Problem 151
Question
Assertion The SI unit of Stefan's constant is \(\mathrm{Wm}^{-2} \mathrm{~K}^{-4}\). Reason This follows from Stefan's Law, \(\therefore\) $$ \begin{aligned} E &=\alpha T^{4} \\ \alpha &=\frac{E}{T^{4}}=\frac{\mathrm{Wm}^{-2}}{\mathrm{~K}^{4}} \end{aligned} $$
Step-by-Step Solution
Verified Answer
The SI unit for Stefan's constant is correctly derived as \( \mathrm{Wm}^{-2} \mathrm{~K}^{-4} \).
1Step 1: Identifying the Assertion
The assertion claims that the SI unit of Stefan's constant, often denoted as \( \sigma \), is \( \mathrm{Wm}^{-2} \mathrm{~K}^{-4} \).
2Step 2: Understanding Stefan's Law
Stefan's Law states that the total energy radiated per unit surface area of a black body per unit time (energy per unit area per unit time, \( E \)) is proportional to the fourth power of the black body's thermodynamic temperature \( T \). This law is expressed mathematically as \( E = \sigma T^4 \).
3Step 3: Deriving the Units from Stefan's Law
According to Stefan's Law, \( E = \sigma T^4 \). Rearranging the formula gives \( \sigma = \frac{E}{T^4} \). Therefore, the unit of \( \sigma \) can be derived from the units of \( E \) and \( T \).
4Step 4: Analyzing Units for Energy and Temperature
In the equation \( \sigma = \frac{E}{T^4} \), \( E \) has units of \( \mathrm{Wm}^{-2} \), where \( \mathrm{W} \) represents watts (power) and \( m \) represents meters (area). \( T \) has units of \( \mathrm{K} \) (kelvin). Thus, \( T^4 \) has units of \( \mathrm{K}^4 \).
5Step 5: Final Unit Calculation for Stefan's Constant
Substituting the units into \( \sigma = \frac{E}{T^4} \) gives us \( \sigma = \frac{\mathrm{Wm}^{-2}}{\mathrm{K}^4} \). Thus, the unit for Stefan's constant is indeed \( \mathrm{Wm}^{-2} \mathrm{~K}^{-4} \).
Key Concepts
Stefan's ConstantSI units in PhysicsBlack Body Radiation
Stefan's Constant
Stefan's constant, symbolized as \( \sigma \), plays a crucial role in the realm of thermodynamics and black body radiation. Stefan's Law, formally known as the Stefan-Boltzmann Law, uses this constant to express the relationship between the radiant energy emitted by a black body and its temperature. More specifically, Stefan's constant helps to define how much energy a perfect black body emits per square meter of its surface area at a certain temperature.One can picture it as a key factor that bridges the gap between temperature and energy emission according to the formula: - \( E = \sigma T^4 \) - Where \( E \) is the energy emitted per unit area per unit time, and \( T \) is the absolute temperature of the black body in Kelvin. The proportionality factor, \( \sigma \), ensures that this relationship is quantitatively correct, making it indispensable for calculating energy outputs in physics.
SI units in Physics
Understanding units in physics, particularly in the International System of Units (SI), is essential for precise measurement and communication. In the context of Stefan's constant, it's important to breakdown its derived SI unit: \( \mathrm{Wm}^{-2} \mathrm{K}^{-4} \). Here's how it unfolds:
- Watts (\( \mathrm{W} \)): Reflect power, or the rate of energy transfer.
- Meters squared (\( \mathrm{m}^{-2} \)): Denotes the area over which this power is distributed.
- Kelvin to the fourth power (\( \mathrm{K}^{-4} \)): Relates to temperature, encapsulating how energy emission scales with the fourth power of temperature.
Black Body Radiation
Black body radiation is a fundamental concept in physics that explains how objects emit electromagnetic radiation. A "black body" is a theoretical object that absorbs all incident radiation without reflecting any light, making it an ideal emitter.
Why is black body radiation important? Here's why:
- It provides a model to understand other types of radiative objects, as real objects can usually be approximated as black bodies.
- Black bodies emit radiation at all frequencies, and the intensity of emission is dependent on temperature. This helps in understanding thermal emissions from stars and other astronomical bodies.
- The behavior of a black body as described by Stefan-Boltzmann Law shows how energy radiated is proportional to the fourth power of the body's temperature, which is crucial in fields like astrophysics and climate science.
Other exercises in this chapter
Problem 144
Heat released when \(10 \mathrm{~g}\) of steam at \(100^{\circ} \mathrm{C}\) cools to water at \(100^{\circ} \mathrm{C}\) is (a) \(540 \mathrm{cal}\) (b) \(54 \
View solution Problem 145
Heat released when \(10 \mathrm{~g}\) of steam at \(100^{\circ} \mathrm{C}\) cools to water at \(100^{\circ} \mathrm{C}\) is (a) \(540 \mathrm{cal}\) (b) \(54 \
View solution Problem 153
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View solution Problem 154
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