Problem 151
Question
\(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{NH}_{2}+\mathrm{CHCl}_{3}+3 \mathrm{KOH}\) \(\mathrm{A}+\mathrm{B}+3 \mathrm{H}_{2} \mathrm{O}\) Here compound \(\mathrm{A}\) and \(\mathrm{B}\) are respectively? (a) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{CN}\) and \(3 \mathrm{KCl}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CONH}_{2}\) and \(\mathrm{KCl}\) (c) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NC}\) and \(3 \mathrm{KCl}\) (d) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NC}\) and \(\mathrm{K}_{2} \mathrm{CO}_{3}\)
Step-by-Step Solution
Verified Answer
(c) \(\mathrm{C}_{2}\mathrm{H}_{5}\mathrm{NC}\) and \(3\mathrm{KCl}\).
1Step 1: Identify the Reaction Type
This is an example of a Hoffmann degradation reaction, where a primary amine reacts with chloroform and a strong base (such as KOH) to form an isocyanide (or carbylamine) compound. Here, the primary amine is \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{NH}_{2}\).
2Step 2: Analyze the Reagents
The reagents given are chloroform \(\mathrm{CHCl}_{3}\) and potassium hydroxide \(\mathrm{KOH}\). In this reaction, \(\mathrm{KOH}\) promotes the conversion of the amine into an isocyanide through dehydration and substitution steps.
3Step 3: Determine the Products by Reaction Mechanism
When \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{NH}_{2}\) reacts with \(\mathrm{CHCl}_{3}\) and \(3\mathrm{KOH}\), an isocyanide is formed, specifically \(\mathrm{C}_{2}\mathrm{H}_{5}\mathrm{NC}\). The side products include \(3\mathrm{KCl}\) and water.
4Step 4: Choose the Correct Pair of Products
The reaction results in \(\mathrm{C}_{2}\mathrm{H}_{5}\mathrm{NC}\) and \(3\mathrm{KCl}\), which matches option (c) of the given answers.
Key Concepts
Primary AmineIsocyanide FormationReaction Mechanism
Primary Amine
Understanding primary amines is crucial when exploring the Hoffmann degradation reaction. Primary amines are organic compounds that contain an amino group
Primary amines are essential in organic reactions because they can react in various ways, including forming bonds with carbon atoms. In the Hoffmann degradation reaction, the primary amine serves as the starting material, reacting with other reagents to produce more complex products.
- They have a general formula of \(RNH_2\). Here, \(R\) represents an alkyl or aryl group.
- In this reaction, the primary amine is \( extit{CH}_3- extit{CH}_2- extit{NH}_2\).
Primary amines are essential in organic reactions because they can react in various ways, including forming bonds with carbon atoms. In the Hoffmann degradation reaction, the primary amine serves as the starting material, reacting with other reagents to produce more complex products.
Isocyanide Formation
Isocyanide formation is a fascinating outcome of the Hoffmann degradation reaction.
- Isocyanides, also called carbylamines, are compounds with the functional group \(\(-N\equiv C\)\).
- They exhibit unique properties like a distinct, pungent smell.
- In the given reaction, the primary amine \(\( extit{CH}_3- extit{CH}_2- extit{NH}_2\)\) reacts to form the isocyanide compound \(\( extit{C}_2 extit{H}_5 extit{NC}\)\).
Reaction Mechanism
A detailed look at the reaction mechanism sheds light on how the Hoffmann degradation reaction occurs.
Potassium hydroxide not only assists in the deprotonation of amines but also plays a role in generating the intermediate species needed for further reaction progression.
- The reaction is initiated by a deprotonation step, where the strong base (KOH) removes a hydrogen from the primary amine.
- This step creates a negatively charged amide ion (\( extit{RNH}^-\)), which is highly reactive.
Potassium hydroxide not only assists in the deprotonation of amines but also plays a role in generating the intermediate species needed for further reaction progression.
- The final products, in this case, include isocyanide \(\( extit{C}_2 extit{H}_5 extit{NC}\)\) and salt byproducts like potassium chloride \(\(3 extit{KCl}\)\).
Other exercises in this chapter
Problem 148
An organic compound having molecular mass 60 is found to contain \(\mathrm{C}=20 \%, \mathrm{H}=6.67 \%\) and \(\mathrm{N}=\) \(46.67 \%\) while rest is oxygen.
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Which one of the following methods is neither meant for the synthesis nor for separation of amines? \([\mathbf{2 0 0 5}]\) (a) Hinsberg method (b) Hoffmann meth
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