Problem 151
Question
The equilibrium constants for the reactions \(\mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3}\) and \(\frac{1}{2} \mathrm{~N}_{2}+\frac{3}{2} \mathrm{H}_{2} \rightleftharpoons \mathrm{NH}_{3}\) are \(K_{1}\) and \(K_{2}\) respectively. The correct relationship between \(\mathrm{K}_{1}\) and \(\mathrm{K}\), is (a) \(\mathrm{K}_{1}=\frac{\mathrm{K}_{2}}{2}\) (b) \(\mathrm{K}_{2}=\sqrt{\mathrm{K}_{\mathrm{t}}}\) (c) \(\mathrm{K}_{2}=\mathrm{K}_{1}^{2}\) (d) \(\mathrm{K}_{1}=\mathrm{K}_{2}\)
Step-by-Step Solution
Verified Answer
The correct relationship is (b) \(\mathrm{K}_{2}=\sqrt{\mathrm{K}_{1}}\).
1Step 1: Understanding Equilibrium Constants
Equilibrium constants describe the ratio of the concentration of reactants and products at equilibrium for a given reaction at a specific temperature. Changing the coefficients in the balanced reaction affects the equilibrium constant for the reaction.
2Step 2: Reaction Comparison
The reaction \( \mathrm{N}_{2}+3 \mathrm{H}_{2} \rightleftharpoons 2 \mathrm{NH}_{3} \) has the equilibrium constant \( K_1 \). The second reaction \( \frac{1}{2} \mathrm{~N}_{2}+\frac{3}{2} \mathrm{H}_{2} \rightleftharpoons \mathrm{NH}_{3} \) is simply the first reaction divided by 2. This means the second reaction has half the number of moles of reactants and products.
3Step 3: Relation Between Reactions
When a reaction is multiplied or divided by a coefficient in a balanced equation, the equilibrium constant changes. Specifically, when a reaction is divided by a coefficient, the new equilibrium constant is the original constant raised to the inverse of that coefficient. In this case, since the second reaction is the first reaction divided by 2, \( K_2 = (K_1)^{1/2} \).
4Step 4: Answer Interpretation
By comparing the relationship we derived (\(K_2 = \sqrt{K_1} \)) to the given options, it corresponds to option (b): \( \mathrm{K}_{2}=\sqrt{\mathrm{K}_{1}} \).
Key Concepts
Chemical EquilibriumReaction CoefficientsEquilibrium Expressions
Chemical Equilibrium
Chemical equilibrium refers to the state in a chemical reaction where the concentrations of reactants and products become constant. This occurs when the forward and reverse reactions proceed at the same rate. It's important to note that at equilibrium, the reaction doesn't stop. Rather, it continues with no net change in the concentrations of substances.
- At the start, reactants are converted into products until equilibrium is reached.
- At equilibrium, reactions proceed in both directions, maintaining a constant ratio of reactants to products.
Reaction Coefficients
Reaction coefficients are the numbers placed in front of compounds in a balanced chemical equation. They indicate the relative amounts of reactants and products involved in the reaction. Changing these coefficients affects the equilibrium constant of a reaction.
- If a reaction is multiplied by a factor, the equilibrium constant is raised to the power of that factor.
- If a reaction is divided by a factor, the equilibrium constant is taken to the root equivalent to that factor.
Equilibrium Expressions
An equilibrium expression is a formula that relates the concentrations of reactants and products of a reaction at equilibrium. For a general reaction:\[aA + bB \rightleftharpoons cC + dD\]the equilibrium expression is:\[K = \frac{[C]^c[D]^d}{[A]^a[B]^b}\]
- Concentrations of products are in the numerator, and reactants in the denominator.
- Each concentration is raised to the power of its coefficient in the balanced equation.
Other exercises in this chapter
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