Problem 152
Question
When \(\mathrm{NH}_{4} \mathrm{Cl}\) is added to an aqueous solution of \(\mathrm{NH}_{4} \mathrm{OH}\), (a) Conc. of \(\left[\mathrm{OH}^{-}\right]\)ions decreases. (b) Conc. of \(\left[\mathrm{OH}^{-}\right]\)ions increases. (c) Conc. of \(\left[\mathrm{NH}_{4}^{+}\right]\)ions as well as conc. \(\left[\mathrm{OH}^{-}\right]\)ions increase. (d) Conc. of \(\left[\mathrm{NH}_{4}^{+}\right]\)ions decreases.
Step-by-Step Solution
Verified Answer
Adding \( \mathrm{NH}_{4} \mathrm{Cl} \) decreases the \( \left[\mathrm{OH}^{-}\right] \) concentration.
1Step 1: Understanding Initial Conditions
Initially, we have an aqueous solution of \( \mathrm{NH}_{4} \mathrm{OH} \). This is a weak base, which means it partially dissociates in water to produce \( \mathrm{NH}_{4}^{+} \) and \( \mathrm{OH}^{-} \) ions.
2Step 2: Adding Ammonium Chloride
When \( \mathrm{NH}_{4} \mathrm{Cl} \) is added to the solution, it dissociates completely in water to give \( \mathrm{NH}_{4}^{+} \) and \( \mathrm{Cl}^{-} \) ions. The increase in \( \mathrm{NH}_{4}^{+} \) ions is due to this dissociation.
3Step 3: Le Chatelier's Principle Application
According to Le Chatelier’s Principle, increasing \( \mathrm{NH}_{4}^{+} \) ions will shift the equilibrium of the dissociation of \( \mathrm{NH}_{4} \mathrm{OH} \) towards the left (towards the undissociated \( \mathrm{NH}_{4} \mathrm{OH} \)), thus decreasing the concentration of \( \mathrm{OH}^{-} \) ions.
4Step 4: Conclusion Deduction
The addition of \( \mathrm{NH}_{4} \mathrm{Cl} \) decreases the concentration of \( \mathrm{OH}^{-} \) ions due to common ion effect and increases the concentration of \( \mathrm{NH}_{4}^{+} \) ions. Therefore, option (a) is correct.
Key Concepts
Common Ion EffectWeak BasesEquilibrium Shift
Common Ion Effect
The common ion effect refers to the shift in equilibrium that occurs when a solution already containing an ion from a weak electrolyte is supplemented with an external source of the same ion. In our case, the solution contains \( \mathrm{NH}_4\mathrm{OH} \) which dissociates partially to give \( \mathrm{NH}_4^+ \) and \( \mathrm{OH}^- \) ions. When \( \mathrm{NH}_4\mathrm{Cl} \) is added, it introduces more \( \mathrm{NH}_4^+ \) ions into the solution.
This injection of additional \( \mathrm{NH}_4^+ \) ions from \( \mathrm{NH}_4\mathrm{Cl} \) exerts pressure on the equilibrium state of the original \( \mathrm{NH}_4\mathrm{OH} \) dissociation.
The extra \( \mathrm{NH}_4^+ \) ions cause the equilibrium to shift towards the left, forming undissociated \( \mathrm{NH}_4\mathrm{OH} \) and reducing the concentration of \( \mathrm{OH}^- \) ions in the solution.
This injection of additional \( \mathrm{NH}_4^+ \) ions from \( \mathrm{NH}_4\mathrm{Cl} \) exerts pressure on the equilibrium state of the original \( \mathrm{NH}_4\mathrm{OH} \) dissociation.
The extra \( \mathrm{NH}_4^+ \) ions cause the equilibrium to shift towards the left, forming undissociated \( \mathrm{NH}_4\mathrm{OH} \) and reducing the concentration of \( \mathrm{OH}^- \) ions in the solution.
Weak Bases
Weak bases are substances that do not fully dissociate in water. Instead, they reach an equilibrium state that allows only a partial release of ions.
\( \mathrm{NH}_4\mathrm{OH} \) serves as a classic example of a weak base. It partially dissociates into \( \mathrm{NH}_4^+ \) and \( \mathrm{OH}^-\) ions.
Unlike strong bases that dissociate completely, weak bases exist in a dynamic balance between their undissociated form and their ions.
\( \mathrm{NH}_4\mathrm{OH} \) serves as a classic example of a weak base. It partially dissociates into \( \mathrm{NH}_4^+ \) and \( \mathrm{OH}^-\) ions.
Unlike strong bases that dissociate completely, weak bases exist in a dynamic balance between their undissociated form and their ions.
- Partial Dissociation: \( \mathrm{NH}_4\mathrm{OH} \leftrightarrows \mathrm{NH}_4^+ + \mathrm{OH}^- \)
- Equilibrium State: Adjusts based on changes to the system like addition of more ions.
Equilibrium Shift
An equilibrium shift occurs when a change in the conditions affects the balance of a chemical system. According to Le Chatelier's Principle, the system will adjust itself to counteract the imposed change.
In our example, the equilibrium of the weak base \( \mathrm{NH}_4\mathrm{OH} \) was disturbed by adding \( \mathrm{NH}_4\mathrm{Cl} \).
This extra \( \mathrm{NH}_4^+ \) from \( \mathrm{NH}_4\mathrm{Cl} \) pushes the reaction to the left, reducing the concentration of \( \mathrm{OH}^- \) ions, which is an outcome of the equilibrium's attempt to restore balance. The equilibrium reaction can be expressed as:
In our example, the equilibrium of the weak base \( \mathrm{NH}_4\mathrm{OH} \) was disturbed by adding \( \mathrm{NH}_4\mathrm{Cl} \).
This extra \( \mathrm{NH}_4^+ \) from \( \mathrm{NH}_4\mathrm{Cl} \) pushes the reaction to the left, reducing the concentration of \( \mathrm{OH}^- \) ions, which is an outcome of the equilibrium's attempt to restore balance. The equilibrium reaction can be expressed as:
- \( \mathrm{NH}_4\mathrm{OH} \leftrightarrows \mathrm{NH}_4^+ + \mathrm{OH}^- \)
- Shift: Caused by increased \( \mathrm{NH}_4^+ \), moves left.
Other exercises in this chapter
Problem 150
The correct order of relative basic strength of the following is (a) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{CH} \equiv \mathrm{C}^{-}>\mathrm{OH
View solution Problem 151
At what concentration of \(\mathrm{CH}_{3} \mathrm{COOH}\) will the \(\left[\mathrm{H}^{+}\right]\) obtained will be same as that obtained from \(10^{-2} \mathr
View solution Problem 153
\(500 \mathrm{ml}\) of \(0.2 \mathrm{M} \mathrm{HCl}\) is mixed with \(500 \mathrm{ml}\) of \(0.2 \mathrm{M}\) \(\mathrm{CH}_{3} \mathrm{COOH} .25 \mathrm{ml}\)
View solution Problem 154
When \(60 \mathrm{ml}\) of \(0.1 \mathrm{M} \mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\) is mixed with \(40 \mathrm{ml}\) of \(0.125 \mathrm{M} \mathrm{Na}_{2}
View solution