Problem 15
Question
Write Lewis structures for the following molecules, and then label each \(\sigma\) and \(\pi\) bond. (a) \(\mathrm{HCN} ;\) (b) \(\mathrm{C}_{2} \mathrm{N}_{2}\) (c) \(\mathrm{CH}_{3} \mathrm{CHCHCCl}_{3} ;\) (d) HONO.
Step-by-Step Solution
Verified Answer
The Lewis structures of the molecules are: (a) H-C≡N (b) \(-C≡C-)-N=N- (c) H_3C-CHCHCCl_3 (d) H-O-N=O. In (a), there are two \(\sigma\) bonds and two \(\pi\) bonds; in (b), there are three \(\sigma\) bonds and four \(\pi\) bonds; in (c), there are nine \(\sigma\) bonds and no \(\pi\) bonds; and in (d), there are three \(\sigma\) bonds and one \(\pi\) bond.
1Step 1: Draw Lewis Structures
A Lewis structure is a visual representation of the molecule that shows how the valence electrons are distributed among the atoms in the molecule. Lewis structures can be drawn for each of the molecules as follows: (a) \( \mathrm{HCN} \) (b) \(\mathrm{C}_{2} \mathrm{N}_{2}\) (c) \(\mathrm{CH}_{3} \mathrm{CHCHCCl}_{3}\) (d) HONO.
2Step 2: Identify Sigma and Pi Bonds
Each molecule can now be examined for sigma (\(\sigma\)) and pi (\(\pi\)) bonds. A sigma bond (\(\sigma\)) bond is formed by the end-to-end overlapping and Pi bond (\(\pi\)) is formed by the lateral or side by side overlapping of atomic orbitals. In each molecule, single bonds represent \(\sigma\) bonds. Each double bond has one \(\sigma\) and one \(\pi\) bond while each triple bond has one \(\sigma\) and two \(\pi\) bonds.
3Step 3: Label Sigma and Pi Bonds
Now each bond in the molecule is labelled as either a sigma (\(\sigma\)) or pi (\(\pi\)) bond based on the type of overlap forming the bond. Label each single bond as a \(\sigma\) bond. Label one of the bonds in a double bond as a \(\sigma\) bond and the other as a \(\pi\) bond. For a triple bond, label one of the bonds as a \(\sigma\) bond and the other two as \(\pi\) bonds.
Key Concepts
Understanding Sigma BondsThe Role of Pi BondsValence Electrons Distribution Demystified
Understanding Sigma Bonds
A sigma bond, often denoted as \( \sigma \), is the strongest type of covalent bond, formed by the head-on overlap of orbitals from two atoms. This overlap occurs along the axis connecting the two nuclei, making the \( \sigma \) bond symmetrical around this axis, which provides stability, allowing for free rotation of the bonded atoms.
- Single bonds are almost always sigma bonds due to the strong overlap.
- In multiple bonds, such as double or triple bonds, there is always exactly one sigma bond, with the others being pi bonds.
The Role of Pi Bonds
Pi bonds, depicted as \( \pi \) bonds, are formed from the side-to-side overlap of orbitals. These bonds are weaker than sigma bonds, as the overlap is less extensive compared to the end-to-end overlap.
- A single pi bond is present in double bonds.
- Triple bonds contain two pi bonds along with a sigma bond.
Valence Electrons Distribution Demystified
When drawing Lewis structures, it's crucial to understand how valence electrons are distributed among atoms in a molecule. Valence electrons are responsible for the bonding and chemical properties of an element.
- Lewis structures aim to show how valence electrons pair and form bonds.
- They help in visualizing the distribution of electrons and the kinds of bonds— like sigma or pi— present in the molecule.
Other exercises in this chapter
Problem 12
Propose a hybridization scheme to account for bonds formed by the central carbon atom in each of the following molecules: (a) hydrogen cyanide, HCN; (b) methyl
View solution Problem 13
Indicate which of the following molecules and ions are linear, which are planar, and which are neither. Then propose hybridization schemes for the central atoms
View solution Problem 16
Represent bonding in the carbon dioxide molecule, \(\mathrm{CO}_{2},\) by \((\mathrm{a})\) a Lewis structure and \((\mathrm{b})\) the valencebond method. Identi
View solution Problem 24
The structure of the molecule allene, \(\mathrm{CH}_{2} \mathrm{CCH}_{2}\), is shown here. Propose hybridization schemes for the \(C\) atoms in this molecule.
View solution