z_{2}, z_{3}, z_{4}\) are the four complex numbers represented by the vertices of a quadrilateral taken in order such that \(z_{1}-z_{4}=z_{2}-z_{3}
View solution