Problem 150
Question
Verify that each equation is an identity. \(\frac{\sin x}{\cos x+1}+\frac{\cos x-1}{\sin x}=0\)
Step-by-Step Solution
Verified Answer
The equation is an identity because both sides equal zero for defined \(x\).
1Step 1: Understand the Given Equation
We need to verify if the given equation \( \frac{\sin x}{\cos x+1}+\frac{\cos x-1}{\sin x}=0 \) is an identity. An identity is true for all values of \(x\) where both sides of the equation are defined.
2Step 2: Establish Common Denominator
The given equation has two separate fractions. In order to combine them, we need a common denominator. For both fractions, use the product \((\cos x + 1)(\sin x)\) as the common denominator.
3Step 3: Rewrite Each Fraction with Common Denominator
Rewrite the fractions with the common denominator:\[\frac{\sin x}{\cos x + 1} = \frac{\sin^2 x}{(\cos x + 1)\sin x}\]\[\frac{\cos x - 1}{\sin x} = \frac{(\cos x - 1)(\cos x + 1)}{(\cos x + 1)\sin x}\]These transformations are valid because we're multiplying the numerator and the denominator by the same terms.
4Step 4: Simplify Each Fraction
Now expand and simplify each fraction:- The first term becomes \( \frac{\sin^2 x}{(\cos x + 1)\sin x} \).- For the second term, use the identity \((\cos x - 1)(\cos x + 1) = \cos^2 x - 1^2 = \cos^2 x - 1\). This becomes \( \frac{\cos^2 x - 1}{(\cos x + 1)\sin x} \).
5Step 5: Combine and Simplify
Combine the fractions:\[\frac{\sin^2 x}{(\cos x + 1)\sin x} + \frac{\cos^2 x - 1}{(\cos x + 1)\sin x} = \frac{\sin^2 x + \cos^2 x - 1}{(\cos x + 1)\sin x} \]Use the Pythagorean identity \(\sin^2 x + \cos^2 x = 1\) which simplifies the numerator: \[1 - 1 = 0\]
6Step 6: Verify Result
Since the numerator becomes zero, the entire expression simplifies to:\[\frac{0}{(\cos x + 1)\sin x} = 0\]Thus, the original equation is an identity as it holds true for any \(x\) where the functions are defined.
Key Concepts
Pythagorean IdentityCommon DenominatorFractions Simplification
Pythagorean Identity
The Pythagorean Identity is a fundamental concept in trigonometry. It states that for any angle \(x\), the square of the sine of \(x\) plus the square of the cosine of \(x\) will always equal 1. This is expressed mathematically as:
In this exercise, we used the Pythagorean Identity to simplify the equation:
- \( \sin^2 x + \cos^2 x = 1 \)
In this exercise, we used the Pythagorean Identity to simplify the equation:
- Replace \(\sin^2 x + \cos^2 x\) in the numerator with 1.
- The rest of the expression can then be simplified further.
Common Denominator
A common denominator is crucial when adding or subtracting fractions. It allows multiple fractions to be combined into a single expression.
In our problem, we have two fractions with different denominators:
This method helps because it covers both original denominators and allows the fractions to be:
In our problem, we have two fractions with different denominators:
- \( \frac{\sin x}{\cos x + 1} \)
- \( \frac{\cos x - 1}{\sin x} \)
This method helps because it covers both original denominators and allows the fractions to be:
- Rewritten with the same denominator \((\cos x + 1)\sin x\).
- Easily combined into a single fraction.
Fractions Simplification
Simplifying fractions involves reducing fractions to their simplest form. This often includes:
- Multiplying or dividing the numerator and the denominator by the same value.
- Using identities or properties to simplify terms.
- Multiply and simplify: Each fraction is adjusted to have the common denominator, making it possible to combine them.
- Simplification with identities: By invoking the identity \((\cos x - 1)(\cos x + 1) = \cos^2 x - 1\), further letting us simplify.
- Use of the Pythagorean identity: After combining, simplify \(\sin^2 x + \cos^2 x - 1\) to 0, since \(\sin^2 x + \cos^2 x = 1\).
Other exercises in this chapter
Problem 149
Verify that each equation is an identity. \(\frac{\sin t}{\csc t}+\frac{\cos t}{\sec t}=1\)
View solution Problem 150
For the following exercises, verify that each equation is an identity. $$\frac{\sin x}{\cos x+1}+\frac{\cos x-1}{\sin x}=0$$
View solution Problem 151
For the following exercises, verify that each equation is an identity. $$\cot \gamma+\tan \gamma=\sec \gamma \csc \gamma$$
View solution Problem 151
Verify that each equation is an identity. \(\quad \cot \gamma+\tan \gamma=\sec \gamma \csc \gamma\)
View solution