Problem 15
Question
Write a formula representing the function The average velocity, \(v,\) for a trip over a fixed distance, \(d,\) is inversely proportional to the time of travel, \(t\)
Step-by-Step Solution
Verified Answer
The formula is \( v = \frac{d}{t} \).
1Step 1: Define the relationship
The problem states that the average velocity \( v \) is inversely proportional to the time of travel \( t \). This means that as \( t \) increases, \( v \) decreases, and vice versa. Mathematically, this relationship is expressed as \( v \propto \frac{1}{t} \).
2Step 2: Introduce the proportionality constant
To convert the proportionality into an equation, we introduce a constant of proportionality, \( k \). This leads to the equation: \( v = \frac{k}{t} \).
3Step 3: Determine the constant using the fixed distance
Since the average velocity is for a trip over a fixed distance \( d \), we can relate this to the formula \( v = \frac{d}{t} \), a standard equation for velocity. Thus, \( k = d \).
4Step 4: Write the final formula
Substitute \( k = d \) into the equation \( v = \frac{k}{t} \) to get the final relationship for average velocity over a fixed distance: \( v = \frac{d}{t} \).
Key Concepts
Inverse ProportionalityDistance-Time RelationshipVelocity Equation
Inverse Proportionality
Imagine two quantities that always multiply to give the same number, such as a constant value. This is what inverse proportionality is all about. When average velocity \( v \) is inversely proportional to time \( t \), it implies a special relationship between them:
- If you increase the time \( t \), the average velocity \( v \) must decrease to keep the product \( v \cdot t \) constant.
- Conversely, if you decrease the time \( t \), then \( v \) should increase to maintain the same constant product \( v \cdot t \).
Distance-Time Relationship
The distance-time relationship is foundational in understanding motion and velocity. It's rooted in the basic formula for velocity: \( v = \frac{d}{t} \), where \( v \) stands for velocity, \( d \) stands for distance, and \( t \) stands for time. This equation reveals how distance traveled in motion is directly related to both velocity and time.
To comprehend this concept further, consider these points:
To comprehend this concept further, consider these points:
- For a fixed distance \( d \), if time \( t \) is reduced, velocity \( v \) must increase to cover the same distance.
- A longer time \( t \) to cover the same distance \( d \) results in a decreased velocity \( v \).
Velocity Equation
The velocity equation, \( v = \frac{d}{t} \), emerges from combining the insights about proportionality and distance-time relationships. It succinctly captures how velocity is influenced by both distance and time. Here's a breakdown:
- \( d \) is the distance: the length over which the object moves.
- \( t \) is the time: the duration over which the movement occurs.
- \( v \) is the velocity: how quickly the object travels over distance \( d \) during time \( t \).
Other exercises in this chapter
Problem 15
Most breeding birds in the northeast US migrate elsewhere during the winter. The number of bird species in an Ohio forest preserve oscillates between a high of
View solution Problem 15
For Problems \(1-16,\) solve for \(t\) using natural logarithms. $$7 \cdot 3^{t}=5 \cdot 2^{t}$$
View solution Problem 15
Use the variable \(u\) for the inside function to express each of the following as a composite function: (a) \(y=2^{3 x-1}\) (b) \(\quad P=\sqrt{5 t^{2}+10}\) (
View solution Problem 15
(a) Make a table of values for \(y=e^{x}\) using \(x=\) 0,1,2,3 (b) Plot the points found in part (a). Does the graph look like an exponential growth or decay f
View solution