Problem 152
Question
When \(\mathrm{NH}_{4} \mathrm{Cl}\) is added to an aqueous solution of \(\mathrm{NH}_{4} \mathrm{OH}\), (a) Conc. of \(\left[\mathrm{OH}^{-}\right]\)ions decreases. (b) Conc. of \(\left[\mathrm{OH}^{-}\right]\)ions increases. (c) Conc. of \(\left[\mathrm{NH}_{4}^{+}\right]\)ions as well as conc. \(\left[\mathrm{OH}^{-}\right]\)ions increase. (d) Conc. of \(\left[\mathrm{NH}_{4}^{+}\right]\)ions decreases.
Step-by-Step Solution
Verified Answer
(a) The concentration of \([\mathrm{OH}^-]\) ions decreases.
1Step 1: Understanding the Chemical Reaction
In an aqueous solution of \(\mathrm{NH}_4\mathrm{OH}\), \(\mathrm{NH}_4\mathrm{OH}\) partially dissociates into \(\mathrm{NH}_4^+\) and \(\mathrm{OH}^-\) ions due to its weak base nature. The equilibrium can be represented as:\[\mathrm{NH}_4\mathrm{OH} \rightleftharpoons \mathrm{NH}_4^+ + \mathrm{OH}^-\] Adding \(\mathrm{NH}_4\mathrm{Cl}\), which dissociates completely, will increase the concentration of \(\mathrm{NH}_4^+\) ions in the solution.
2Step 2: Applying the Common Ion Effect
The increase in concentration of \(\mathrm{NH}_4^+\) ions due to the addition of \(\mathrm{NH}_4\mathrm{Cl}\) will shift the equilibrium of the dissociation of \(\mathrm{NH}_4\mathrm{OH}\) to the left according to Le Chatelier's principle. This means there will be a decrease in the concentration of \(\mathrm{OH}^-\) ions in the solution.
3Step 3: Analyzing the Ion Concentrations
Since the equilibrium shifts to the left, the \(\mathrm{OH}^-\) ion concentration will decrease, while the \(\mathrm{NH}_4^+\) concentration is higher initially due to \(\mathrm{NH}_4\mathrm{Cl}\) addition. Therefore, the statement that matches this scenario is that the concentration of \([\mathrm{OH}^-]\) ions decreases.
Key Concepts
Le Chatelier's principleChemical equilibriumIon concentration changes
Le Chatelier's principle
Le Chatelier's principle is a fascinating concept in chemistry that helps us predict how changing conditions affect chemical equilibria. Imagine a group of acrobats perfectly balanced on a see-saw. If someone tips the see-saw to one side, the acrobats will shift to maintain their balance. Similarly, this principle states that if a stress is applied to a system at equilibrium, the system will shift in a direction that counteracts this stress, striving to restore equilibrium. When additional \(\mathrm{NH}_4^{+}\) ions from \(\mathrm{NH}_4 ext{Cl}\) are added to the solution, the reaction shifts to consume some of these excess ions, thereby decreasing the concentration of \([\mathrm{OH}^-\)] ions.
- This shift to the left (towards Reactants) occurs because the equilibrium tries to minimize the effect of the added common ion.
- In our exercise, it reduces the hydroxide ion concentration while effectively rebalancing the system.
Chemical equilibrium
Chemical equilibrium is a state within a chemical reaction where the concentrations of reactants and products cease to change. At equilibrium, the rate at which the reactants convert into products is equal to the rate at which products convert back into reactants. This dynamic balance is vital as it helps in understanding reaction properties and controlling industrial processes.
When \(\mathrm{NH}_4 ext{OH}\) dissociates, it establishes a chemical equilibrium with its ions:\[\mathrm{NH}_4 ext{OH} \rightleftharpoons \mathrm{NH}_4^+ + \mathrm{OH}^-\]
When \(\mathrm{NH}_4 ext{OH}\) dissociates, it establishes a chemical equilibrium with its ions:\[\mathrm{NH}_4 ext{OH} \rightleftharpoons \mathrm{NH}_4^+ + \mathrm{OH}^-\]
- The state of equilibrium signifies that, though reactions are still occurring, there is no net change in concentration.
- This balance is sensitive to outside influences, such as the addition of \(\mathrm{NH}_4 ext{Cl}\), which shifts the equilibrium, showing how chemicals can interact in a closed loop of reactions.
Ion concentration changes
The concentration of ions in a solution is a key factor in determining the behavior and properties of the solution. When another compound is added to a solution at equilibrium, concentrations of ions can change significantly due to the common ion effect.
- The common ion effect occurs when a salt containing an ion already present in the solution is added, affecting the solubility of compounds and the equilibrium state. For instance, adding \(\mathrm{NH}_4 ext{Cl}\) increases \(\mathrm{NH}_4^+\) ions.
- This addition can lead to a decrease in \([\mathrm{OH}^-\)] ion concentration due to a shift in equilibrium, based on Le Chatelier's principle.
Other exercises in this chapter
Problem 148
The solubility product of \(\mathrm{PbI}_{2}\) is \(7.47 \times 10^{-9}\) at \(15^{\circ} \mathrm{C}\) and \(1.39 \times 10^{\mathrm{s}}\) at \(25^{\circ} \math
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At what concentration of \(\mathrm{CH}_{3} \mathrm{COOH}\) will the \(\left[\mathrm{H}^{+}\right]\) obtained will be same as that obtained from \(10^{-2} \mathr
View solution Problem 153
\(500 \mathrm{ml}\) of \(0.2 \mathrm{M} \mathrm{HCl}\) is mixed with \(500 \mathrm{ml}\) of \(0.2 \mathrm{M}\) \(\mathrm{CH}_{3} \mathrm{COOH} .25 \mathrm{ml}\)
View solution Problem 154
When \(60 \mathrm{ml}\) of \(0.1 \mathrm{M} \mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\) is mixed with \(40 \mathrm{ml}\) of \(0.125 \mathrm{M} \mathrm{Na}_{2}
View solution