Problem 15
Question
Write an equation for each translation. $$ x^{2}+y^{2}=20 ; \text { left } 6 \text { and up } 1 $$
Step-by-Step Solution
Verified Answer
The equation of the circle after translation is \((x+6)^{2}+(y-1)^{2}=20\).
1Step 1: Translate Left
To translate the circle 6 units to the left, we substitute \(x+6\) for \(x\). So the equation becomes \((x+6)^{2}+y^{2}=20\).
2Step 2: Translate Up
To translate the circle 1 unit up, we substitute \(y-1\) for \(y\). Now the translated equation becomes \((x+6)^{2}+(y-1)^{2}=20\).
3Step 3: Final Equation
The final equation of the circle after being translated 6 units left and 1 unit up is \((x+6)^{2}+(y-1)^{2}=20\).
Key Concepts
Translations of FunctionsCoordinate ShiftsAlgebraic Transformations
Translations of Functions
Translations of functions are a fundamental concept in algebra that allow us to shift a graph along the coordinate plane without altering its shape. This is crucial when working with the equation of a circle, such as the one given in the original exercise.
When we talk about translating a function, we mean moving it either horizontally or vertically on the graph:
- Horizontal translation shifts the graph left or right.
- Vertical translation moves the graph up or down.
Coordinate Shifts
Coordinate shifts refer to alterations made to the coordinates of the function's graph. These are expressed algebraically in the equation of the function.The circle's equation \[x^{2} + y^{2} = 20\]can be readjusted using coordinate shifts as specified in the exercise:
- To shift the circle left by 6 units, substitute \(x+6\) for \(x\). The equation becomes \((x+6)^{2} + y^{2} = 20\).
- To shift the circle up by 1 unit, substitute \(y-1\) for \(y\). The equation transitions to \((x+6)^{2} + (y-1)^{2} = 20\).
Algebraic Transformations
Algebraic transformations are operations that alter an algebraic equation to represent shifts, stretches, or other changes in the graph of a function. Specifically, these transformations are applied to the variable terms in the equation.In our specific problem, we applied a transformation to translate the circle. It involved:
- Adding 6 inside the squared term for \(x\), resulting in \((x+6)^{2}\), to move it 6 units left.
- Subtracting 1 inside the squared term for \(y\), leading to \((y-1)^{2}\), to shift it 1 unit up.
Other exercises in this chapter
Problem 15
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