Problem 15
Question
Write a balanced net ionic equation for (a) the electrolytic decomposition of hydrogen fluoride. (b) the oxidation of iodide ion to iodine by hydrogen peroxide in acidic solution. Hydrogen peroxide is reduced to water.
Step-by-Step Solution
Verified Answer
Question: Write balanced net ionic equations for the following reactions: (a) electrolytic decomposition of hydrogen fluoride (HF), and (b) oxidation of iodide ion (I-) to iodine (I2) by hydrogen peroxide (H2O2) in an acidic solution.
Answer:
a) 2HF → H2 + 2F2
b) 2I- + H2O2 + 2H+ → I2 + 2H2O
1Step 1: a) Electrolytic decomposition of hydrogen fluoride
Step 1: Write the overall reaction
First, we know that HF undergoes an electrolytic decomposition, which means that an electric current is used to break it down into its elements: hydrogen (H2) and fluoride (F2).
HF → H2 + F2
Step 2: Write the half-reactions
To write the net ionic equation, we need to identify the half-reactions involved.
The oxidation half-reaction is:
2HF → H2 + 2F- + 2e-
The reduction half-reaction is:
2F- + 2e- → F2
Step 3: Balance the half-reactions for mass and charge
In this case, both half-reactions are already balanced for both mass and charge. If they were not balanced, we would need to adjust the coefficients accordingly.
Step 4: Combine the half-reactions
Now, we can combine the half-reactions to form the balanced net ionic equation:
2HF → H2 + F2 + 2F- + 2e-
2F- + 2e- → F2
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Net ionic equation: 2HF → H2 + 2F2
2Step 2: b) Oxidation of iodide ion to iodine by hydrogen peroxide in acidic solution
Step 1: Write the overall reaction
We know that iodide ion (I-) is oxidized to iodine (I2) by hydrogen peroxide (H2O2) in an acidic solution.
2I- + H2O2 → I2 + 2H2O
Step 2: Write the half-reactions
To write the net ionic equation, we need to identify the half-reactions involved.
The oxidation half-reaction is:
2I- → I2 + 2e-
The reduction half-reaction is:
H2O2 + 2H+ + 2e- → 2H2O
Step 3: Balance the half-reactions for mass and charge
The oxidation half-reaction is already balanced, but the reduction half-reaction needs to be balanced for both mass and charge.
H2O2 + 2H+ + 2e- → 2H2O
Now both half-reactions are balanced.
Step 4: Combine the half-reactions
Now, we can combine the half-reactions to form the balanced net ionic equation:
2I- → I2 + 2e-
H2O2 + 2H+ + 2e- → 2H2O
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Net ionic equation: 2I- + H2O2 + 2H+ → I2 + 2H2O
Key Concepts
Electrolytic DecompositionOxidation-Reduction ReactionsAcidic Solution
Electrolytic Decomposition
Electrolytic decomposition is a process where an electrical current is utilized to break down a compound. This is a fascinating concept because it involves transforming substances through electricity, specifically breaking chemical bonds to form simpler substances. For example, in the decomposition of hydrogen fluoride (HF), electrical energy is harnessed to separate it into hydrogen gas (H₂) and fluorine gas (F₂). This reaction can be split into two half-reactions, which are crucial for balancing the net ionic equation.
In the oxidation half-reaction, HF loses electrons:
In the oxidation half-reaction, HF loses electrons:
- 2HF → H₂ + 2F⁻ + 2e⁻
- 2F⁻ + 2e⁻ → F₂
- 2HF → H₂ + 2F₂
Oxidation-Reduction Reactions
Oxidation-reduction reactions, or redox reactions, are a cornerstone of chemical processes. They involve the transfer of electrons between species, indicating changes in oxidation states. This interplay can either manifest through gaining or losing electrons, hence the names oxidation and reduction.
Understanding this concept can be simplified by examining the oxidation of iodide ions (I⁻) by hydrogen peroxide (H₂O₂) in an acidic solution. Here, the iodide ion loses electrons to form iodine (I₂):
Understanding this concept can be simplified by examining the oxidation of iodide ions (I⁻) by hydrogen peroxide (H₂O₂) in an acidic solution. Here, the iodide ion loses electrons to form iodine (I₂):
- The oxidation half-reaction: 2I⁻ → I₂ + 2e⁻
- The reduction half-reaction: H₂O₂ + 2H⁺ + 2e⁻ → 2H₂O
- 2I⁻ + H₂O₂ + 2H⁺ → I₂ + 2H₂O
Acidic Solution
An acidic solution is one where there is an excess of hydrogen ions (H⁺). This environmental condition can greatly influence the behavior of chemical reactions, including redox reactions.
In the context of oxidation of iodide ions by hydrogen peroxide, the acidity of the solution is essential for the progression of the reaction. The presence of extra H⁺ ions, which are prominent in acidic mediums, aids in the overall balancing of the reaction:
In the context of oxidation of iodide ions by hydrogen peroxide, the acidity of the solution is essential for the progression of the reaction. The presence of extra H⁺ ions, which are prominent in acidic mediums, aids in the overall balancing of the reaction:
- The reduction half-reaction already highlights the involvement of 2H⁺: H₂O₂ + 2H⁺ + 2e⁻ → 2H₂O
Other exercises in this chapter
Problem 13
Give the formula of (a) an anion in which \(S\) has an oxidation number of \(-2\). (b) two anions in which \(\mathrm{S}\) has an oxidation number of \(+4\). (c)
View solution Problem 14
Give the formula of a compound of nitrogen that is (a) a weak base. (b) a strong acid. (c) a weak acid. (d) capable of oxidizing copper.
View solution Problem 16
Write a balanced net ionic equation for (a) the oxidation of iodide to iodine by sulfate ion in acidic solution. Sulfur dioxide gas is also produced. (b) The pr
View solution Problem 17
Write a balanced net ionic equation for the disproportionation reaction (a) of iodine to give iodate and iodide ions in basic solution. (b) of chlorine gas to c
View solution