Problem 150
Question
The specific heat of copper is \(0.385 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\). How much heat energy in kilojoules is required to raise the temperature of \(454 \mathrm{~g}\) of copper from \(40.0{ }^{\circ} \mathrm{C}\) to \(75.0^{\circ} \mathrm{C} ?\)
Step-by-Step Solution
Verified Answer
The amount of heat energy required to raise the temperature of \(454 \mathrm{~g}\) of copper from \(40.0{ }^{\circ}
\mathrm{C}\) to \(75.0^{\circ} \mathrm{C}\) is approximately \(6.198 \mathrm{~kJ}\).
1Step 1: Identify the given values
In this exercise, we are given:
- Specific heat capacity of copper (c) = 0.385 J/g°C
- Mass of copper (m) = 454 g
- Initial temperature (T1) = 40.0°C
- Final temperature (T2) = 75.0°C
2Step 2: Calculate the temperature change (ΔT)
To find the change in temperature, we can use the formula ΔT = T2 - T1:
ΔT = 75.0°C - 40.0°C = 35.0°C
3Step 3: Apply the heat transfer formula
We can now use the heat transfer formula, Q = mcΔT, to find the heat energy required to raise the temperature of the copper:
Q = (454 g) × (0.385 J/g°C) × (35.0°C)
4Step 4: Calculate the heat energy
Multiply the values obtained in step 3:
Q = 454 × 0.385 × 35
Q = 6197.9 J
5Step 5: Convert the heat energy to kilojoules
Since we want the result in kilojoules, we must convert the heat energy from joules to kilojoules:
1 Joule = 0.001 Kilojoules
Thus,
Q = 6197.9 J × 0.001 kJ/J = 6.1979 kJ
The amount of heat energy required to raise the temperature of 454 g of copper from 40.0°C to 75.0°C is approximately 6.198 kJ.
Key Concepts
Heat TransferTemperature Change CalculationEnergy Conversion
Heat Transfer
Heat transfer is the process by which thermal energy moves from one material or substance to another. This can occur in three primary ways: conduction, when heat moves through a solid material; convection, which involves fluid or gas currents carrying heat; and radiation, where heat is transferred in the form of electromagnetic waves. In the context of our exercise, we're dealing with conduction, focusing on the transfer of heat through the metal, copper.
When a substance like copper is heated, its particles begin to vibrate more quickly and the energy is passed along from one particle to the next, resulting in an overall increase in temperature. It is important to realize that during this process, the amount of heat transferred depends on the specific heat capacity of the substance, its mass, and the temperature change. The specific heat capacity is a measure of how much energy is required to raise the temperature of one gram of a substance by one degree Celsius, often reflecting a material's ability to store heat.
When a substance like copper is heated, its particles begin to vibrate more quickly and the energy is passed along from one particle to the next, resulting in an overall increase in temperature. It is important to realize that during this process, the amount of heat transferred depends on the specific heat capacity of the substance, its mass, and the temperature change. The specific heat capacity is a measure of how much energy is required to raise the temperature of one gram of a substance by one degree Celsius, often reflecting a material's ability to store heat.
Temperature Change Calculation
Understanding temperature change is vital when dealing with heat transfer problems. The temperature change, denoted as \( \Delta T \), is calculated by finding the difference between the final and initial temperatures. In our exercise, we've calculated \( \Delta T \) to be \( 75.0^{\circ}C \) minus \( 40.0^{\circ}C \) resulting in a \( 35.0^{\circ}C \) increase in temperature.
As \( \Delta T \) represents the net change, whether the temperature rises or falls, the sign is crucial in determining the direction of heat flow. In this scenario, because the temperature increases, the heat flow is positive, meaning energy is being absorbed by the copper to elevate its temperature.
As \( \Delta T \) represents the net change, whether the temperature rises or falls, the sign is crucial in determining the direction of heat flow. In this scenario, because the temperature increases, the heat flow is positive, meaning energy is being absorbed by the copper to elevate its temperature.
Energy Conversion
Energy conversion, in thermodynamics, is the change of energy from one form to another. In our example, electrical energy provided by a heat source, such as a stove, is converted into thermal energy within the copper. This thermal energy is absorbed by the copper's particles, causing an increase in kinetic energy and, hence, an increase in temperature.
The formula \( Q = mc\Delta T \) that we use in the exercise assists in quantifying this energy conversion, where \( Q \) denotes the amount of heat energy in joules, \( m \) is the mass in grams, \( c \) is the specific heat capacity, and \( \Delta T \) is the temperature change in degrees Celsius. By calculating the energy required to achieve a certain temperature change, we are effectively bridging the gap between the abstract energy conversion and a tangible number, allowing us to understand and predict the outcomes of heating or cooling substances.
The formula \( Q = mc\Delta T \) that we use in the exercise assists in quantifying this energy conversion, where \( Q \) denotes the amount of heat energy in joules, \( m \) is the mass in grams, \( c \) is the specific heat capacity, and \( \Delta T \) is the temperature change in degrees Celsius. By calculating the energy required to achieve a certain temperature change, we are effectively bridging the gap between the abstract energy conversion and a tangible number, allowing us to understand and predict the outcomes of heating or cooling substances.
Other exercises in this chapter
Problem 148
A student measures the mass of an object three times and reports the numeric average of her measurements. If her three measurements are \(212 \mathrm{~g}\), \(2
View solution Problem 149
The density of an irregularly shaped object is determined by immersing the object in water. If the mass of the object is \(8.34 \mathrm{~g}\) and the water leve
View solution Problem 152
Express \(23,000,000\) in scientific notation having: (a) Two significant figures (b) Three significant figures (c) Five significant figures (d) Six significant
View solution Problem 153
Dieters are often told that drinking ice-cold water burns more energy than drinking roomtemperature water. Why is this true?
View solution