Problem 152
Question
The color of \(\mathrm{KMnO}_{4}\) is due to (a) \(\mathrm{M} \rightarrow \mathrm{L}\) charge transfer transition (b) \(\mathrm{d}-\mathrm{d}\) transition (c) \(\mathrm{L} \rightarrow \mathrm{M}\) charge transfer transition (d) \(\sigma-\sigma^{*}\) transition
Step-by-Step Solution
Verified Answer
\(\mathrm{KMnO}_{4}\) color is due to (c). \(\mathrm{L} \rightarrow \mathrm{M}\) charge transfer transition.
1Step 1: Understanding Charge Transfer Transitions
In a charge transfer transition, electrons are transferred between the metal and the ligand. There are two types: Metal to Ligand Charge Transfer (MLCT) and Ligand to Metal Charge Transfer (LMCT). In MLCT, the electron moves from the metal to the ligand, while in LMCT, it moves from the ligand to the metal.
2Step 2: Analyze \\(\mathrm{KMnO}_{4}\\) Composition
The compound \(\mathrm{KMnO}_{4}\) consists of potassium (K), manganese (Mn), and oxygen (O). Manganese in \(\mathrm{KMnO}_{4}\) is in a high oxidation state (\(+7\)), with no d-electrons available to participate in a \(d-d\) transition. As a result, \(d-d\) transition can be ruled out.
3Step 3: Determine Likely Origin of Color
Since \(d-d\) transition is not possible, examine charge transfer types. In \(\mathrm{KMnO}_{4}\), due to manganese’s high oxidation state, it is more likely for electron transfer from the oxygen ligand to manganese (LMCT) leading to absorption in the visible region and hence color formation.
Key Concepts
Charge Transfer TransitionKMnO4 ColorOxidation States in Mn Compounds
Charge Transfer Transition
Charge transfer transitions play a vital role in the coloration of various inorganic compounds. These transitions occur when an electron moves between a metal and a ligand. In essence, there are two main types of charge transfer transitions:
- Metal to Ligand Charge Transfer (MLCT): Here, electrons are transferred from the metal to the ligand. This transition is common in compounds where the metal is in a lower oxidation state.
- Ligand to Metal Charge Transfer (LMCT): In this transition, electrons move from the ligand to the metal, typically observed when the metal is in a high oxidation state.
KMnO4 Color
The deep purple color of potassium permanganate \(\mathrm{KMnO}_{4}\) is intriguing and is a classic example of how ligand to metal charge transfer (LMCT) can cause vivid coloration. In \(\mathrm{KMnO}_{4}\), manganese exists in a high oxidation state of \(+7\). This elevated oxidation state means there are no d-electrons available for typical \(d-d\) transitions, which can often contribute to color in transition metals. Instead, the striking purple hue of \(\mathrm{KMnO}_{4}\) arises from LMCT, where electrons are transferred from oxygen ligands to the manganese center.
Because the manganese is in such a high oxidation state, its ability to accept electrons from the oxygen (ligand) becomes the primary mechanism for electronic transitions. This transfer happens when the compound absorbs certain wavelengths of visible light, with the remaining light being the color we perceive. Thus, in simple terms, the purple shade is the result of which wavelengths of light are absorbed and which are not, due to LMCT.
Because the manganese is in such a high oxidation state, its ability to accept electrons from the oxygen (ligand) becomes the primary mechanism for electronic transitions. This transfer happens when the compound absorbs certain wavelengths of visible light, with the remaining light being the color we perceive. Thus, in simple terms, the purple shade is the result of which wavelengths of light are absorbed and which are not, due to LMCT.
Oxidation States in Mn Compounds
Manganese is a versatile element, capable of showing a range of oxidation states, from \(+2\) to \(+7\). This property significantly influences the behavior and properties of its compounds. Here are some key points regarding oxidation states in manganese compounds:
- Low Oxidation States (e.g., \(+2\), \(+3\)): In these states, manganese can often participate in \(d-d\) transitions, contributing to the color and magnetic properties of the compounds.
- High Oxidation States (e.g., \(+6\), \(+7\)): As seen in \(\mathrm{KMnO}_{4}\), higher oxidation states typically lack d-electrons for \(d-d\) transitions. These compounds often exhibit colors resulting from ligand to metal charge transfer, as they can accept electrons from ligands.
Other exercises in this chapter
Problem 150
Which of the following arrangements does not represent the correct order of the property stated against it? (a) \(\mathrm{Co}^{3+}
View solution Problem 151
Four successive member of the first now transition elements are listed below with atoms number. Which one of them is expected to have the highest \(\mathrm{E}_{
View solution Problem 153
Which of the following atoms has the highest first Ionization energy? (a) \(\mathrm{Na}\) (b) \(\mathrm{K}\) (c) \(\mathrm{Sc}\) (d) \(\mathrm{Rb}\)
View solution Problem 149
In context of the lanthanoids, which of the follwoing statements is not correct? (a) Availability of 4f electrons results in the formation of compound in \(+4\)
View solution