Problem 153
Question
A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five questions. The number of choices available to him is (A) 140 (B) 196 (C) 280 (D) 346
Step-by-Step Solution
Verified Answer
There are 196 different ways to choose the questions.
1Step 1: Understand the Problem
The student needs to choose 10 questions out of 13, and he must choose at least 4 questions from the first 5.
2Step 2: Determine Possible Scenarios
Identify possible selections by choosing 4, 5, or more from the first five and filling in the rest from the remaining questions. The options are to choose 4 or 5 from the first five questions.
3Step 3: Calculate Scenario 1 (Choose 4 from First 5)
If the student chooses 4 from the first 5 questions, he needs 6 more questions from the remaining 8. Calculate the combinations as follows: \( \binom{5}{4} \times \binom{8}{6} \).
4Step 4: Calculate Scenario 1 Using Combinatorics
Calculate the number of ways to choose 4 out of 5: \( \binom{5}{4} = 5 \). Calculate the number of ways to choose 6 out of 8: \( \binom{8}{6} = 28 \). Thus the total ways for this scenario is \( 5 \times 28 = 140 \).
5Step 5: Calculate Scenario 2 (Choose 5 from First 5)
If the student chooses all 5 from the first group, he needs 5 more from the remaining 8 questions. Calculate \( \binom{5}{5} \times \binom{8}{5} \).
6Step 6: Calculate Scenario 2 Using Combinatorics
Calculate the number of ways to choose all 5 from 5: \( \binom{5}{5} = 1 \). Calculate the number of ways to choose 5 out of 8: \( \binom{8}{5} = 56 \). Thus the total for this scenario is \( 1 \times 56 = 56 \).
7Step 7: Add Results from Both Scenarios
Add the possibilities from both scenarios: 140 (from choosing 4) + 56 (from choosing 5) = 196.
Key Concepts
Binomial CoefficientProblem Solving in MathematicsMathematical Reasoning
Binomial Coefficient
A binomial coefficient is a way to describe the number of ways to choose a subset of items from a larger set, without considering the order. It is widely used in combinatorics to calculate combinations. The notation for a binomial coefficient is \( \binom{n}{k} \), which reads "n choose k".
For instance, in our problem, calculating \( \binom{5}{4} = 5 \) and \( \binom{8}{6} = 28 \) helps determine the possible combinations of questions the student can choose. Mastering binomial coefficients is fundamental in solving problems involving combinations and permutations.
- Here, \( n \) represents the total number of items.
- \( k \) denotes the number of items to choose.
For instance, in our problem, calculating \( \binom{5}{4} = 5 \) and \( \binom{8}{6} = 28 \) helps determine the possible combinations of questions the student can choose. Mastering binomial coefficients is fundamental in solving problems involving combinations and permutations.
Problem Solving in Mathematics
Problem-solving in mathematics is a logical process, employing strategies and methods to find a solution. In the context of our exercise, the problem was dividing the task into smaller scenarios. Here, it was broken into two possible scenarios based on the fixed criteria:
- Choosing at least 4 questions from the first 5.
- Filling the rest from the remaining questions.
Mathematical Reasoning
Mathematical reasoning involves logical thinking to analyze problems and select appropriate methods and formulas. In our scenario, it is employed to discern how to allocate the choice among different groups of questions logically.
The student utilized reasoning to understand and apply the constraints of the problem. The must-choose condition from the first five questions enforced a thoughtful approach:
The student utilized reasoning to understand and apply the constraints of the problem. The must-choose condition from the first five questions enforced a thoughtful approach:
- Calculate the combinations if choosing 4 questions out of the first 5.
- Calculate the combinations if choosing all 5 questions from these five.
Other exercises in this chapter
Problem 151
$$ \begin{array}{ll} \text { Column-I } & \text { Column-II } \\ \hline \text { (I) }{\underline{\phantom{xx}}}^{n-2} C_{r}+2 .^{n-2} C_{r-1}+ & \text { (A) } n+3 \\ { }^{n-2} C_{r-2}
View solution Problem 152
Instructions: In the following questions an Assertion \((A)\) is given followed by a Reason \((R) .\) Mark your responses from the following options: (A) Assert
View solution Problem 154
If \(^{n} C_{r}\) denotes the number of combinations of \(n\) things taken \(r\) at a time, then the expression \({ }^{n} C_{r+1}+{ }^{n} C_{r-1}+\) \(2 \times{
View solution Problem 155
How many ways are there to arrange the letters in the word GARDEN with the vowels in alphabetical order? (A) 120 (B) 480 (C) 360 (D) 240
View solution